<II-v> .1. 1.10

aa×{3:a3 } = {illeg} ab×3:cde = 6:a3b3 × 6:ccddee = 6:a3b3ccddee . to find the proportion of two irrationall rootes. to free the Numerato{r} or denom from {illeg}surde q{illeg} ab+c = x = ab+c × bcbc = abacbbc .


2axca3c 3a+abbc 6aax3aa3 +2axcabbcca4bbcc 6aax3aa3+2axabbaabc error tantum 1′ in metallo 2″ in radio 110160.1100×11230×60×60160,30,3054000160,30,601080001c 160000121200(40c 0 0 300,12,10 3000,12 36000 0 0 160,60,60.=1300,720 9a5 3aa 0,0515130,0132 (5 baax(9)a5 cd)ab(dacb 22 38×9 01405614 8.12 12.132 = 616 = 38 . 9.1969)392(4359 2.14 14.132 . 96.7 7.4996 1.cdab.dacb cd.1ab.dacb c.d 1.
cd.1 cdind . 1×d c . d cc . dc 1 . dc cd.1 c.d 1.dc ab.dacb . cd.1 (cdind)c . (1×d) d (cc) 1 . dc ab (dc×ab) dacb

a+3xc4bbx481aa 2bxx9a 2abxx+6bx39ca aa2ay=abbb+by aa=abbb+by+2ay aaab+bb=by2ay aaab+bbb2a=y

z=yyx 20=a 140=b x.y.yyx. yy=yyxx x+y+yyxa=0 xx+yy+y4xxb=0


To find a heavy bodys descent in any given time, & the proportion of the pressure of the rays by gravity to the force by which a body hath any given motion; by this figure Figure If the cilinders bc, df bee of glasse &c: the proportion of their strength is knowne by the proportion of the gravity of the circles Figure a, e &c in respect of the axis in.

If a Staffe bee bended to find the crooked line which it resembles.

If the motion of a line is knowne to find the crooked line which that line toucheth continually.

If a stick ab revolves with even velocity about the center a haveing the weight c Figure fastened {in} it by {the} string bc , then shall the string bc bee a tangent to the circle bde.

But it may be inquired what line the weight (c) would describe were the stick with uneven velocity, or did the point b describe a Parabola or some other crooked line were the weight c in some other place as at the center { a } when the stick began to move.

If the ball b revolves about the center n the force by which it Figure endeavours from the center n would {beget} soe much motion in a body as there is in the time that the body b moves the length {of the} {semidiameter} bn . [as if b is moved with one degree of {motion} through e bn in {a} seacond of an {hower} than its force from the center {illeg} being continually like the force of gravity impressed upon the body during one second it will generate one degree of motion in that body.] Or the force from {n} in one revolution is to the force of the body motion as ∷ periphrad . Demonstration. If ef=fg=gh ad. =he=2fa=2fb=2fb=2gc=2ed. & the globe {b} from a to b {then} 2fa{ak}abfa force {or} pression of b upon fg {at} its reflecting ∶ force of b{'}s motion. therefore 4ab=ab+bc+cd+da fa ∷ force of the reflection in one round (viz: in b , c , d , & a) ∶ force of b 's motion. by the sa{me} pro{illeg} the Globe b were reflected by each side of a circumscribed polygon of 6, 8, 12, 100, 1000 sides {illeg} the force of all the reflections is to the force of the bodys as the sum of those sides {illeg} r{adius} of the circle about which they are circumscribed. And so if body were reflected by the sides of an equilaterall circumscribed polygon of an infinite number of sides {illeg} by {illeg} circle it selfe) the force of all the reflections are to the force of the bodys motion {as each} those sides ({illeg} the perimiter) to the radius.

If the body b moved in an Ellipsis then its force in each point (if its motion {in that point bee} g{illeg}) bee found by a tangent circle of equal crookednesse with that point of the Ellipsis.

If a body undulate in the circle bd all its undulations of any altitude are performed Figure in the {same} time with the same radius. Galileus.

As radius ab to radius ac ∷ so are the Squares of theire times in which they undulate.

If c circulate in the circle { cgef } , to whose diamiter { ce ,} ad=ab being perpendicular then will the body b undulate in the same time that c circulate.

And those body circulate in the same time whose {illeg} {illeg} from the {illeg} to the center d are equall

And addc force of gravity to the force of { c } to its center d . {illeg} {illeg} {illeg} {illeg} the motion of things falling were they not hindered by the {illeg} may very {illeg} {illeg} cdad force form d ∶ force from a.


[1] ag=x. gh=y. ah=c. bxx+ex+cc=0. +dxy+fy +gyy . dp=v. ad=xxyy+cc2c [2] dg2=2ccx2+2xxyy+2ccyycx4y44aa+vv=ss fig 2d. xxyyvy y . ds=yyxxyyv 4c4x42bx42ex32dx3iny 2fxx 2eccxbbx42ccdx 2bccxx2ebx32bccx22ccf 2cceexeexx y3xxxyyvx + +yxxyyx=df. y3y3+yxxvyxxyyvx+xxxyy. [3] xxvxxyyxxyyv=bd. xxvxxyyvxxyya {illeg}{illeg}f ab=x. Parab mak=ade=bad. ergo, ab=bd.

[4] vat=bao=oas. ab=x. as=y. bo=v. bs=a. xy vav . vy=axvx Hyperb.

[5] os=v. sa=x. oi=ae=y. saae sooh=vyx . oioh de : ergo ey=dvyx. & ex=dv. Hyp: abaebccn. ae×vx=cn. deae×vx.ae . dx=ev.

[6] ab=y. as=x. bc=v. bac=cas, Ergo yxvav. bs=a. & xv=ayvy. Ellipsis.

[7] ab=x. as=y. bac=tar=cas. Ergo, baasbc=vcs=av axvx=vy. Hyperb.


The invention of Figures for reflections. at right angles at the point reflecting ac the radius reflected to the focus b. ag the radius reflected from the focus b. aq a perpendicular to ed the tangent of the crooked line sought. ab=x. ac=y, or, . ag=y. bg=a, or, bc=a. bd=v, or bq=a. fig: 1st[9]. eac=bad=adb. Ergo, ab=bd, or x=v. & caq=qab=aqb. ergo ab=qg. x=v. fig: 2d[10]. eac=bad=adg. Ergo, abag bddg axvx=vy. &, ab agqbbg. Ergo ax+vx=yv. v=bq. fig 3d[11]. eac=bad Ergo caq=qab . Ergo, caab cqqb . & axvx=vy.

The invention of figures for refraction. b , & g the foci. ca the Radius refracted to b . qa the Radius refracted from b. bg the distance of the foci. qa the perpendicular to de the tangent of the crooked line sought qr, qh= perpendiculars to the Radii cg, fb.

bg=a. bq=v. ba=x. ag=y. fig: 1st[12]. abas bqqr=vyx . deqrqh, Ergo. dx=ev. fig: 2d[13]. abas bqqr=vyx . deqhqr, Ergo. ex=dv. fig 3d[14]. abas bqqr=vinasx . agas gqqh=a+vinasy . de qrqh: Ergo dax+dvx=evy . fig 4th[15]. abas bqqr=vinasx . agas gqqh=vainasy . de qrqh : dvxdax=evy . fig 5t[16]. abas bqqr=vinasx . agas gqqh=avinasy . de qhqr . eaxevx=dvy . fig 6t. abas bqqr=vinasx . agas gqqh=avinasy . de qrhq . d axd v x=evy.


ad=a. ae=x. ed=y. af=z. fd=az.
xxzz=yyzz+2azaa. fg=v 2 aeefaggi. & deefdggh. [17] xxyy+aa2a=af. yyxx+aa2a=fd. ef=m. ae=xmxxyy+aa+2av2a=aggi=mxxmyy+maa+2mav2ax. edmgdmyymxx+maa2mav2ay=gh. gighde: therefore dyydxx+daa2davy=exxeyy+eaa2eavx. d=2. e =1 . y3 + 2xyy xxy + 2aax = 0 aay 2x3 2avy 4axv y3+2xyyxxyaay+2aax2x3 2ay+4ax =v=xxyy2a+2axay2y+4x bf=2aax+2aay+2xxyyx4y4a4iny+2xy3+2xyyxyyaay+2aax2x3in2a. af=v ae {ef}aggi. deefdggh. degigh. xmvmvx. ymavmamvy. demvxmamvy: & adxdvx=evy. af=x. fe=y. ae=xx+yy. ed=xx2ax+aa+yy. adxx+yydvxx+yy=evxx2ax+aa+yy aaddxx+aaddyy+2addvxx+2addvyy+ddvvxx+ddvvyy=eevvxx2eevvax+eevvaa+eevvyy. ef=o. bc= 2aaxxyx4ya4y+2aay3+2xxy3y5+4a2x3+4aayyx+4yyx32y4x2a4x2y4xx5 2aoy34aoxyy+2aoxxy+2a3oy4a3ox+4aox3 +2ay3+4axyy2axxy2a3y+4a3x4ax3 [18] an=on ab=y. ag=x. pg=b. pm=c. gb=z. gq=v. ezxevx=dvy. gm=p. gs= [19] ab=x=bq=v . as=y. nb=z nm=yzx. edzdze=np. e2yyzz+aaxxe2=ddzzxx nb2=eeaaxxddxxeeyy. nm2=eeaayyddxxeeyy. mb2=eeaaxxeeaayyddxxeeyy. np2=aaddxxddxxeeyy=ξ2. as2=ddzzxxeeaaxxeezz=aaddxx+ddxxξξeeξξ. eeaaξξ+aaddzz=0. [20] [21]


[22] [23] Figure Make the line ac to revolve about the point a : on the end c let the nut c bee fastened so {as} to turne about its center. make ab=ac & fastend another nut at the point b in the same manner. make the line bc to slide through those two nuts soe that the triangle abc will always be an isosceles. To the line cb fasten the line rstv at right angles. make the line kg with 2 nuts e & d at each end through which the lines rs & tu must slide to keepe the line kg perpendicular to bc , in the midst of kg fasten the nutt m so as it may turne about its center & that the line ac may slide through it then make that side of the line kg which is next ab to be a file which must be very smooth at the point m but must grow rougher towards the ends d & e . Then by turneing the line ac to & from l & h about its center & holding the file kg close to the plate hmflab , it shall file it into the shape of a Parabola.

Figure To describe the Parabola by points. Make ca=r4; c the vertex; a the focus; ab=r. then with some radius as ag=ae, describe the circle ge : & take bd=2ga=2ae=2de & the point e shall bee in the parabola, also if from e to g , a streight line be drawne it shall touch the Parab: in e.

Or thus, take ch=ca=r4, hd=2cg or da=2hg:; & ga=ae=de. &c:

Or thus, take cm=gc, dm=ma; & ga=ae=de; &c.

Or thus take cm=gc & raise me a perpendicular to ca, which shall intersect the parab, & circle ge in the same point.

Figure Or thus. make ab=r4. bd=2bc= r. kb=bg. with the Radius bc describe bed . the circle.

[24] Or thus take r2=ac=cn=Rad. Circle aen: ab=r4. am=ap & produce mp indefinitely. Then take some point ad in the line an , & draw dg perpendic: to an that is soe that dm=dg, then take df=ae, & f shall be a point in the parabola afr.


Banderon's addition to Ferrarius's Lexion Geographicum, the best for Geog. Ortelius Geogr. Lexicon. MrJohn Craige DrArchibald Pitcarne } Scotch Mathematicians

Experiments about the resistance of things falling in water.

1. I filled to the top a wooden vessel 9 inches square within & 9 foot 412 inches high within. And making balls of bees wax of several bignesses with pieces of Lead stuck in them to give them weight: three balls each of which weighed in the air 7612 grains & in the water 5116 grains, fell each of them in the water from the top to the bottom of the vessel in 15″ of time the motion of descent being (to {sence}) uniform almost from the top to the bottom. so then a globe equall to 71716 grains of water moving uniformly 9 foot 412 inches in 15″ of time feels a resistance equal to 5116 grains of weight.

2. Two balls, each weighing in air 15614 grains in water 77 grains fell each of them the same height of 9 foot 412 {dig.} in 4″ of time. And these experiments seemed sufficiently accurate.

Corol. Ergo the resistance is as the square of the velocity.

3. Two balls weighing each of them in air 245 grains, in water {almost} 1gr12 fell each the same height in 4412″. But these experiments were not so accurate as for{mers.}

The same two balls augmented with lead so as each of them to weigh in air 25112 in water 7gr18

Three balls


[25] as=y. sm=x. . mp=a. qs=v mn=yzx+z. ab2=xx+yy+2zx+zz. zzyy+zzxx+2z3x+z4xx+2zx+zz=nb2. eezzyy+eezzxx+2eez3x+eez4 ddxx+2ddzx+ddzz =np2=aa+yyzzxx+2zx+zz. sb=z. mn=zyxyz. ab2=qb2=zz+y nb2= z.4+yyzz.2xz.32xz.yy+xxzz.+xxyy. zz= ddzzyy.2d2zxy.y+ddxx.y2+aaddzzeezz . e2=1. d2= z42xz3+xxzz+2xyyzxxyy=0 yy 2aa . Suppose. yy=fx2+2gx+h. then, v=fx+g. z+fx+g=ω. ω44fxω3+6ffxxω24f3x30000z+f4x4=0 4g+12fgx12ffxxg+4f3x3g 2x+6gg12fxgg+6ffxxgg +5fxx4g3+4fxg3 +4gx4ffx3+g4 +xx+6fgx2+f3x4 2ggx+2ffx3g 2aa+fxgg h+2gxx +2fhxffx4 +2gh4fgx3 +4faax3ggx2 +4gaaffhx2 +2hx2fghx ggh 2aaffxx 4aafgx 2aagg 2fhxx 2ghx fx4 2gx3 hxx . & ω=bq. ab=ξ. sb2=ξ2y2. mb=ξξyyx. ξξyyyx ξξyy =nm. ξξξyyξx ξξyy =nb. nb2= aa.dd+ yyξξdd.y4dd.+yyxxdd.2d2yyxξ2y 2 eeξξyyee = eeξ4.eeξξyy.+eeξξxx.2eeξξxξξyy eeξξeeyy . dd=2. ee=1. 2aaξ22aayy+3yyξ22y4+2yyxxξ4ξξxx 4yyxξ2y2+2ξξxxxyy } =0 .

Problems. 1 To find the axis, diameters, centers, asymptotes & vertices of lines

2 To compare their crookednesse with the crookednes of a given circle

3 To find the longest & shortest lines which can be drawn with in & perpendicular to the line & to find all such lines are perpendicular at both ends to the given crooked line

4 To find where their greatest or least crokedness.

5 To find the areas, the lengths, & centers of gravity of crooked lines when it may b{e}

[26] 6 If y (one undetermined quantity) moves perpendicularly to x (the other undetermin{ed} quantity. if s=a secant=db. v=dc. y=bc. x=ca. Then having the proportion of v to {x}{s} to find y, or having the proportion of v to y to find x: when it may bee.

7 To reduce all kinds of equations, when it may bee

8 To find tangents to any crooked lines. Whither Geometricall or Mechanicall

9 To compare the superficies of one line with the area of another & to find the centers of gravity twixt two lines or sollids. 15

10 Haveing the position which x must beare to y (as if x is always in the same line, but y cutteth x at given angles. or if x & y wheeling about 2 poles describe the lines by theire intersection &c) to find theire position in respect of the line soe the equation expressing theire relation may bee as simple as may bee (as to find in what line x is & what angles it maketh with y; or to find the distance of the 2 poles & in what line they must be, soe that the relation twix{t} x & y may bee had in as simple termes as may bee).

11 Of the description of lines.

12 Reasonings of gravity & levity upon severall suppositions (as that the rays of gravity are parallel or verge towards a center; that they are reflected, refracted, or neith{er} by the weighty body &c.

13 Of the use of lines

< insertion from lower down f 4r >

14. To find such lines whose areas length or centers of gravity may bee found.

15. To compare the areas, lengths, gravity of lines when it may bee. & to find such lines whose lengths, areas may be comp{illeg}

16. To doe the same to sollids in respect of theire areas, content, gravity &c which was done to lines in respect of their lengths, areas, & gravity.

17. Of lines which lye not in the same plane as those made by the intersection of a cone & {sphæreides}.

18. Two equations given to know whither they expresse the same line or not.

19. Of the proportion which the rootes of an equation beare to one another.

20 One line being to find other lines at {pleasure} of {illeg} {same length} {illeg}

21 How much doth any medium resist the motion of any given body.

22 To Determin maxima & minima in equation which hath more than {illeg} unknowne quantitys.

To Determin max & min by numbers.

< text from f 4r resumes >

[27] cd=x. gd=y. rx+rqxx=rx. ac=a de=12r+rqx. ag=aa+2ax+xx+rx+rxxq. af=a+x+12x+rq aa+2ax+xx+ar+2aqrx+rxxq+rrxxqq+14r r = fa2 , in rx+rqxx aa+2ax+xx+rx+rxxq =fo2. fofl2.1. fl2= aarx+aarqxx+2arxx+2arxxx+rx3+rqx4+arrx+3arrqxx+14r3x+r3xx2q+2arrx3qq+2r3x3qq+r3x4q3 2aa+4ax+2xx+2rx+2rxxq aar+arr+14r3=bbr. a+12r=b. bbrx+crxx+grx3+rqq+r3x4q 2aa+4bx+2q+2rxxq =fl2. aaq+2a+3arq+rr2q=c . 2aq+1+2aaqq+2rrqq=g . r=2 q=6. x=3. gd=r2x+13xx=3. ac=1 df=r2+rqx=2. ag=5. 53af=6185=of . . deoffl=18e5d. dk=9×29324ee25ddO 18×324ee25dd+81×324ee25dd9×Q:324ee25dd: 8118×324ee25dd+Q:324ee25dd: . dk=450dd225d2324eeO801900ddee944784e4 50625dddd145800ddee+104976e4 dk=50dd25dd36eeO9900ddee11664e4 625d41800ddee+1296e4 }=g. de=a3. g=p+ps . e=1 9aae254aee+81ee18agee+54gee+9ggee ddgg +aaee6aee+9ee 2age2+6ge2+ggee dd 9aa+54a81 +18ag54g9gg gg =e 2 =z2 +9aaee54aee+81ee18apee18aeeqs+54eep+54eeqs+9eepp+9eeqs2qsqs×eea=z2 +eep4+6eeppqs+eeqqrs+2aaeepqs2aaep3+18eepqs+aaeepp+aaeeqs+6eeqsqs 9aadd+54add81dd12aaeepqs+6eep3+18eeqs6aeepp6aeeqs +18apdd54pdd9ppdd6aaeepqs54d2qs+9eepp+9eeqs +18eeppqs18pddqs6aeepqs +4eep3qs+18eepqs +4eepqsqs9ddqs +18addqs ddpp+2ddpqs+ddqs

[28] ac=a=ce . cd=x. dg=y. bc=x. df=12r. rx=yy. aa+2ax+rx+xx rxaa+2ax+ar+rx+xx+14rrlf. rx+ar+14rrinrxaa+2ax+rx+xx=fo2. fl2=eerxdd+4eearrx+eer3x4ddaa+8ddax+4ddrx+4ddxx. fl2=pp. lk=r ac=a. ab=x. axxax . xx=aaax. xx=42x. x=1+5 2515135. 625=525+1. xx=ax+aa. 14418_324 18×25_=45009036 14410 324×18_=58322592324 02916011664}=145800 003242592}=2624458320032076 x=1a+5aa4 ei=a. hk=z. gd=y hi=ezd. he=eezzaadddd. ek=ddzzeezz+aadddd. ce=a. fl=b fk=c. lk=ccbb. zeezzaaddddcb. c=dbzeezzaadd. lk2=ddbbzzbbeezz+aabbddeezzaadd. df=v lk=bv+dbbzeezzaaddy =dbby+bveezzaaddyeezzaadd=yddbbzzbbeezz+aabbddyeezzaadd ddbbyy+vveezzvvaaddddyyzz+eeyyzzaayydd+2b dvyeez2aadd=0. ab=q. bc=x. dc=y. r=latrxrxrxxq=yy. ef=b. fg=c. cf=x12q. ce=x12q+b. bcx12q+by. cx12qc+bc b=y=rxrxxq ccxxqccx+2bccx+14qqccqccb+bbcc=0 +bbrqxxbbrx . q=3. fg=c=1 b=1. xx+13xx=3x2x+x94+31=0. 4xx3=2x14=0 xx=64x316. x=34O9316. x=34O38 rx+rxxq=9. r2+rxq=2 12r+rxxq=7 rx2 =7. ac=a . kd=b. ad=c. dc=d. cababc dabec=cf. kl=e. x=1. r=14. ad=a. dl=b. lk=c. ac=g. dgbea=ce. ddgceea=ef. of2=d4ggcce4ccaae4aa. e=2. d=2. ggcc16aacc. g={ 8 } =8a=2 c 3 =of2 . ab=a. bc=b. cd=c. be=x. ce=xb. de=xx2bx+bbcc=cxa . xx=2bxbb+ccinaaaacc x=aabaaccOa4bb+aabbcc+a4ccaac4a42aacc+c4 bm=f. be=g. me=fg. ab=a. cd=c. agcgca=de. gafgafagg=mr. mn=z. aaff2aafg+aagggg+ff2fg+gg(=re2)ineedd=rn2=aaff2aafg+aagggg+zz.


eh=8 {}{} ei=6 hi=10. ek=15. 0751546=289=17=hk. de=15. dg=16=y. cd=x. df=a. gk={14} 3416 gkgd 178 30a2408a17=fl . flfo 10 17 . 1204a5=244a5=fo . ad=b. ag=bb+{illeg} 256bb+256 576192a5+16aa25 576bb1925abb+16aabb25256+576192a5+16aa25 = af2 = aa+2ab+ {illeg} 5bb4+3abb20 +aabb4009aa252ab1925a+576=0. +500bb+60a+aa=200ab+144aa+15360a230400 {illeg} yy=rx+rqxx=256. rqx+r2=a. 256ax=12rx. 512xa2=r eh=52 . ei=6. hi=132. hk=222120. ek=9514920 ek=3514920. kd=g. 5g×2065149=50g35149=dg. dg2=2500gg46341. gk2=48841gg. fk=ca. 50cg50ag35149in221=fl=f k×dggk 50cg50ag3905149=fo. ae=p. d e=g3514920 ad=pg+3514920. ag2=pp2pg+48841gg46341+46341400+3p1051493g105149 ag2gd2af2fo2.

eh=a. ei=b. hi=aa+bb hk=deaa+bb. ek=ddaa+ddbbeeaae eh=c. ek=ddcc+ddbb000ee a33410aab+abb+6=0102a10b. qa2+qa+s×a+c. c=6s. r+6s=34b10. 10r34+6034s=b. a3+raa+sa+cs +c+cr r=6s34b10. 36ss204b10s+s=bb10210b. cc=20 c45 b=1 10a334aa+112 a +60. 04483360_3808_ (2. 2. 2. 2. 2. 7. / 2. 2. 3. 5 190495247623811917 03868.(2.2.967 01934( 00967( 20 10.0. 0 2.967.4.1934.3868. 10 0036=1020=_1056= pqrDiv nn+2pn . pn=c aa4a 4 10a334aa92a+60 34+2+4 2 . 4 12034_86 15034_126 036827 00_0120_3168 (2.2.1594.797. 372 3720_ 4094 120_ 3974 1987 014c 056 14 (296160_ 256 144180_ 324 11713 20a3136aa 22a + 120 49_96480_57649 6252 [29] 30a3306aa+168a180. 1008( 50400_ 0180_ 51228.25614.12807.4269.1423 1361531134217 102 40a3204340aa+640102a+240. 0 40a3544aa538a+240. eh=12.ei=9. hi=15.hk=20.ek=16. 17_ 119 170_ 0289_ 2083 2890 49131530_ 3 729 816480_6561×4= { 2 }620 1 {illeg}

[30] axxca=bb. axx+abbbxx+baaed. daxx+dabb=ebxx+ebaa. 25839(600239{illeg} xx=aabeabbdadeb=10aab17abb17a10b. xx=17abb10aab10b17a. 40b17abb+10aab. a=917. b=1. 109017{illeg} xx=4abb3aab3b4a. {3 } x4axx4abb+3aab ax2xx+2bb3bO 4x4+8bbxx+4b49bbxx 9bb . 4x4bbxx+4b4. x=4 . b=1 . {illeg}+{illeg}={illeg}2bc+cc. cc+xx2c=b. 4x4bbxx {illeg} b4=4b4bbxx+63 {illeg} {illeg} = {illeg}c44a2bb{illeg}3aab=4bb3ab=4bb4{illeg}cc. 4c{illeg} {illeg}aa=4aa{illeg} {illeg}9acc{illeg}36a{illeg} {illeg}


[32] 4x4bbxx+4b4=4b4+4bbcc+c4 hx2+in+ 4x4b2x2+4b4=bb+cx+dxx+ee. 4x4bbxx=4bbcx4bbdxx4bbee+ccxx+2cdx3+2ceex+ddx4+2deexx+e4: +4x4+ddx4+2cdx3+ccxx+2deexx+2ceex+e4 xx+4dxx+4cx+4ee =bb. 24503 2236+4520 223 12+15203 hhx4+2hix3+2hkx2+2ikx+kk +ijxx . k=ee. 2i=2c. i=c. h=cc+ee4ee. c4+2ccee63e416e4=hk c4+2ccee63e4=c4+2ccee+e4. c4+2ccee+e4eeinx4 : +c3+cee2eeinx3 : + 32ccxx + ee2xx + 32ccxx + 2ceex + e4 +ff 2f =xx .

[33] 43+32+12+2+92= 6 x3+y3 +9zz43azx2y+y3z3azxyy 9x46ayx2+10aay2+aax26a3x 25+5+6+12+4+14112 834f 2ff 254+58+ 6424+6+2 5 dabbebxxebaa+d axx=0 dpqqeqyyeqpp+dpyy=0 . ssv2 + 2vyyy=a4yy2a42y3+2y 2ab=2exx. daxxeaaexx= b . ebxx +ebaa abb + axx =d= eq y y +eqpp pqq + pyy . pqqbxx+pqqbaa+pyybxx+pyybaa abbqyyabbqppaxxqyyaxxqpp =0 pqqab+pyyab =bbppq+xxppq. axxqyy+abbqyy=pqqbxx+pyybxx. bbpq+xxpq bqq+byy =a= pqqbxx+p yybxx qyyxx+qyybb . aabpyyabbqyy+bpyyxx=0 +aabpqqabbqpp+bpqqxx=0 axxqyy axxqpp . aa+xx= abbqyy+abbqpp+axxqyy+axxqpp bpyy+bpqq aabpyy+aabpqq = abbqyy+axxqyy a=x=bqq=yy=pp

< insertion from the bottom >

b3+z3=abz . bb2bx+xx+yy ss2vv+2vxxx=r4xx 0012-2 2r42xxx+2xx2x=v

< text from f 5v resumes >

hgxxgix+ . hkx+ik. 2rxxx+rr=yy. v=rx. rx+rqxxyy=0 120 . r=2rxq 2rx+2yx+xx=yy r+y+x . xx =q2 yy=rq2+rq4xx+yy axxx=yy. yyrq4. 2rxxx =yy. v=rx. x=rSymbol (taurus Operator with dot inside circle) in text2rr x Symbol (taurus Operator with dot outside circle) in textrzSymbol (inverted taurus Operator with dot outside circle) in textzx for x write x+zzxr 00000+rr for y write 2rxxx4zx+2zxxr+2zzxrzzxxrr {illeg} 00000xx r x z 2rxxxr for y rx {illeg} z Symbol (inverted taurus Operator with dot outside circle) in text 2zx 2x Symbol (taurus Operator with dot inside circle) in text2 zx Symbol (inverted taurus Operator with dot inside circle) in text2 zx xr {illeg}Symbol (inverted taurus Operator with dot outside circle) in text{illeg} xx+ Symbol (taurus Operator with dot outside circle) in text4zxSymbol (inverted taurus Operator with dot inside circle) in text 2zxxr 2 z2 {illeg} z Symbol (inverted taurus Operator with dot outside circle) in text4zxr Symbol (taurus Operator with dot inside circle) in text2zSymbol (inverted taurus Operator with dot inside circle) in text4zxr=0 {illeg} zz {illeg}{illeg}xx


[34] ag=x. bg=y. ag=x. gd=d. dc=e. bo=s. de=w. gh=b. go=v. if=c. ewe+bew000e ew+bwe=if. yvy+byv+bvy=hf. de+hi+gh×dedc=go+gh×gobg.
ag=x. bg=y. r x=yy. go=de=12r. gd=o. dc=rx+ro. gh=z. o+rz zrx+ro =rzzrx 4orrxx+rrox + 2rzrx = 2rzrx+ro. 4ozrx3+roxx=4zzro. x3=zzr. z=x3r. rxr2x3rxrx2rx=x2 x+r2=hf. x3r+9xx4+3rx2+rr4=bf2.
[35] xy=rr. v=yyx=y3rr=r4x3. gh=z. dg=o. de=+r4x3+3oxxdc=rrx+ofizxrr+000x+o +rrzxr4+rrzo x3+3xxo =fi. r4x3rrxfhzxrrx . r4+zxrrox3x3=fi rrzx4+r4x3rrzox3r4x3zrrx4+ox6+3r4xx03zx3rro+3x5oo +2rrzxx43r4=0. z=3rr2x+x32rr=gh. bh=rr2x+x32rr +r4x3+x2=fh. r8x6+r4xx+xx4+r44xx+xx2+x64r4=bf2 6r8x63r42xx+3xx4+6x62r4. 6 x12+16x8r410r8x4 24r12. 6r12+

gogbfk+gohg . dedcfi+dedi . dc×fi+dc×dede=di=gb×fi+gb×dg+gb×gogo. rrz x+o + r6 x4+4ox3 inr4x3= rrzx+ rrox+r6x4inr4x3+3ox2 . zxx+ox+r4x5+4ox4=z+oxx+3ox+r4x5+3ox4 . zx3+3zoxx+r4 x5+4ox4 = zx4+ox4+3ozx3+xr4+3or4 x6+6ox5 zx5+ 3zox4 + r4xx 6zox4+ 6r4xo =zx5+ 2 ox5 + 3ozx4 + xxr4 + 4ozx4 + 3oxr4 + 4ozr4 9zx4+6xr4=x5+7zx4+7xr4 . 2zx4xr4x5=0. z=r42x3+x2. r4x3rrx r4+x4 2x3 hb . xxrrr4+x42x3r4+x42rrx=bh. r8+2r4x4+x8 4r4xx r8+2r4x4+x8 4x6 =3r8x4+3r4x8+x12+r12 4r4x6=bf. 6x12+6r4x86r8x46x12 =0 . x8r8=0 . x4r4=0 . xxrr=0 . x=r. therefore take ag=gb=r , & the greatest crookedness of the line cb will be found at b . bh=r=fh . bf=r2 . bf=p . al=q . gb=y . go=v . ag=x. bf=p. vyq+vxqy+yvyxv=p . gb×al+gb×gogb×gago= {illeg} yq+y4rrrr=py3rr . y4rr+3rr2yq=0. q=y32rr+3rr2y . as before. or q= yy 2x +3x2=yy+3xx2x gl=yy+xx2x . w=v+x= dyy+ey+2fxy+bx+dx2+2ayx d+dx+2ay +bx+dxw+2ayw+dyy+ey+2fxy+bx+dx2+2ayx=0 . fxx+ex+c=0 +dyx+by +dyx . w22wx+xx w2 2wc2wby2wayy2wdyx fx+e ex+dyx+c+by+ayy f . +fxx+ex+dyx+c+by a xy=aa . x=aay . y=aax . v=yyx . qaax+aayyxxa4xy=0 . qaayxx2a2y3x32a4xy . q= fxx+ex+c=0 +dyx+by +dyx . 2fxy+dyy+ey b+dx+2ay =v . qy+ 2fxyy+dy3+eyy2pfxypdyypey b+dx+2ay yx=0 [36] 2bqyf+4aqyyf+2dy3f+2eyyf2pdyyf2peyf2dyc2dbyy2day3 2pf y+by+2a yy+dey+ddyydfqy2ffyy =x x=edy2fO ee+2dey+ddyy 4cf4bfy4afy 4ff bqyf+2aqyyf+ dy3f+ eyyf pdyyfpeyfdcydbyyday3 2pffy+bfy+2af yy+edy+ddyy dfqy2ffyy =x. 2bqyff+4aqyyff+ 2 dy3ff+ 2 ffey2 pdffyy2peffy2dcfydbfyy2dafy3 . 4befy+2aefyy+ edfy+ c ddfyy edfqy+eddyy+d2y3ddfqyy


[37] vv.+xy.+ay.+ax.+yy.=ss= vv.2ov+xy.+xo+ax.+ay .+ao+yy.+2oy. . 2ov=ox+ao+2oy . vv+2ov+oo+rs+ra+as+ss. v= xy+ax+ay+yyrsarasss zo .
xy+ax+ay+2yy+vv2vy=ss=ξz+aξ+az+2zz+vv2vz xyξz+axaξ2y2z=b. xyξz2by+2bz=0 . xy2by=0 x=2b . xxyyξξzz a2xξa2 =b . 12y+12x 4x2axO22x4ax3 4z2+azO2zzzzaz 2z+2x =v 4x24zz 2x2z =b. 2x22x3bxbz 2010 b=4x 2x4+2z4ax3az32zz4x2z2axz2+aazx2azxx=ccxx2c2zx+cczz O2x4ax3O2z4az3 =cxcz. 2x+2z12aO2xxaxO12zzaxz4x 2xO2xxax+axOa2xxax O2 xxax 4xy+2ax2xx+ay2xy2x2y= xxO6x2xxax+3axOx2xxax O22xxax 8xxO6x2xxax+3axOa2xxax O22xxax . 64x348axx+9aax 4x2a 2xxax+ 4zzx2zz 2x xx+dy+yy=0 . 2b ϩzccb cc +dϩbc +2abϩc+ 2b ϩzccb cc . d2=+a . b=0 . c= any finite line. as x=ϩ. y=12d+z . ϩ2+14dddzzz y3=axx+aax . y+a=ϱ . ϱ33aϱ2+3aaϱaxx+aaxa3=0 0450.2250 48xx 54×16×27_324540_864 240480_720 ϩ3b3=0 . +6ϩabc+cϩccbb×a3abcϩcc=0 105300_2025 075150_225 11252250_3375 16_96160_256 ba=b . ac=c . ad=d . ddb=r , latrec:Parabdbe . ddc=s=lat:rec:Parab:dce . lq=a . axx=y3. y=x+z . axx+x3+3x2z+3xz2+z3=0 . caxxx=z. +2axy3xxy6xyy3y3 3yy+6yx+3xx =v=2axy 3yy+6yx+3xx z3+3xz2+3xxz+x3d xx=0 a=8 . x=1 . 7+3z+3zz+z3=0 y3+ ayy+2ab+abb +2b+bb zz+4z+7. z=2O47 +448+192z+24zz+z3=0. zz+20z+11 2 3x=a+2b.3xx=2ab+bbb3dbb=abb.bd=a 3x2b=a=3xxbb2b6bx+3bb+3xx=0. x=aa=b=x.ba=d. y+a×y+b×y+byyy+ayy+2abyabb+2byy+bby ax=yy. axyy+2ay+aa=0. ax=y+a. caϩrabzc+ddcc2dbcϩ +2dczr+cczz+bbϩz2aabϩ 2bϩzrbbzz+2azcd +2aazr . 2bccbb.b=c. 2dbc2aab. aac4aabbcc=4bbccdd+8 2dc+2ac=0.d=acc.d=a. af=a . ag=b . ab=ϱ . bc=z . abbh=aϱabbϱb=gb . ch=ϩbaϱ+ab . fg=c . ag=b . fg=c . fh=cϩb . af=ccbb . ϱbinccbbb=bh . bϩϱ+b×ccbbb=ch . bϩϱ+binccbbc=cd . abϩaaϱ+aab+ccϱbc=df . cc= aa+bb . ϩbaϱ+ab aa+bb =cd=x. aϩaa+bϩ aa+bb =df=y. bϩ+abxaa+bb a =ϱ= yaa+bbaaaϩ b bbϩ+aaϩ=ayaa+bba3 abb+xaa+bb . a ϩ=ayaaa+bb+bxaa+bb . Or ϩ= ayac+xccaac . ϱ= yccaaax c ϱ=cybaaybcxac c=5 . a=3 . ϩ=3y15+4x5 . ϱ=4y3x5 . ϩ4=ϱ3 . 5 27y3405yy+2025y3375=256y4768y3x+864yyxx432yx3+81x4 +108yyx1080yx+2700x 144yxx720xx +64x3 ϱϱϩ=a3 . c=5r . a=4r . ϩ=4y20r+3x5 . ϱ=3y4x5 =2rr . =rr .
9yy24xy+16xx25 . 36y396xyy+64xxy+48x3=225a3 +2772xxy 180ryy+480rxy360rxx 36y369xyy8xxy+48x3=0 180ryy+480rxy360rxx rrr .


2bqff +4aqyff 2qeff 2dcf +d3yy dbyf +bef+2aefy +dee+2ddey defqddfqy = 2pff+bf+2afy +de+ddydfq2ffy inee+2edy+ddyy4af4bfy4a {illeg} 4bbqqf4 +16abqqf4y +6bqffd3yy +8aqffd3y3 8bqf3dc 4bbqf3d 4d4cf 2d4bf +4bbqf3e +8aef3bq +2befd3 +4aefd3 +6bqffdde +4d5e 4bqqf3de4bqqf3dd2d5fq +16aaqqf4 +4ddcffb8aqf3db +4ddccff16dcf3aq+16aaq3f3+d6y4 4dcffbe8dcffae 4ddcfee8d3fce8aqqf3dd +4ddcffeq+4d3cffq+ddbbff +bbeeff+8aqbef34aedbff +2be3fd2bbeffd4d3ebf +2beeffdq+4abeeff +dde4+4bddeef+4aaeeff 2de3fq+8aeeddf +ddeeffqq 2ddeebf +4ade3f+6d4ee +4d3e310d4efq +d4ffqq 8adef3qq+12aeddfq +2ddeffqb +4adeeffq 6d3eefq +2d3effqq 8ppf4edy =4ppf4+4pbf3 +4bbf3+8paf3q+4aaffyyinee+4bf4cf +4pdeff+4pddff+4afdd +4df3qq+4abff+d4 4pdqf3+2ddbf 8pqf4+4afde +bbff4adffq +2debf8aqf3 2dbffq+2ed3 4bqf32d3fq +ddee4ddffq 2ddefq 4deffq +ddffqq +f4qq
bc=x. cd=y. ef=a. ea=b. ad=c. xx+yycc=ab2+b=eb . axb+xx+yy cc=ch . aa+xx+yycc+bb+2bxx+yy cc=bf2 caa+xx+yycc+bb+2bxx+yy cc+ax b+xx+yy cc =y . ccaa+ccxx+2ccyyc4+bbcc+2bccxx+yy cc=bbyy+2by2(&c)2axx+xxyy+y4 . yy+xx+bbcc+2bxx+yy cc ccaa2axyxx+yyaaxxax yycc
Figure ac=x. bc=y.
bf=z af=az . ad=aa4+az za4+zxxaa4+az+zz . 4z3+4azz+aaz=axx+4zxx .

To know whether the changing of the signes of an Equation change the nature of the crooked line signified by that Equation observe that

If the signes of every other terme (of that Equation ordered according to {either} of the undetermined quantitys) be changed the nature of the line is not changed. but if some signes bee changed but not in eve{ry} other terme (of it ordered according to one of the unknowne quantitys) the nature of the line is changed.

If the knowne quantitys are every where divers, & one of them be blotted out that produceth a line, when one terme is already wanting

Those lines may bee defined the same whose natures may be expressed by the same equation although angles made by x & y are not the same.

In the Hyperbola the area of it beares the same respect to its Asymptote which a logarithme {di}{illeg} number.

To make the equation x3ax2+abxabc=0 . be divisible by xc=0 . suppose c=x , then tis c3acc+0=0 c=a . therefore write c in steade of a & it is x3cx2+cbxbcc=0 . which is divisible by xc To make the same Equation divisible by xx2ax+ac=0 Suppose it to bee divided by it & the ration will bee xx2ax+ab)x3ax2+abxabc=0(x+a x3+2ax2abx 0+ax2+0abc axx+2aaxaab 0+2aaxaababc . The quote is 2aaxabcaab which have vanished therefore to make soe suppose each terme =0 & the{illeg} will be 2aax=0 & abc+aba=0 both include a=0 . Which since it cannot happen the equation cannot be divided the one by the othe{r}

The rootes of two divers equations may easily be added to substracted from multiplyed {&c} by one another while they are unknowne.

[38] That the penultimate terme of the Equation x3a2x+b3=0 . bee wanting I multiply & then suppose x a knowne quantity & y an unknowne {illeg} x3 {illeg} +b3y3 {illeg}{ d3ayy+y3=0 .} by this {having}{illeg} x {illeg} {illeg} {illeg}


[39] ddϱ2+2dϱϩeedd+eeϩϩddϩϩ=eexx. d3ϱ3+3ddϱϱϩeedd+3dϱϩ2ee3dϱϩ2dd+eeddϩ3eedd={e3x3} [40] 6ddϱϱϩϩee6d4ϱϱϩϩ+4ee4dddϱϩ3eedd+e4ϩ42eeddϩ4+d4ϩ4=e4x4 [41] +10ee10ddd3ϱ3ϩϩ +10ee10ddddϱϱϩ3eedd +5e410eedd+5d4dϱϩ4 +e42eedd+d4ϩ5eedd =e5x5 [42] ccee2cedϩ+ddϩϩ +2ceϱ2dϩϱeedd +eeϱϱddϱϱ =eeyy. +c3e3+3cceeϱeedd+3ce3ϱϱ+eeϱ3eedd=e3y3 3cceedϩ6cedϩϱ3eedϩϱϱdd +3ceddϩϩ+3ddϩϩϱ3ceddϱϱ d3ϩ3+3d3ϩϱϱ . +c4e4+4c3e3ϱeedd+6cce4ϱϱ+4ce3ϱ3eedd+e4ϱ4=e4y4 4c3e3dϩ12cceedϩ12ce3dϩ4cedd2eedd +6cceeddϩϩ+12ceddϩϩ+6eeddϩϩ4eedϩ+d4 4ced3ϩ34d3ϩ36cceedd+4d3ϩ +d4ϩ4+12cced3ϩ 6d4ϩϩ . c5e5+5c4e4ϱeedd+10c3e5ϱϱ+10cce4ϱ3eedd+5ce5ϱ4+e4ϱ5eedd=e5y5 5c4e4dϩ 20c3e3dϩ30cce4dϩ20ce3dϩ5dϩe42eedd +10c3e3ddϩ2 +30cceeddϩ2+30ce3ddϩϩ+10eeddϩϩ10ce3dd+d4 10cceed3ϩ3 20ced3ϩ310eed3 ϩ310cceedd+10d3ϩee +5ced4ϩ4 +5d4ϩ410c3e3dd+20ced3ϩ+5ced4 d5ϩ5 +30cceed3ϩ10d4ϩϩ5ϩd5 30ced4ϩϩ +10d5ϩ3 . [43] cceeϩeedd+2ce3ϩϱ+eeϩϱϱeedd=e3xyy 3ddϩ +ddϩ 34 ceddϩϱ +cceedϱ . [44] e4xxyy= 2ce3dϩ3 +2ced3ϩ3 2deeϱϩ3eedd +4 d3ϱϩ3 +2ccdeeϱϩ +4cde3ϱϱϩ6cd3e +2deeϱ3ϩeedd4d3. 6ddceϱϱϩe2d25ddeeϱ3ϩ+c3e3ϩeedd=e4xy3 4d4ϱϩ3+3ce3ϱϱϩeedd+4d4ϱ4ϩ+ceddϩ3 +3cce4ϱϩ3ceddϱϱϩeedd +e4ϱ3ϩ +3ddeeϱϩ3 . 8ddc3e3ϱϩ 18ddcceeϱϱϩe2d22ddce3ϱ3ϩ6ddeeϱ4ϩeedd+c4e4ϩeedd=e5xy4 16d4ceϱϩ3 10d4ϱϱϩ3 +16d4ceϱ3ϩ +5d4ϱ4ϩ+6ccddeeϩ3 +4c3e5ϱϩ +6cce4ϱϱϩ +4ce5ϱ3ϩ +e4ϱ4ϩ+d4ϱ5 +12ce3ddϱϩ3 +6ddeeϱϱϩ3 . c5e5ϩeedd +5c4e6ϱϩ+10c3e5ϱϱϩeedd+10cce6ϱ3ϩ+5ce5ϱ4ϩeedd+e6ϱ5ϩ =e6xy5 +10c3e3ϩ3dd10c4e4ddϱϩ+30ce3ddϱϱϩ350cce4ddϱ3ϩ30ce3ddϱ4ϩ8e4dd +5ced4ϩ5+30cce4ddϱϩ330c3e3ddϱϱϩ+10dde4ϱ3ϩ3+25ced4ϱ4ϩ+13eed4 40cceed4ϱϩ350ced4ϱϱϩ330eed4ϱ3ϩ36d6 +5eed4ϱϩ5+40cceed4ϱ3ϩ3 6d6ϱϩ5+20d6ϱ3ϩ3 . 3c2eeeedϩ3 6ce3dϩ3ϱeedd 3e4dϱϱϩ3 +6cde3ϱ3ϩeedd +e4dϱ4ϩ =e5xxy3 d3eeϱ5+12ced3ϱϩ3 +12eed3ϱϱϩ312cd3e +3cceed3ϩ2+2c3e3dϱϩ10d5ϱϱϩ3 +d5ϩ5 +6ccde4ϱϱϩ5eed3 +3cceed3ϩ+4d5 . 4c3e5dϩ312cce4dϩ3ϱeedd12cde5ϩ3ϱ24de4ϩ3ϱ3eedd+8ce5dϩϱ4+2de4ϱϩeedd =e6xxy4 4ce3d3ϩ5+24cceed3ϩ38d3eeϱ5ϩ +4c3e3d3ϩ34d3eeϩ54ced5ϩ3+20d5ϩ3+20ced5ϩ+6d5ϱ5ϩ +4ced5ϩ5+6 d5ϩ5+8c3de5ϩϱϱ+12ccde4ϩ28ce3d3ϩ +2c4e4dϩ+20d3eeϩ3 +48ce3d3ϩ3ϱϱ24cceed3ϩ 12c3d3e3ϩ . ce3ϩ3eedd +4d4ϱϩ3+3ceddϩϱϱeedd 4d4ϱ3ϩ =e4x3y ceedd5ddeeϱϩ3+3ddee +e4ϱϩ3 . +cce4ϩ3eedd +8ced4ϱϩ3 +3ccddeeϱ2ϩeedd 8ced4ϱ3ϩ 5d4ϱ4ϩeedd =e5x3yy cceeddϩ310ce3ddϱϩ3+10d4ϱϱϩ3+6ce3ddϱ3ϩ+3ddeeϱ4ϩ +ddeeϱ5+2ce5ϱϩ38ddeeϱϱϩ3 d4ϩ5+e4ϱϱϩ3 . [45]


[46] ϱϱϩϩϱ2g2= { b4 . } a=r. c=2r. y2r+xx2=ϩ . ϱ=x+y32 ϩ=ayac+xccaac . ϱ=yccaaaxc aaccy42aac3y3+2accxy3ccaa4aaccxxyy a4y42a4cy3+2a3xy3ccaa+4a4xxyy 2a3xy3ccaa+a4xxyy +4a3cxyyccaa+aac4yy +c4xxyy 2ac3xy2ccaaaaccxxyy +a4ccyy ϩϩ=aayy2aacy+aacc+ccxxaaxx +2ayxccaa2acxccaa 0 ϱϱ=ccy2aayy2axyccaa+aaxx 0 2aaxy+aacx axxccaa +ccxy+ayyccaa acyccaa aaccx4+4a3x3yccaa+6a4xxyy a4x42a3cx3ccaa6 aaccxxyy+6a3cxyy000+aaccy4 2accx3yccaa+4 aac3xxy4a3xy3000a4y4 6a4cxxy 2a3 ccxy000+2a4cy3 2aac3y3 +a4ccxx+2 accxy3000+aac4yy +c4xxyy2 ac3xyy000a4ccyy 3x44x3y32xxyy 2cx33+10cxxy+2cxyy3+3y4=0 +ccxx2ccxy6cy3 +4xy3+2ccyy g3y3 0 3x44x3y3+6cxxy+4xy33 2cx336xxyy2ccxy3 +4xxyy +4cxyy+2cxyy3 +ccxx +yy3xx3+2xy. +cxcy3 0 xxyy2axxy+aaxxaaxxa4=0 0 xxyy+4bxyy+4bbyy2axxy8abxy a48abby

[47] bc=x. cd=y. bf=c. bp=ϱ. pd=ϩ. fefgde . feegdf. hp= z. fg=exd . eg=fxd . pddhrs. dh=sϩr . rtpdph=tϩr. dedhdg=esϩdr. gh=fsϩdr fg=ϱ+tϩdr+fsϩdr=exd . drϱ+dtϩ+fsϩer=x . rfx+cdresϩdr=y . fdrϱ+dtfϩ+ffsϩ+cdereesx der =y= frϱ+tfϩdsϩ+cer er ec=c. bc=x. dc=y. pd=ϩ. pf=ϱ. fg=exd . eg=fxd . pg=sϩ r . gd=tϩ r . fg=ϱr+sϩr=exd . x=drϱ+dsϩre. eg+ecgd=y=frϱ+fsϩ+recteϩre.

[48] fe=bc=x. cd=y. fp=ϱ. pd=ϩ. fefgdedhdg. feegdfhdhg. pddhrs. pdphrht drϱdtϩ+fsϩer=x. frϱftϩdsϩ+cerer=y. d=r . f=eedd . s=rrtt . s=ddtt . ddϱdtϩ+ϩeeddeett+ddttd4ed=x. dϱeeddtϩeedddϩddtt+ceded=y. Lastly dp=dt+eeddeett+ddttd4 . n=eedd . dq=teedd+dddtt . & Therefore x=dϱ+pϩe. & y=nϱqϩ+cee.

[49] bf=c. fa=z. fk=v. bc=x. cd=y. ap=ϱ. dp=ϩ. vv+zzvvϩϩvvϩϩvv+zz=pg2. devϩvv+zzevϩdvv+zz=po. ac=xzao=exezdde. exezdevϩdvv+zz=ϱ . dϱvv+zz .

[50] bf=c. af=z. bc=x. fc=xc=an. fk=v. deanno=execd. oc=exec+dzd . ak=vv+zzzed=ϩzϩvv+zz=gd. vϩvv+zz=eg . go=evϩdvv+zz. exec+dzddzϩevϩdvv+zz=y



fd=x. db=y. dc=v. ab=z. vv+yyvvzzvvzzvv+yy=ed2. fe= x y fe=xOvzyy+vv. ae=yOyzyy+vv. in the 1st case.[52] fe=xOvzyy+vv. ae=yOyzyy+vv. in the 2d case.[53] fe=Ox+vzyy+vv. ae=y.

[54] Haveing the nature of a crooked line expressed in Algebraic termes to find its axes, to determin it & describe it Geometrically &c

[55] If fd=x. db=y. & y being perpendicular to x describes the crooked line the line with one of its extremes. Then reduce the Equation (expressing the nature of the line ) to one side soe that it be =0. Then find the perpendicular bc which is done by finding dc=v. for vv+yy=bc2 (In finding dc=v observs this rule. Multiply each terme of the Equation by so many units as x hath dimensions in that terme, divide it by x & multiply it by y for a Numerator. Againe multiply each terme of the Equation by soe many units as y hath dimensions in each terme and divide by y for a denominator in the valor of v. [56] Example, rx+rxxq+yy=0. 1rx+2rxxq+0yyiny x =ry+2rxyq. 0rx+0rxxq+2yy y =2y. therefore ry+2rxyq2y =v=+12rrxq. Also if x3bxx+yyxy3=0 +yxx . +3x32bxx+yyxiny +2yxx x 3y3+2yxx+yxx y 000= 00= 0003xxy2bxy+2xyy+y3000 003yy2yx+xx00 =v [57] And if x4yyxx+aayxy4=0 . then 4yx32y3x+aayy 4y3aax+2yxx =v . &c) Then make ab=z. fe=x+vzyy+vv. ae=yvzyy+vv. & substitute this valor of (fe) into the place of x & this valor of (ae) into the place of y in the Equation & there take {in} a 2d equation. then by multiplication or by some other meanes take away the irrational quantity yy+vv & lastly take awa{y} y or x by the helpe of these 2 Equations, soe that you have a 3rd equation in which there is either x onely, or y onely & supposeing it to have 2 equall roots multiply it according to Huddenius his Method for a 4th Equation & by the helpe of the 3rd & 4th equation take away the unknowne quantity viz: either x or y. & there will result a 5t Equation in which is neither x nor y. & by which the valor of z may be found. The greatest of whose valors signifies the longest, the least of them the shortest of all the perpendicular lines ab. & if it have other rootes they signifie other lines (ab) which are perpendicular to the crooked line at both ends, a & b; & some of these must signifie the axes of the line if it bee of an elliptical nature.


[58] ac=x. ch=y. bf= z . fh= ϩ cd=a. dbbefhehbc. cxb=be. cϩb=eh. ϩccbbb=fe=cxbzb. ϩccbb+bzc=x. ed=xccbbb= ϩccϩbb+bzccbbbc hc= ϩbb+bzccbb+abcbc= acϩb+zccbbc=y.
||00 = ||00 ||00 = ||00 ||00 for ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 { x ||00 xx ||00 x3 ||00 x4 ||00 y ||00 yy ||00 y3 ||00 y4 ||00 xy ||00 xyy ||00 xy3 ||00 xxyy ||00 xxy ||00 x3y ||00 } ||00 = ||00 ||00 = ||00 ||00 write ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 { +ϩccbbc ||00 2bϩzccbbcc ||00 ϩ3ccccbb c3 ϩ3bbccbb c3 + 3bbzzϩccbb c3 ||00 4ϩ3ccccbb×bz 4y3b3zccbb + 4ϩb3z3ccbb c4 ||00 ϩbc ||00 2ϩabc2ϩbzccbb cc ||00 ϩ3b33ϩbaacc3ϩbcczz +3ϩb3zz6ϩabczccbb ||00 4ϩ3b3ac4ϩ3b3zccbb4ϩa3bc312ϩaabcczccbb12ϩabb3zz+12ϩab3cz2 +ϩz3b3ϩz3bccccbb c4 ||00 acϩccbb+ϩzcc2ϩzbb cc ||00 4ϩabbcz3ϩbbzccbb+aaccϩ+zzccccbb+2ac3zϩ+b2ϩ3ccbb c3 ||00 3bbccϩ3z 4b4zϩ3 + 3abbcϩ3ccbb+z3c4ϩ+4z3b4ϩ5z3bbccϩ9abcc+3ac3zzϩccbb aabbcc+3aac4zϩ+a3c3ccbb c4 ||00 2ab3cϩ3 2abc3ϩ3 +4b32bcczϩ3ccbb +2bcc4b3z3ϩccbb+2aabbcczϩccbb+4abc3zzϩ6ab3czzϩ c4 ||00 b3ϩ3 bccϩ3 + 2bcczzϩ 3b3zzϩ +2abczccbb c3 ||00 4b4zϩ3 5bbcczϩ3 + c4zϩ3 +ac3abbcϩ3ccbb +3b cczzϩ 4b3zzϩ +3abczϩccbb c4 ||00

Haveing therefore an equation expressing the nature of a crooked line To find its axis. Supposeing c= some quantity most frequent in the equation Subrogate bz+ϩccbb c into the roome of x ; & acϩb+zccbb c into the roome of y: Order the Equation according to ϩ, make every terme =0 , in which ϩ is of one dimension Order every terme in this secondary Equation according to the dimensions of z. & supposeing every terme of each of them =0 , by the helpe of these Equations (in which is neither x , y , z or ϩ ) may be found the valors of a & b . Then perpendicular to ac from the point a draw ab=a. & from the point b draw bk=b, & parallel to ac. from the point k draw mk=ccbb , & perpendicular to bk . & through the points b , m draw bl the axis of the line hgn . & that the relation twixt bf=z. & fh=ϩ may bee had, write the valors of a , b , c now found in their stead in the secondary equation.

Example dd+dy+xyyy=0. Then makeing d=c I write bz+ϩccbb c , or bz+ϩddbb d for x & its square for xx &c. & adbϩ+zddbb d for y , & its square for yy. & soe I have this equation, 0=dd+adbϩ+zddbb +adbz2bbϩz bϩϩ +bzz +adϩ +2azd +2bϩz ddbb +ϩzdd aadd +2adbϩ bbϩϩ ddzz +bbzz dd or by ordering it according to ϩ , bbϩϩ+bϩϩddbb+ddbϩdaϩddbbd4 +2bbzϩ2bzϩddbb+abdz aadd ddz+ddzz 2abdbbzz +2adz0 bzz ddz ddbb =0 Then by makeing those quantitys in the last terme save one =0 . I have this Equation 2bbz ddz 2bzddbb + ddb 2abd daddbb =0 . Which I divide into 2 parts makeing those termes =0 in which z is not, & those =0 in which z is of one dimension. & then I have these 2 equation{s} 2bbdd2bddbb=0 . & db2abaddbb=0 . by the first 4b4 4bbdd + d4 =4bbdd 4b4 . Or 8b4 8bbdd + d4 =0. That is bb=dd2Od48=dd2Odd22=dd2Odd22. by the 2d Equation I find ddbb4adbb+4aabb=aaddaabb . or 5aabbaadd=0 4adbb +ddbb . & by writing the valor of dd which was found before I have 5aadd2O5aadd4ad32O4ad3+d32Od42aadd2 22 =0. Or 3aa24ad2+dd2=0 O5aaO4adOdd . Or aa= 4ad2O4addd2Odd 32O5 . & a=d8O2d18O5 O 8ddO4dd8+4dd5dd dd36O5dd2Odd18 18O518+25 a= d8O2d 18O5 O+ dd 18O518+25 or 2d22d 325 O+ dd 43152 =a . & dd2Odd 22 =bb. a= 2d2O2dOd 32O5


[59] ddϱ2+2dsϱϩ+ssϩϩ ee =xx. d3ϱ3 + 3ddϱϱsϩ + 3dϱϱsϩϩ + s3ϩ3 =e3x3 . {d }. a+y d4ϱ4 + 4d3ϱ3sϩ + 6ddϱϱssϩϩ + 4dϱs3ϩ3 + s4ϩ4 =e4x4. d5ϱ5 + 5d4ϱ4sϩ + 10d3ϱ3ssϩϩ + 10dds3ϱϱϩ3 + 5dϱs4ϩ4 + s5ϩ4 =e4x5 ttϱϱ2tϱvϩ+vvϩϩ=yy +2tϱce2cevϩ +ccee . t3ϱ3 3ttϱϱvϩ + 3tϱvvϩϩ v3ϩ3 =e3y3 +3ttϱϱce6tϱce+3ce +3tϱccee3ccee +c3e3 . t4ϱ4 4t3ϱ3vϩ + 6ttϱϱvvϩϩ 4tϱv3ϩ3 + v4ϩ4 =e4y4 +4t3ϱ3ce 12ttϱϱce + 12tϱce 4ce + 6ttϱϱccee 12tϱccee + 6ccee +4tϱc3e3 4c3e3 +c4e4 . t5ϱ5 5t4ϱ4vϩ + 10t3ϱ3vvϩϩ 10ttϱϱv3ϩ3 + 5tϱv4ϩ4 v5ϩ5 =e5y5 +5t4ϱ4ce 20t3ϱ3ce + 30ttϱϱce 20tϱce + 5ce + 10t3ϱ3ccee 30ttϱϱccee + 30tϱccee +10ttϱϱc3e3 20tϱc3e3 +10c3e3 +5tϱc4e4 5c4e4 + c5e5

[60] bc=x . dc=y . df=z . bh=c . hkkede . ke=exd. dfdedf . fzd=de . cd+exfzd=y. p=n . fp=ϩ2nn. ep= eϩ2nn+dn d =exd eeϩϩ= eenn+ddnn2dnex+eexx . fdfp fg. ϩgf=fp . fϱ+ϩg f =x . fppede. . pd=ϩffggf fm=eϱd. hm=ϱ. eϱ+cddϩffggf=y. f=d. &c dϱ+gϩd=x. eϱ+cdϩffggd=y.

[61] If any crooked line be revolved about its owne axis it generates a Sollid intersected by any plaine not perpendicular to the axis produceth another line { not more compoundyn of the same kind with the former. But if it bee revolved by any other line it generates a Sollid which intersected by any plaine not perpendicular to the axis produceth another whose composition is {n}ot { lesseynequall moreyndouble } to the formere

Figure In the triangle adb if ab=a, & db=b are definite, but ad=v, & bc=x indefined. Then the Equation is bbvv+aa2ax=0. But in this case the maximum or minimum of either v or x cannot bee found according to Cartes or Hudde{nius} method, by reason that {vx} hath not 2 divers valors when {xv} is determined, which become equall when {xv} is the least or greatest that may be. But cd might have bee used inste{ad} of cb &c. There be other instances of this Nature against Huddenius his assertion.

Figure These points a,b,c, being given a circle may be described (which shall pass through them all) by an instrument whose angle edf=abc. And soe the sides ed & df being moved close by the points a & c, the point (d) shall describe the arch abc

To worke mechanically & exactly by a {scale} it may bee better divided according to the fassion represented by the figure A, then by that at B.

To make a {plated} superficies exactly: Take three plates A, B, D. Figure & {grind} them together A & B, A & D, B & D; pressing the uppermost plate onely in the middle at c that it may not weare {move} away in the edges than in the midst & move it to & fro with but small vibrations. Soe shall the 3 fiduciall sides of the 3 plates bee {ground} exactly plane.


[62] Probleme. Of Usury. ab=a= the principle. bc=x= the time of the money lent ce=dxe= the use due for the principle for the time bc. de= the use upon use. cd=y= the use for the principle & use during the time bc. axdxea+yinfcy. df a tangent to the line bd. dg a perpendicular. cg=v. Then as the summe (ab) or principle drawne into the time bc, is to (ce) the use for it in that time [63] So is the summe ab+dc drawne into the time fc, to the use (dc) for it in the time fc. therefore axdxe a+yin{hfcy . axy=ahdx+yhdxe. eayad+yd=hyyv. eav=ady+dyy. v=ady+dyyea. d=e. ay+yya=v

Of Reflections.

[64] Of Reflection.

Figure Suppose the Bodys a, b doe not reflect one another but conjoyne at theire meeting & soe move or rest together. a= the body a; b= the body fec; c= body ced; d= body fedc. m= motion of a, n= motion of b, p= motion of c, q= motion of d=n+p, before reflection. e= motion of a, f= motion of b, g= motion of c, h= motion of d after reflection. r= swiftnesse of a, s= motion of b, c, or d, before reflection t= swiftnesse of a, v= swiftnes b, c, or d occursion. ⊙ the point of theire occursion.

Axiome 1st

Two bodys bc being alike swift the motion of bmotion cbc. for equall parts have equall motion. Therefore bcall the parts of ball such parts of cmotion bthe motion of c.

Prop: 1st. If before the occursion of a & d a rest then shall e+h=q. & since t=v, tis {alsoe} eqaa+d. Or e=aqa+d also h=qaqa+d=dqa+d.

Prop: 2d. If a meete d, & have lesse motion than it, then, qm=e+h. for suppose, m=n. then should a & b rest after occursion did not p=qm force them towards k.

Prop 3 suppose i the center of gravity in d, y in a. z & f the in which the bodys a & d touch in theire meeting. ⊙ the point of theire meeting. a the magnitude of the body a, d the magnitude of d. m= motion of a before meeting, n= motion d before meeting. the time in which a or d Figure moves to = time in which they both move to y. p= motion of a, q= motion of d after occursion m+n=p+q. adpq. or a+ddm+n=p+qq= dm+dna+d. am+ana+d=p. mpz⊙zy. am×z⊙+an×z⊙ am+dm=⊙y.

Figure a= magnitude of the body a, d= magnitude of the body d. {illeg} o= {illeg} the point of concourse: zf= the points of contact, at o. zo=b. fo=c. op=e. t= time in which the bodys move from z & f to o. v= time in which they move from o to p. m= motion of a before occursion n= motion of d after occursion {illeg}=dn+ana or cdm+bam=bdn+ban. & cdm+bambd+ba=n{illeg}mn. tmvnbetbd+tbavcd+vba. {illeg} v=det+aetcd+ab. Figure. {illeg}{&} d meete {illeg} {illeg} that c must be negative that is abv0nt{illeg}e be negative the point {illeg} must be t{illeg}on the same side {illeg}



[66] 1st When a body Quantity {is translatedpasseth} from one parte of Extension to another it is saide to mo{ve.}

2 One body Quantity is soe much swifter than another, as the distance through which it passeth is greater than the distance through which the other passeth in the same time.

3 One Quantity hath so much more motion than another, as the distance through which it moveth drawne into its quantity, is to the distance trough which the other moveth in the same time drawne into its quantity. As if the line ab move the length of bc Figure & ef the length of eh in the same time, the motion of ab is to the motion of cd, as ab×bc=abcd, to ef×eh=iehk. Figure Alsoe if the cube lmqyz=8 move the length of op=5; & the piramis tvwx=7 move the length of rs=3 in the same time; then, as, op×lmqyzrs×tvwx4021 the motion of lmqyz to the motion tvwx. Or the motion of one quantity to another is as their powers to persever in that state

Those Quantitys are said to have the same determination of their motion which move the same way, & those have divers which move divers ways.

[67] 5 A quantity is reflected when meeting with another quantity it looseth the determination of its motion by rebounding from it. As if the bodys a, b meete one another in the point c they are parted Figure either by some springing motion in them selves or in the matter {crouded} betwixt them. & as the spring is more dull or vigorous quick soe the bodys will bee reflected with th more or lesse force; as if it endeavour to get liberty to inlarge it selfe with as greate strength & vigor as the bodys ab , pressed it together, the motion of the body a from b will bee as greate after as before the reflection. but if the spring have but halfe that vigor, then the distance twixt a & b,at the minute after the reflection shall bee halfe as much as it was at the minute beef{ore} the reflection.

Figure 7 Refraction is when the body c passing obliquely through the surface ed at the point b meets with more opposition on one side of the surface than on the other & soe looseth its determination; as if it turne towards a.

[68] 9 Force is the pressure or erouding of one body upon another,

10 The center of { Motion } in the same body is such a point within a quantity which rests when a body is moved with any circular but noe progressive motion; also the line in n drawne through it is called an axis of motion.

The center of motion in 2 divers bodys is a point soe placed twixt those bodys that (if it bee conceived to rest ) if the bodys bee moved about it with circular motion they shall both have an equall quantity {o}f motion, the line about which they move is the axis of motion.

12 A Body is said to move toward another body either when all its points move towar{d}s it or else when some of its points have more motion towards it than others have from it. Otherwise not

< insertion from the left margin >

13 Bodys are more or lesse distant as the distances of their centres of motion are more or lesse. or as their distances might bee acquired with more or less motion

< text from f 10v resumes >

Axiomes. Propositions.

1 If a quantity once move it will never rest unlesse hindered by some externall caus{e.}

2 A quantity will always move on in the same streight line (not changing the determination {nor} celerity of its motion) unlesse some externall cause divert it.

3 There is exactly required so much & noe more force to reduce a body to rest as there was {to} put it {illeg}n motion: et e contra.

4 S{illeg} much {illeg}{illeg}s is required to destroy any quantity of motion in a body soe {illeg} to generate it; & soe much as is required to generate it soe mu{illeg}ived to destroy it.

[69]6 {illeg}ove 2 unequall bodys (a & b) the swiftnesse of one body a is to the s{illeg} is to a . {(1)} & therefore the motion of both bodys shall bee equall.

5 If {illeg}{b}ee moved by unequall forces, as the force moveing b is to the force {illeg} motion of b. to the m{illeg} of c, so is the swiftnes of b, to that of c.

[70]7 If two body {illeg}{illeg} {illeg}way to{illeg}s {illeg}{illeg}r{illeg}cking {illeg} {illeg}e of theire motion shall be lost. f{illeg} pres{illeg}{illeg}{illeg}{illeg} the motion of b shall {illeg}{illeg}


[71] 8 If two quantitys (a & b) move towards one another & meete in o, Then the difference of theire motion shall not bee lost nor loose its determination. For at their occursion they presse equally uppon one another, & (p)[72] therefore one must loose noe more motion than the other doth; soe that the difference of their motions cannot be destroyed.

[73] 9 If two equall & equally swift bodys (d & c) meete one another they shall bee reflected, soe as to move as swiftly frome one another after their reflection as they did to one another before it. For first suppose the sphæricall bodys ef to have a springing or elastick force soe that meeting one another they will relent & be pressed into a sphæroidicall figure, {&} in that moment in which there is a period put to theire motion towards one another theire figure will be most sphæroidicall & theire pression one upon the other is at the greatest, & if th{e} endeavour to restore theire sphæroidicall figure bee as much vigorous & forcible as theire pressure upon one another was to destroy it they will gaine as much motion from one another their parting as they had towards one another theire reflection. Secondly suppose they be sphæricall & absolutely sollid then at the period of theire motion towards one another (that is at the moment of theire meeting) theire pression is at the greatest or rather tis done with the whole force by which theire motion is stopt, for theire whole motion was stoped by the force of theire pressure upon one another in ysone moment & there cannot beesucceede divers degrees of pressure twixt two bodys in one moment) Now so long as neither of these 2 bodys yeild to one another they will retaine the same forcible pressure towards one another: that is soe much force as deprived the bodys of their motion ( towards one another soe much doth now urge them from one another, & therefore (r)[74] they shall move from one another as much as they did towards one another before theire reflection.

10. There is the same reason when unequall & unequally moved bodys reflect, that they should seperate from one another with as much m{ot}ion as they came together.

[75] [76]

Figure 11 If a line ce be bisected in a about which the line ce doth circulate & that point bee fixed. then the whole line hath noe progressive motion. For makeing ab=ad, bf, ag, & dh bee parallel, & perpendic to fh, then is vb=dp. & vf+ph=bf+dh=2ag. Wherefore the point c moveing towards n the point d shall move soe much towards the line fh as the point b doth from it, & all the points in ac or the line ac move as much to the line fh as all the points in ae or the line ae moves from it soe that the whole line ce stays in equilibrio neither moveing to nor from fh, by the 12th Defin.

12 Hence when the center of a line a is not in the midst of a line me the whole line moves the same way which the longest parte doth. for supposeing ca=ae then the line ce in equilibrio (per axiom:11) but if mc moves towards fh & be added to ce then me moves towards ce (by def {12}

13. When ce moves circularly but maketh noe progression its middle point shall rest & is therefore the center of its motion, for if the middle point move let it bee to r from a soe that the line ec bee moved into the place {wt} then let the {wt} move about the fixed center r into the place xs, then {xs} & {wt} are equally distant from fh (by definition 13 & axiom 11) & alsoe ln & ce are equally distant from the {illeg}{am} f{illeg} but xs & ln are not equally distant from f{illeg}{illeg}ore neither are wt & ce equally distant from fh. & therefore the line {illeg} pro{gre}ssive motion when it {pressed} into {wt}

14 By the same reason the middle point {illeg}ogram, parallelipipedon, prisme cilinder, circle, sphære, elipsis, sphæroides {illeg} of theire motion



14 A Body being moved parallell to its selfe all its points describe parallel lines, & each them have the same determination & velocity with the body. for (by axiome 2d) they must all bee streight ones which if they intersect the body will not be moved parallel to its selfe.      &c.

[78] 17 If a body move streight forward & circularly its center of motion shall have the same determinacon & velocity that the body hath. For {suppose} ac to be moved into the place gh & its center of motion b into the place d, then let it turne about the center d into the place ef parallel to to ac soe that the point which was in a bee now in e. Now since {gf} by moveing into the place fe makes noe progressiv motion (definition 10) it follows that the same quantity (Or since gh=ef=ac) the same velocity & (axiom 10) determination of motion in the same time would translate ac parallell to it selfe into the place ef that would translate it into the place gh , had it both progressive & circular motion. But the point d hath the same velocity & determination which the line ef hath when moved parallel to its selfe (x)[79] therefore the point d hath the same determinacon & velocity which the line gh hath when moved with both circular & progressive motion vide axiom 37.

18 If a body move progressively in some crooked line & alsoe circularly its center of motion shall have the same determination & velocity which the body {hath} for (axiom 17) this is trew when its motion is in a streight line but a crooked line may bee conceived to consist of an infinite number of streight lines. Or else in any point of the crooked line the motion may bee conceived to be on in the tangent.

[80] 19 If 2 bodys make the same number of circulations with the same dista{nce} from the center c : then as the Radij of the circles which their centers of motion describe are to one another soe are the perimeters one to another soe are theire velocitys one to another (axiom 10, definition 2), & their motions are to one another as theire bulkes drawne into the Radij of those circles (which theire centers of motion describe) are to one another (definition 3). As: ec=eo velocity of eb velocity of ac. & eb×ecao×co motion eb motion of ao.

[81] 20 If a sphære ⊙c move with in the concave sphæricall or cilindricall surface of the body edf circularly about the center m it shall press upon the body def for when it is in c (supposeing the circle bhc to be described by its center of motion & the line cg a tangent to that circle at ⊙) it moves towards g or the determination of its motion is towards c      therefore if at that moment the body edf should cease to check it it would continually move in the line cg (axiom 1. 2.) obliqly from the center m , but if the body def oppose it selfe to this indeavour keeping it equidistant from m , that is done by a continued checking or reflection of it from the tangent line in every point of the circle chb , but the body edf cannot check & curbe the determination of the body c⊙ unless they continually presse upon one another. The same may be understood if the body adb bee restrained into circular motion by the thred om

21. Hence it appeares that all bodys moved circularly have an endeavour from the center about which they move, otherwise the body ⊙c would not continually presse upon edf .

22 The whole force by which a body c⊙ indevours from the center m in halfe a revolution {i}s more than double to the force which is able to generate or destroy its motion for supposeing it have moved from c by h to b then the resistance of the body ef (which is equall to its pressure upon def ) is able to destroy its force of moveing {illeg}{illeg} & to generate in it as much force of moveing from b to h the qu{illeg}g way.

[82] 2{5}{3} Having {illeg}of motion of the 2 bodys ob & dc to find the common center of both {in}{illeg}draw a line ⊙e from the centers of theire motions ⊙ & e & divi{illeg}oe that the body ob is to the body de as the line ae to the line oa : that is soe{illeg} ae×de . For then if they move about the center {illeg}{illeg}{illeg} they have equall motion (axiom 19th) & consequen{tly} {illeg} <12r> have an equall endeavour from the center a (axiom 23) soe that if they bee joyned to center a by the lines ae & ao the one hindereth the other from forcing the center a any way soe that it shall stand in equilibrio betwixt them & (by definition 10) is therefore their center of motion


24 If two bodys ( cb & de move about a center a then ∼ ∼ ∼ ∼ ∼ ∼ The whole force by which the body cb tends from the center a in one revolution being equall to {6}{61} times the force by which that body is moved (axiom 22) is to the motion of that body as the whole force by which the body de tends from the center a in one revolution (which is equall to 6{+} times the force by which the de is moved, or which is able to stop its motion (axiom 22) ) is to the motion of the body de . Vide Axioma 23ũ.

[84] 26 If the body a move through the space ab =b in the time d =be, & the body c through the space cd =e in the time f . then the velocity of a is to the velocity of c as ab×dc to cd× be . For supposeing that gp=eb. then is cp=eb×cdfd And (by definition 2) the velocity of a is to the velocity of cabcpabeb×cdfdab×fdeb×cd

[85] Alsoe the motion of a is to the motion of c (by definition 3d) a×abc×cp a×abc×cpa×abc×eb×cdfda×ab×fdc×eb×cda×its velocityc×its velocity.

Note that when the motion is uniforme that is when a body moves over the same space in the same time (which will ever bee when the motion of that body is neither helped nor hindred) then in a right angled triangle a b may designe the space through a body moveth in the time eb. Otherwise when tis not uniforme the proportion of the time in which a body moves to the distance through which it moves may be designed by lines drawne to a crooked line, as the time by gf & ih , the distance by gh or fi , the velocity by the proportion of nh to hi , ni being tangent to the crooked line at i . &c.

[86] 23
If the body bace acquire the motion q by the force d & the body f the motion p by the force g . then dqgp. for suppose the body rscb=f , to acquire the motion w by the force d , then (axiom 5)[87] dgwp . but q=w (by axiom 4) therefore dgqp.

Axiom {1}00 Every thing doth naturally persevere in that state in which it is unlesse it bee interrupted by some externall cause, hence axiome 1st, & 2d, & {γ}, A body once moved will always keepe the same celerity, quantity & determination of its motion.


101 . Supposeing the bodys aobc & cbqp to be equall & equivelox: Then that cause hindrence, impediment resist{ance} or opposition which can onely deprive cbqp of its whole velocity & motion by hindering its p{er}severance can also onely deprive aocb of its whole {whole velocity &} motion {illeg} that caus hath the same {illeg}{illeg} over both the bodys. Now if {illeg} add the opposition a which can {being} {illeg}ive of its {illeg} reduce cbpq to {illeg}{illeg}ion b which can reduce aob {illeg} {illeg} the whole opposition ( a+b=2a=2b ) {illeg} {illeg} both {illeg} bodys aobc+bcpq=aopq ) {illeg} {illeg} motion when they are joyned into one aopq for acbpqbaobca+bcbpq+aobc2aaopq Also neither {illeg} a or b {illeg} aopq of {illeg} motion for {illeg} <12v> parte ( a or b ) would be equall to the whole (a+b=2a=2b ). By the same reason aopq & cbqp loosing equall velocity the impediment of aopq must be double to the opposition of cbpq .

[89] 102 Since beacuse aopq is double to cbpq & both of them equivelo{x} therfore the opposition which can deprive aopq of its motion must be double to that which can deprive cbpq of its motion; by the same reason it will follow that in equivelox bodys as one body a is to another b soe must the resistance which can deprive that body a of its {velocitymotion bee to the resistance which can deprive b of its whole {velocitymotion so is the resistance which can deprive a of some parte of its velocity, to the resistance which can deprive b of the same quantity of velocity, soe that a & b bee still equivelox.

103 By the same reason alsoe If two bodys rest or bee equivelox: then as the body a is to the body b soe must the power or efficacy vigor strength or virtue of the cause which begets new velocity in a bee to the power virtue or efficacy of the cause which begets the = same quantity of velocity in b , soe that a & b bee still equivelox.

104 Hence it appeares how & why amongst bodys moved some require a more potent or efficacious cause others {a lesse} to hinder or helpe their velocity. And the power of this cause is usually called force. And as this cause useth or applyeth its power or force to hinder or change the perseverance of bodys in theire state, it is said to Indeavour to change their perseverance.

[90] 105 If the equall & equivelox bodys a & b meete (unlesse they could passe that one through the other by penetrating its dimentions) they must necessarily hinder the one the others progression, & since these bodys have noe advantage the one over the other the hindrance on both parts will be equall, likewise if the bodys d+a & b+c bee equall & equivelox they must equally hinder one anothers progression But the body b (being lesse than the body b+c & equivelox with d+a ) cannot hinder the progression of the body d+a soe much as the body b+c can; for {then} the power of b being part of the power of the body b+c would bee equall to the whole power of b+c therefore that b+c & d+a being equivelox doe equally hinder the one the others progression tis required that they be equall.

[91] 106 Now if the bodys a & b meete one another the cause which hindereth the progression of a is the power which b hath to persever in its velocity or state & is usually called the force of the body b & is soe that a body is {so} to be moved with more or lesse force which meeting with another body can cause a greater or lesse mutation in its state, or which requireth more or less force to destroy its motion. & as {one} body b useth or applyeth this force to stop the progression of a it is said to Indeavour to hinder the progression of a which indeavour in body is performed by pressure & by the same reason the body b may bee said to endeavor to helpe the motion of a if it should apply its force to move it forward: soe that it is evident what the Force & indeavor in bodys are.

[92] 107 If the bodys b & c be equivelox then as bc the force with which b is moved (or the power of b to persever in its velocity or to {keepe}{helpe} {illeg} hinder another body from persevering in its velocity to the force of c . For let there be 2 other bodys a & d equivelox to them soe that a meeting b , & d meeting c they would eqaully hinder one others progression then is a=b , & c=d (axiom 105) & a=bd=c then force which can stop a (= to the force of b ) to the force which can stop d (= to the force of c ). (vide axiom 102.

[93] 108 Tis knowne by the light of nature that equall forces shall effect an equall change in equall bodys. Therefore if the forces g, h, k, m, be equall, & the bodys a, b, equall & rest, then let a bee moved by the force g ; & b by h , a & b shall be equivelox: Also (since tis noe greater change for a to acquire another part of motion now it hath one than for it to acquire that one when it had none) if a bee againe moved forward by the force k , its velocity shall be double to the velocity of b , & if it bee againe moved forward by the force m its velocity shall be triple to that of b . &c. Whence as the force moving a is to the force moving b soe is the velocity acquired in a to the velocity acquired in b {by that force}

109 By the same reason if a=b & the velocity of a be triple to the velocity of b , that force can deprive a of its velocity. which is triple to the force which can deprive b of its velocity. Or in generall {2} so is the lost velocity of a to the lost velocity of b As the force which deprives a of some or all of its velocity, to the force which deprives b of some or all of its velocity


[94] 112 A body is saide to have more or lesse motion as it is moved with more or lesse force, that is as there is more or lesse force required to generate or destroy its whole motion.

[95] 113 If a body a move through the space ab =r in the time c . & the body f through gf =v in the time h then, time c time h line ab =rh×abc=ak . & the body a would move through the space ak in the same time h in which the body f moves through the space fg . Therefore the velocity of a is to the velocity of f as the line ak=h×abc line fg h×abc×fg (definition 2) Then I add the body r to f soe that r+f=a . since f & r are equivelox, (axiom 107) as ff+r=am= force or motion of f , to amf= force of f+r. againe since a=f+r , (axiom 111) as the velocity of a ; to the velocity of f+rh×abc×fg n= the force or motion of a , to n×c×fgh×ab=a×mf= to the force of f+r . Soe that, n×f×c×fg=m×a×h×ab . Soe that haveing any 7 of these the 8th may bee found. but suppose the bodys moved in equall times that is if c=h , then the rest of the termes may bee found by, m×a×ab=n×f×fg . &c. that is as f×fg is to a×ab soe is the motion m of the body f to the motion n of the body a . &c.

[96] 110. If the bodys ( a & b ) bee equall & the celerity of a triple to that of b , then if the force d can deprive b of its motion, the force 3d can deprive a of its motion. But if there bee lesse force 3 d p it cannot deprive a of its motion for soe the parte 3 d p would be = to the whole 3d ; if there be more force 3d +p it will doe more than deprive the body a of its motion (i.e. move it the contrary way) otherwise the parte 3d would be equall to the whole 3d+p . Therefore the
force which can deprive a of its motion must bee triple to the force which can deprive b of its motion & consequently (definition 106) the force wherwith a is moved is triple to the force wherewith b is moved

111 By the same reason as the celerity of the body a=b is to the celerity of b so is the force wherewith a moveth to the force wherewith b moveth.

[97] 114 There is required soe much & noe more force to reduce a body to rest than there is to move it: et e contra. And

115 Soe much force a is required to generate any quantity of motion in a body so much is required to destroy it, & e contra. For in loosing or to getting the same quantity of motion a body suffers the same quantity of mutacon in its state, & in the same body equall forces will effect a equall change

[98] 116 If the bodys a=3b , a & b are moved with the same force d then the celerity of b is triple to the celerity of a . for 3b moved by 3d is equivelox to b moved by d , but since 3b=a , therfore a moved by 3d is equivelox to b moved by d . And (axiom 108) as the celerity of a moved by d is to the celerity of a moved by 3d , soe is 1 to 3 , soe is the celerity of a moved by d to the celerity of b moved by d .

By the same reason, Any bodys f & g being moved by the same force as f is to g , soe is the celerity of g to the celerity of f acquired by that force. tis axiome the 4th And (by axiom 113) the bodys will have equall motion.

[99] 118 If the body p , be moved by the force q , & r by the force s , to find v the celerity of p & w that of r , I add t to p , soe that p+t=r , & that p , & p+t are moved with equall force, then p+t=rpvpvr the celerity of p+t, (axiom 117) alsoe, (axiom 108) sqwqws=pvr. Or qrw=pvs . that is the celerity of p is to the celerity of r as qr is to ps. And by axiom 113 the motion of p is to the motion of r as the force of p to the force of r . And by the same reason if the motion of p & r bee hindered by the force q & s , the motion lost in p is to the motion lost in r , as q is to s . or if the motion of p be increased by the force q , but the motion of r hindered by the force s ; as q , to s proportional so is the increase of motion in p , to the decrease of it in r (axiom 111

[100] 121 If 2 bodys p & r {nest} the one the other, the resistance in both is the same for soe much as p presseth upon r so much r presseth on p . And therefore they must both suffer an equall mutacion in the motion.

119 If r presseth p towards w then p presseth r towards w . {illeg} without {illeg}

120 A body must move that way which it is pressed.

122 Therefore if the body p comes from c & the body r from d soe much as { p {illeg} } motion is changed towards w soe much the motion of {illeg} changed {illeg}{illeg}


[101] 27 If two bodys b & c move from o their center of gravity they shall have equal motion For suppose b moved into the place d ; then putting, cbdob×doc=oe (axiom 25) the body c must be then moved into the place e . Alsoe cbbob×boc=oc . (axiom 25) therefore ec=b×bob×doc=b×bdc . that is c×ec=b×bd . But (axiom 11326 or) c×ecbd×b the motion of c , to the motion of d , & therefore c , & d have equall motion towards o

[102] 28. If two bodys b & c mov in the lines br & cr . The body c moveing through the space cg in the time vs , & though g h in the time nv , & through kr in the time nr . & the velocity of the body b is to the velocity of c as d , to e , & as the line cg to the line be , or as ck to br , then when the body c is in the place g , b will bee in e , & when c is in k , b will be in r . to find the line which the center of their motion describes, viz dfo . Then nameing the quantitys br=a, cr=f. bc=g. edadae=ck . kr=efdae . If o be the center of motion of the bodys at k & r ; then, b+cbefdaebefabdeb+ec=or . And the line df must passe through o . againe making gk=v . then devevd=er . & if bcfiem , then agevd=ergevad=em . &, afevd=erfevad=mr gr=gk+kr=v+efade . gm=grmr=ev+efadefevad=adev+adefaaddfeevade. since f is the center of motion in the bodys at g & e tis, b+cc gefg . b+ccegfgem=gevadcgevabd+acd=figm=&cgi=cadev+cadefcaaddcfeevbade+cade. gr=gk+kr=ev+efade. go=gror=ev+efade+abdbefeb+ec=bev+cev+cefcadeb+ec. gogi=io=adbev+cfeevbade+cade=abdv+cefvabd+acd. co=cror=fec+abdeb+ec. b+ccgcgb+c=cd . [103] Now if the lines oiifoccd . Then the line od must be a streight line. but oiifadb+cfecgeoccdfec+abdecgfec+abdecg . therefore the line do is a streight line, with which may bee found by the two points d & o . The demonstracon is the same if the body b moved from a to b

Figure 29 If two bodys q & c be moved in divers plaines, then find the shortest line pr which can bee drawne frome one line cr to the other line qp in which those bodys are moved, & that line pr shall bee perpendicular to both the lines cr & qp , viz qpr= rps=prc=recto. then draw qb equall & pr & draw br=qp . Then shall the plaine qbrp be perpendicular to the plaine bcr . Suppose also the body c moves over the space cggkkrin the timevwwttr & that the body q moves over the space qa in the time vw , & ap in the time wt . Also suppose another body b=q & equivelox to { q } that is to move over the space be=qa in the time vw {illeg}


Soe that when c is in g or k , b will bee in e or r & q in a or p . Then Then drawing {the} streight lines qc , ag , bk if b+ccbccdegfgrkok , the points d , f , & o , shall be the centers of motion of the bodys b & c , when they are in the places b & c , e & g , r & k . & (proposition 28) therefore the line ( dfo ) in a streight line. Likewise if it bee q+ccqclcagmgpknk, then the points l , m , n are centers of motion to the bodys ( q & c ) being in the places q & c , a & g , p & k . Then drawing the lines ld , mf , no , (twixt the neighbouring centers of motion) since b+cc q+ccbccdq {bc }. therefore qbc=ldc & by the same reason gfm=gea & krp=kon. Wherefore all the lines qb , ae , pr , ld , ml , no are parallell to one another. And b+0cbcdcqbldegfgea=qbmfkrkopr=bqno , soe that ld=mf=no . & since these lines ld , mf , no , are parallell, equall, in the same plaine ldon , & stand upon the same streight line do , the line lmn in which their other ends l , m , n , are are terminated (i.e. in which are all the centers of motion of the bodys ( c & q )) must bee a streight line.

The demonstracon is the same if q moved from p to q .



[106]28 & 30th. The bodys ( b & c ) being in b & c , e & g , r & k , in the same times, & d n being described by their centers of motion. Also making defsey . & mfcn. Then bebrcycrcgck (for the motions of b & c are uniform) gy =cycgkr=crckgskn (for b+ccgegfgygskrkn) mf=cs =cg+gscn=ck+kn . Againe brerbceydcfs=mc (for b+ccgegfeyfsbcdc (proposition 25)). Therefore bebrdmdcmfcn & consequently the points d f n are in one streight line. also since bebrdfdn the center of motion must bee uniforme.

[107] 31 If two bodys ( b & c ) meete & reflect one another at their center of motion shall bee in the same line kp after reflection in which it was before it. For the motion of b towards d the {center} of their motion is equall to the motion of c towards d , by proposition 25. then drawing { bkkp} & { cmbp}. then cdbdcmbk . therefore the bodys b & c have equall towards the points k & { c }. that is towards the line kp . And {illeg} {illeg} reflection so much as c presseth b from the {illeg} after reflection that is gp {illeg} {illeg} kp . { e } & g {illeg} n p {illeg} tis {illeg} equall {illeg} the {illeg} <14v> must therefore be the center of motion of the bodys b & c when they are in the places g & e . & it is in the line kp . The Demonstracon is same in all cases.

[108] 32 Figure If the bodys ( b & c ) reflect at q to e & g , & the center of their motion describe the line kdop . the velocity of that center o after reflection shall bee equall to the velocity of that center d before reflection. For from the center d draw the lines af perpendicularly to kp . & suppose the line af to have the same celerity which (the point d ) the center of motion hath before reflection, soe that when the bodys (after reflection are in e & q , the line af may bee in kr . Also draw ab kp abfcehrgkp . Then since d is the center of motion in b & c , the bodys b & c have equall motion towards d , but, bdbadcfc . Therefore, the bodys b & c have equall motion towards a & f that is towards the line adf . Now when the bodys reflect, so much as the body b presseth the body c from the line af (or sf ) or towards p soe much the body c presseth the body b from the same line, or towards k , (by x axiom 119) therefore the bodys b , & c , have equall motion from the line af , after reflection (by axiom 121) that is when are at e & g they doe equally move from the points h & r ; then drawing eg , tis eheorggo. Therefore the bodys doe equally move from the point o which (by axiom 25) must bee their center of motion, & since the motion of the line ( af or hr ) is uniforme (by supposition) & the point o is in the line hr , & also in kp (by proposition 31.) its motion must be uniforme.

Note that by this, & the 31th proposition I can find the center of motion of two bodys at any given time; & by proposition 9, or definition 5th, I can find their distance, & by proposition 25, their distance from their center of motion. that is the 2 spheres in whose perimeters they be found; There wants therefore onely their determination to bee knowne that their places in the spære may bee found.

[109] 33 Suppose the body dcgk immoveable, the surface dcg being plaine. Also let the sphæricall body amn bee moved in the perpendicular ch . so as to be reflected in c Then since the side am hath as much force to weigh or presse towards d as the side an to presse towards e by reason that a the center of its motion is in the line ch (       ) the body must be in equilibrio neither pressed towards d nor e but reflected back in the line ch . The same may be said of any bodys whose motion center is in the perpendicular to the reflecting point.

[110] 34 Take an=2bn=4cn=8dn . soe that addn71. Then draw the perpendiculars eb , fc , gd , hm . And Set a body aem upon the points a & m & let efk stand on the points e & k which are in the perpendiculars eb , & hkm , & fh , on the points f , & h & lay a Globe g let the same be supposed of hkm . Then suppose (for distinctions sake g have 8 parts of force, with which it presseth fh . Then must fh presse with 8 parts of force, that is (since fg=gh , or cd=dn ) with 4 parts on the point h , & with 4 on the point f upon the body efk , so that efk must presse with 4 parts of force viz: (since it presseth equally on the points e & k ) it presseth on k with 2 parts of force & with the other 2 at e on the body aem so that aem presseth with 2 parts of force, viz: with one on the point { n }{ m } with the other on the point a ; Soe that the body hkm hath 7 parts of pression upon the point n , 4 at h , 2 at k , & one at m , & since the pressure of all the point h k & m is directly towards { n } n will be pressed by it all. but the Globe causeth but one part of pression upon a . Now if these bodys fh , ek , aem , understood continually to diminish & come nearer to the line ad n the pressure of the body g upon a & n will still bee the same that is as 1 is to 7 , & so is the line dn to da . By the same reason it may be generally pronounced addn pressure of the body g upon n to the pressure of it upon a

35 Or if the bodys a & n bee supposed united by the line ( and ) & another body g moving towards them hit perpendicularly upon the line an at d ; as dn to ad so is the pressure of g upon { a } to its pressure upon n , so is the motion in a to the motion in n which is generated in them by those pressures of g , that is which they received from g , at the moment of reflection, & which they might continually injoy as in fig 6t.[111] did not their union by the line adn hinder

By the same reason if g reflect {nor} twixt the bodys, then addn pression of n towards s to the pression of a towards r motion of n to { a } motion of a to r .

Note that {illeg} & n are taken for the centers of motion in a & n . & adn for {illeg}



[113] 36 If the bodysGlobes a & n doe rest, but soe that the body g moveing perpendicularly to qp to them & refleting on the line qp (which is supported by but not fastened to the bodys a & n & ought now to be conceived a line onely.) doth move them by communicating its whole motion to them which it selfe looseth, Tis required what motion a & n shall receive from g . Suppose that in so much time as g moveth to d before reflection in so much time it moveth from d to e after reflection & in so much time the bodys a & n move the one to r the other to s ; & that then the point of reflection d is moved to t . Then naming the given quantitys gd=b. qd=c. qp=e. dp=ec=f. qr=z. the whole motion of a & n to r & s call xx , that is a×qr+n×ps=xx , or if anpwwq , (then w is the center of the bodys motion )     ) & if wldtqrps , then lw is a line described by their center of motion Then is (     ) xx=a+n×lw.[114] Now, as the motion of a to the motion of n (proposition 34) so is dp to dq ; Therefore (axiom 113) as the velocity of a to the velocity of n n×pda×qdqrps . that is fncazcazfn=ps . but az+n×ps=xx;that is az+cazf=xx ; or fxxaf+ac=z=fxxae=qr . & ps=cazfn=cxxen . is=fxxaecxxne=fxxxcaxxane . riisritv . therefore, tv=cfnxxccaxxanee . & tdqrtv=efnxxcfnxx+ccaxxanee= ffnxx+ccaxxanee=td . Also (by axiom 9th) gd=et=b . Therefore ed=ffnxx+ccaxxbaneeanee . Now since g hath soe much motion before reflection as all three bodys g+a+n have afterward, therefore (axiom 113) gb=xx+g×de ; Or, ed=gbxxg=ffnxx+ccaxxbaneeanee. That is 2abeegn=aeenxx+gffnxx+ccgaxx. Or, xx=2abeegnaeen+gffn+ccga=a+n×lw. Or, calling a+n=d ; then 2abeegnadeen+gdffn+ccgad=wl . Soe that by this Equation the point l twixt the bodys r & s being then their center of motion may bee always found. Note that the lines qr & ps must be described by the centers of motion of 2 bodys on divers sides of the point d that is ar by center of motion of the body a or ad , & ps by the center of n or dn

37 Now when a & n or ad & dn are united together (as in the 2d fig) they cannot seperate the one from the other, & therefore since (when they are not equivelox) rs is longer than pq , the one cannot be at s when the other is at r , but they will check the one the others motion soe as their centers of motion shall not describe streight lines (as qr or ps ) but crooked ones (as perhaps Trochoides as qmk , pht). yet the common center of their motion w or l shall retaine both the same determinacon & velocity that it would did the bodys move parallell to them selves or were they not united (by axiom {7}{17}). Soe that if the conjoyned bodys (fig 2d) move to m & h in the same time that they would have moved to r & s were they their center of motion l when they are at m & h is {the} same that it would be wer they at {illeg} & therefore may be found by the {illeg} rule, viz; aeedn+gdffn+gccad2aeegnbwl the {veloci}ty of the point l ; to the velocity of the body {illeg} befor{e}{illeg}{r}eflection. Vide

[1] {Se}{p}t 1664.

[2] Figure

[3] Figure

[4] Figure

[5] Figure

[6] Figure

[7] Figure

[8] Figure

[9] Figure

[10] Figure

[11] Figure

[12] Figure

[13] Figure

[14] Figure

[15] Figure

[16] Figure

[17] Figure

[18] Figure

[19] Figure

[20] Figure

[21] Figure

[22] Figure

[23] Figure

[24] Figure

[25] Figure

[26] Figure

[27] Figure
{illeg} 2x+13xx=gd2. xx+4x+1=ag2.

[28] 36_ 2025 1620_ 0405
29376_ 162_ 29376_ 07776_ 07290_ 00486_ a'____________b'_____c' 32076×25dd_=801900dd16038064152_ 72907290 13405370486_00518400486000324 012960648962}=104976×9_944784 09000361800 0405 1620_ 2025×25dd_=50625 10125 4050 Q:324_=104976 01296 0648 972 0216106_000 6 360216106_0127611484 9×25×36324162064_8_810018_00_ 99
36×3240194409720_11664 x+rqxx=9. r2+rxqq=2 {illeg}x=2xrx2 . rx2+2x=9.
Figure x=3. rx=6 r=2 rx+4x=18 qr2+2q=rx
2qqr2+4x=18 qr2+72r+418=0

[29] cc=52c117. c=2 6156(0 520_(0 559(2 4 1 00(0 cc=80c180

[30] 1600141420(30020 0 13. 14.192 15.225 16.5 17.289 18.324 19.361 20.400

[31] {illeg}



x3+y3axy=0 . v=3xxyayyax3yy x+3xxy2ayyz9x4yy6axxy3+aay4+aaxxyy6a3xyy+9a4y4 for x. x+3zxxazy9x46ayxx+10aayy+aaxx6a3x for x . y+3yyzazx9x46ayx2+10a2y2+aax26a3x for y
Figure ab=a=2ad ad=3aa4



{illeg}=x. ce=y. af=q. {illeg}xxx=yy. ed=z. ed=s . {illeg}c=qx. eb 2=qq. eb=q. {illeg}:2qxxx:zz: eh2. eh=2qxzzxxzzqq {illeg}= 2qxxxzq00000xx {illeg} =2qxxx+2zzqx000qq {illeg}4zx+2zxxq {illeg}=qzxzq {illeg}zxq

[34] Figure

[35] Figure

[36] dxqy+2fxyy 2pfxybyx 2ayyxdexyddyyyf

[37] {illeg} xy+ay=0 ax+yy
ed=v. cd=x. ac=y. ab=s. {illeg}=z. eg=ξ. 0=yy2xy+axx2 y= O2xxax=ac yy=2xxaxO22x4ax3. eg2=3x260xax+ao O2x4ax3 . eg2=3z2azO2z4az3 yy2xy+axxx=0 2yy+ay2xy 2y+2x +x=v x+y+ay 2x2y =v 8x44ax3+4az38z4 x3+4xxz+4xzz+4z3 2xxa2axz2az2 2xxax2z2zzaz +2z2xxax
ab=a. bdbebc. cxb=be . cϩb=eh. fe2==ccϩϩbbϩϩbb fe=cxbzb=ϩccbbb bz+ϩccbb c=x ed=xccbbb ed= ϩccϩbb+bzccbb bc eh= ϩb+zccbbca b

[38] Figure

[39] ϩecdd=ex .

[40] {illeg}00+4d3ϱ3ϩeedd+

[41] {illeg}000ϱ5+5d4ϱ4ϩeedd

[42] {illeg}00dϩ+ϱeedd=ey.

[43] ϱ2ddϱϩ+eeϱϩ0+ceϩeedd=eexy.

[44] dϩ3ϩ3+2ceϱϩeedd+2deeϱϱϩ3d3ϱϱϩ}=e3xxy

[45] {illeg} x+ax+bb=0 . {illeg} +aa0+bb

[46] ac=d. {illeg}=a. ad=b. ed=c. aab=ab. ae=e {aeb=eb.} bc=dbaab {illeg} c2= cc . ddbb2aabd+a4+aaccbb=ee.

[47] Figure
{illeg}d=a. pg=b. pd=g ead=dh . fad=gh . h=bdfad . {illeg} bdd2bdfa+aaff+eeaa=bbgg {illeg} aeeaadd=2bdaeedd+bbggbbdd . {illeg} a=bdeedd 2eeddO bbddee +2bbggeebbggdd 4e44eedd+d4

[48] Figure

[49] Figure

[50] Figure

[51] Figure

[52] Figure

[53] Figure

[54] Figure

[55] September 1664

[56] Figure

[57] Figure

[58] Figure

[59] dϱ+sϩe=x . tϱvϩ+cee= y

[60] Figure


dgegeddgg+dddgg=0. g=ddgg. dd=2gg or d=e ag2cg2cddgg=0 ag 2g+2ddgg=c. g3=dd+ggddgg. 2gg=dd . 3ccddddgg=0=c . 3ddg=3eeddgg d=e. aegd 6cdeddgg= adeg=0 +add 3ddccddggaddcg=0 9ccdd9ccgg=aagg . d4gg= {t4}gge4 36ccddee36ccggee=aaggee +aad4aaddgg 2cead3 rrx6xrx 3rx+8xx+16x3r+rr4 +4xx

[62] Figure

[63] Figure


Ian 20th 1664.

[65] Figure

[66] Figure

[67] Noe motion is lost in reflection. For the circular motion being made by continuall reflection would decay.

[68] Figure

[69] Def 3d

[70] {illeg}s Axiome 4th.

[71] Figure

[72] p Axiom 4th.

[73] Figure
Of the seperation of body{s} after reflection

[74] r axiome 3d

[75] Figure

[76] Figure

[77] Figure

[78] The center of motions determinacon & velocity

[79] x axiom 14

[80] Figure

[81] Figure
Of endeavor from the center

[82] Figure

[83] Figure

[84] Figure

[85] Figure

[86] Figure

[87] let this follow the 5t axiom

[88] Figure

[89] What force is required to beget or destroy equall velocity in unequall bodys

[90] Figure
What resistance in bodys

[91] What force Indeavor & Pression is

[92] What force or Motion is in equivelox bodys

[93] Figure
What velocity acquired or lost in equall bodys by unequall forces

[94] What motion in bodys

[95] Figure
A generall Theorem of the proportion of velocity & motion of given body moving through given spaces in given times.

[96] What force required to beget or destroy unequall celerity in equall bodys

[97] Of hindering and helping motion

[98] What celerity acquired or lost by equall forces in unequall bodys

[99] Figure
What velocity & motion gotten or lost by unequall forces in unequall bodys A Generall Theorem.

[100] Of the {illeg} force in reflected bodys

[101] Figure

[102] Figure
Two bodys being uniformely moved in the same plaine their center of motion which describe a streight line

[103] Figure
{illeg} the {illeg} {as divers plaines}

[104] Figure
of the velocity of the center of motion 14

[105] The 28th & 30th proposition done otherwise

[106] Or thus

[107] Figure
The {illeg} of motion is {illeg} before after {illeg}

[108] Figure
The center of motion in finite bodys hath the same velocity before & after reflection

[109] Figure
This ought to be proved by the 34th & 35t, & the 36t by this concerning the impresse of g on qdp

[110] Figure
Of the Advantage of force in divers positions to some center.

[111] Figure

[112] Figure

[113] Figure

[114] Figure

© 2017 The Newton Project

Professor Rob Iliffe
Director, AHRC Newton Papers Project

Scott Mandelbrote,
Fellow & Perne librarian, Peterhouse, Cambridge

Faculty of History, George Street, Oxford, OX1 2RL - newtonproject@history.ox.ac.uk

Privacy Statement

  • University of Oxford
  • Arts and Humanities Research Council
  • JISC