<II-r>

{+6=xx}{+δ=xx}

<II-v>

1.5.10.10.5.1. 1.6.15.20.15.6.1. 1.7.21.35.35.21.7.1 1.8.28.56.70.56.28.8 .1. 1.9.36.84.126.126.84.36.9.1 1.10

aa×{3:a3 } = {illeg} ab×3:cde = 6:a3b3 × 6:ccddee = 6:a3b3ccddee . to find ye proportion of two irrationall rootes. to free ye Numerato{r} or denom from {illeg}surde q{illeg} ab+c = x = ab+c × bcbc = abacbbc .

<III-r>

2axca3c 3a+abbc 6aax3aa3 +2axcabbcca4bbcc 6aax3aa3+2axabbaabc error tantum 1′ in metallo 2″ in radio 110160.1100×11230×60×60160,30,3054000160,30,601080001c 160000121200(40c 0 0 300,12,10 3000,12 36000 0 0 160,60,60.=1300,720 9a5a 3aa 0,0515130,0132 (5 {illeg} baax(9)a5 cd)ab(dacb 22 38×9 01405614 8.12 12.132 = 616 = 38 . 9.1969)392(4359 2.14 14.132 . 96.7 7.4996 1.cdab.dacb cd.1ab.dacb c.d 1.
cd.1 cdind . 1×d c . d cc . dc 1 . dc cd.1 c.d 1.dc ab.dacb . cd.1 (cdind)c . (1×d) d (cc) 1 . dc ab (dc×ab) dacb

a+3xc4bbx481aa 2bxx9a 2abxx+6bx39ca aa2ay=abbb+by aa=abbb+by+2ay aaab+bb=by2ay aaab+bbb2a=y

z=yyx 20=a 140=b zz x.y.yyx. yy=yyxx x+y+yyxa=0 xx+yy+y4xxb=0 x+y+yyxa+xx+yy+y4xxb=0

<1r>

To find a heavy bodys de{illeg}|s|cent in any given time, & ye proportion of ye pressure of ye rays {illeg}|b|y gravity to |ye| force by wch a{illeg} given body hath \any/ given motion; by this figure Figure If ye cilinders bc, df bee of glasse &c: to {kow} ye proportion of their strength is knowne by ye proportion of the{illeg} gravity of ye circles Figure a, e &c {illeg}|i|n respect of ye axis in.

If a Staffe bee bended to find ye crooked line wch it resembles.

If the motion of a line is knowne to find ye crooked line wch yt line toucheth continually.

If a stick ab revolve {sic} \wth even velocity/ about ye center a haveing ye weight c Figure fastened {in} it by {the} string bc , yn shall ye string bc bee a tangent to ye circle bde.

But i{illeg}|t| may be inquired what line ye weight (c) would describe were ye stick wth uneven velocity, {illeg} or did ye point b describe a Parabola or some other crooked line were ye weight c in some other place as at ye center { a } when ye stick began to move.

If ye ball b revolves about ye center n ye force by wch it Figure endeavours from ye center n would {beget} soe much { b } motion in a body \as ther {sic} is/ in ye time yt ye body b moves ye length {of ye} {semidiamiter {sic}} bn . [as if b is moved \wth one degree of {motion}/ through {illeg} \{illeg} {illeg}/e \ bn / in {a} seacond of an {hower} & bn is {os{illeg} {illeg}d{illeg}} yn its force from ye center {illeg} {illeg} being continually like ye force of gravity impressed upon {illeg}|ye| body during one second it will generate one degree of motion in {illeg}|yt| body.] Or ye force from {n} in one revolution is to ye force of ye body motion as radperiphrad . Demonstracon. If {ab=bc=dc= } ef=fg=gh \ ad. / =he=2fa=2fb=2fb=2gc=2ed. & ye globe {b} from a to b {yn} 2fa{ak}abfa force {or} pression of b {illeg}|u|pon fg {at} its reflecting ∶ for{illeg}|e| {sic} of b{'}s motion. therefore 4ab=ab+bc+cd+da {illeg}fa ∷ force of ye reflection in one round (viz: in b , c , d , & a) ∶ force of b 's motion. by ye sa{me} pro{illeg} ye Globe b were reflected by each side of a circumscribed polygon of 6, 8, 12, 100, 1000 sides {illeg} ye force of all ye reflections is to ye force of ye bodys as ye sum of those sides {illeg} r{adius} of ye circle about wch they are circumscribed. {illeg} is if {illeg} And so if body were reflected by {illeg} the sides of an equilaterall {illeg} circum{}|s|cribed polygon of an infinite number of sides {illeg} by {illeg} {illeg} circle it selfe) ye force of all ye reflections are to ye force of ye bodys motion {as each} those sides ({illeg} ye perimiter) to ye radius.

If ye body b moved in an Ellipsis ye {sic} its force in each point (if its motion {in yt point bee} g{illeg}) bee found by a tangent circle of equal crookednesse with ye|t| {illeg}|p|oint of ye Ellipsis.

If a body undulate in ye circle bd all its undulations of any altitude are performed Figure in ye {same} time wth ye \same/ radius. Galileus.

As radi{illeg}|u|s ab to radius ac ∷ {illeg} so are ye Squares of theire times in wch they undulate.

If c circulate in ye circle { cgef } , to whose diamiter \{ ce ,}/ ad=ab being perpendicular yn will ye body b undulate in ye same time yt c circulate.

And ye {illeg} those body circulate in ye same time whose {illeg} {illeg} from ye {illeg} to ye center d are equall

And addc force of gravity to ye force of { c } to its center d . {illeg} {illeg} {illeg} {illeg} ye motion of things falling were they not hindered by ye {illeg} may very {illeg} {illeg} cdad force form d ∶ force from a.

<1v>

[1] ag=x. gh=y. ah=c. bxx+ex+cc=0. +dxy+fy +gyy . dp=v{illeg}. ad=xxyy+cc2c [2] dg2={illeg}2ccx2+2xxyy+2ccyycx4y44aa+vv=ss vw vyxwyx . vyx=df. /fig 2d. xxyyvy y . ds=yyxxyyv \ 4c4x42bx42ex32dx3iny 2fxx 2eccxbbx42ccdx 2bccxx2ebx32bccx22ccf 2cceexeexx yy +vxxyy yyxy y3xxxyyvx + {illeg}+yxxyyx=df. y3y3+yxxvyxxyyvx+xxxyy. [3] {illeg} xxvxxyyxxyyv=bd. xxvxxyyvxxyya {illeg}{illeg}f ab=x. Parab mak=bad , ergo: ad mak=ade=bad. ergo, ab=bd.

[4] a=bad=adbasb=sad ergo tri: anb, anm, sim: ab=x. bs=a. eb=y. ae=xxyy. bo=v ao=xx2vy+vv. abas boos . xxx2ay+aa v av . vat={illeg}||bao=oas. ab=x. as=y. bo=v. bs=a. xy vav . vy=axvx Hyperb.

[5] os=v. sa=x. oi=ae=y. saae sooh=vyx . oioh de : ergo ey=dvyx. & ex=dv. Hyp: abaebccn. ae×vx=cn. deae×vx.ae . dx=ev.

[6] ab=y. as=x. bc=v. bac=cas, Ergo yxvav. bs=a. & xv=ayvy. Ellipsis.

[7] ab=x. as=y. bac=tar=cas. Ergo, baasbc=vcs=av ayyv= axvx=vy. Hyperb.

[8]

The invention of Figures for refra|le|ctions. \at right angles/ at ye point refra|le|cting ac ye rad: reflected to ye focus b. ag ye radius reflected {illeg}|fr|o ye focus b. aq a perpendic: to ye ed ye tangent of ye crood|k|ed line shought. ab=x. \ac=y, or,/ bd=w. ag=y. bg=a, or, bc=a. bd=v, or bq=a. fig: 1st[9]. eac=bad=adb. Ergo, ab=bd, or x=v. & caq=qab=aqb. e{illeg}|rg|o ab={illeg}qg. x=v. fig: 2d[10]. eac=bad=adg. Ergo, abag bddg axvx=vy. &, ab {illeg}agqbbg. {illeg} Ergo ax+vx=yy|v|. v=bq. fig 3d[11]. eac=bad {illeg} Ergo caq=qab . Ergo, caab cqqb . & axvx=vy.

The invention of figures for refraction. b , & g ye foci. ca ye Rad: refracted to b . qa ye Rad: refracted from b. bg ye distance of ye foci. qa ye perpend: to de ye tangent of ye crood|k|ed line sought qr, qh= perpendic:s to ye Radiusi cg, fb.

bg=a. bq=v. ba=x. ag=y. fig: 1st[12]. abas bqqr=vyx . deqrqh, Ergo. dx=ev. fig: 2d[13]. abas bqqr=vyx . de∶  {sic}qhqr, Ergo. {illeg}|e|x=dv. fig 3d[14]. abas bqqr=vinasx . de∶  {sic}qr agas gqqh=a+vinasy . de qhqr /qrqh\: Ergo eax+evx=dvy dax+dvx=evy . fig {illeg} 4th[15]. abas bqqr=vinasx . agas gqqh=vainasy . de qrqh : dvxdax=evy . fig 5t[16]. abas bqqr=vinasx . agas gqqh=avinasy . de qhqr . eaxevx=dvy . fig 6t. abas bqqr=vinasx . agas gqqh=avinasy . de qrhq . e | d | axd {illeg}| v |x=evy.

<2r>

ad=a. ae=x. ed=y. af=z. fd=az.
xxzz=yyzz+2azaa. fg=v \2/ aeefaggi. & deefdggh. [17] xxyy+aa2a=af. yyxx+aa2a=fd. x {illeg} 2aaxxx4+2xxyyy4+2aayya4 4aa xxyy+aa+2av2agi . gi \{illeg}/ =2aaxx+2xxyy+2aayyx4y4a4in+2aaxx2aayy2xxyy+x4+y4+a4+2xxav2yyav+2a3v+4aax gh=2aaxx+2xxyy+2aayyx4y4a4in0000000000000000000 ef={illeg}|m|. ae=xmxxyy+aa+2av2a|=|aggi=mxxmyy+maa+2mav2ax. edmgdmyymxx+maa2mav2ay=gh. gighde: therefore dyydxx+daa2davy=exxeyy+eaa2eavx. {illeg} d=2. e {illeg}=1 . y3 + 2xyy xxy + 2aax = 0 aay 2x3 2avy 4axv y3+2xyyxxyaay+2aax2x3 2ay+4ax =v=xxyy2a+2axay2y+4x bf=2aax+2aay+2xxyyx4y4a4iny+2xy3+2xyyxyyaay+2aax2x3in2a. af=v ae {ef}aggi. deefdggh. degigh. xmvmvx. ymavmamvy. demvxmamvy: & adxdvx=evy. af=x. fe=y. ae=xx+yy. ed=xx2ax+aa+yy. adxx+yydvxx+yy=evxx2ax+aa+yy aaddxx+aaddyy+2addvxx+2addvyy+ddvvxx+ddvvyy=eevvxx2eevvax+eevvaa+eevvyy. ef=o. bc= 2aaxxyx4ya4y+2aay3+2xxy3y5+4a2x3+4aayyx+4yyx32y4x2a4x2y4xx5 2aoy34aoxyy+2aoxxy+2a3oy4a3ox+4aox3 +2ay3+4axyy2axxy2a3y+4a3x4ax3 [18] an=on pg=a. ab={illeg}|y.| ag={illeg}|x.| pg=b. pm=c. gb=z. gq=v. ezxevx=dvy. gm=p. gs= [19] ab=x. qb=v {illeg}. v=x. mp=a. {illeg} aq=vvxx. xxv=bs. sa=vvxxx4vv. nb=y. mn=yvvvxx nr=nb. edtb=nmrs=dyvvxxev. rsnr mn np = yyv vvxx dyev vvxx = eyd yyvvyyxx+aavv eeyyvvddyyvv+ddyyxx=ddaavv. mn2=ddaavvddaaxxeezzddzz+ddxx. np2=eeaavveezzddzz+ddxx. mb2=ddaavveezzddzz+ddxx {illeg} =zz. ddaaxxddxxzzeezzddzz=vv. v=dxaazzzeedd. sa2 bs2=eezzxxddzzxxddaaddzz . as2=ddaaxxeezzxxddaaddzz . sbab ab \2/ {bq}{bp}{illeg}sb 2 xx= \2/ {illeg}sb{illeg}b{illeg}sb. sb=. sb=n: xxnn=sa2=x/+\n×xn. xx{illeg}x+3n{illeg} xxnn=nn{illeg}x ab=x=bq=v . as=y. nb=z nm=yzx. ed{illeg}zdze=np. {illeg} e2yyzz+aaxxe2=ddzzxx nb2=eeaaxxddxxeeyy. nm2=eeaayyddxxeeyy. mb2=eeaaxxeeaayyddxxeeyy. {illeg} np2=aaddxxddxxeeyy={illeg}ξ2. xx{illeg}yy{illeg}xx{illeg}yy as2=ddzzxxeeaaxxeezz=aaddxx+ddxxξξeeξξ. dd{illeg}ξξeeaaξξ+aaddzz=0. [20] ab= [21] ab=bq=x. pm=a. as=y. no=z: zxy=nb . om=zza=mt. po=aazza. pn2=a4aazz+z4aazzxxyy{pt{illeg}} pt2=a4+2aazz+z4aa tb2{}z6xx bxx=cyy. xxbxxc=sb2. xcbceeaaxxeeaabxxcddxxeebxxc= xx|yy|=bxx+c{illeg}x+ {illeg}g. sb2=xxbxx{illeg}cxg. mb2= eeaaxxeeaabxxeeaacxeeaag ddxxeebxxeecxeeg . qa=s. qm=v. vv+xxbxxcxg. + eeaaxxeeaabx2eeaacxeeag ddxxeebxxeecxeeg : 2xxbxxcxginc?aaxxc2a2bx2e2a2{illeg}{illeg}d2x2e2bx2e2cxe{illeg}{illeg} 2vxxbxxcxg+2v e2a2x2e2a2bx2e2a2cxe2a2g ddxxeebx2eecxeeg =ss=vv+xx+
=2ox+2ee mb=z. sb=x. sa=y. ab2=xx+yy. zz=eeaaxxddxx+ddyyee sm={illeg}|x| {illeg} sa=y. mb=z. sb2=xx+2zx+zz. x2=byy+cy+d. yy{illeg}=bxx+cx+g. sm=xeeaaxxddxx+ddeeinbxx+cx+y vv2vx+2veeaaxxddxx+ddeeinbxx+cx+g{+}xx+eeaaxxddxx+ddeeinbx+cx+g2xeeaaxx????+ddinbbxx+ =ss=2vo+2v2xeeaaxx2eeaaoxddxx+2ddox+ddeeinbxx+2box+cx+co+g+{illeg} vv. mb=z. sb=x: sa=y. {mn=}yzx. ab2=xx+yy. zzxx+zzyyxx={sb2 }{illeg} eezzxx+eezzyyddaaxxddyyzz=0. x2=bzz+{illeg}. yy=e?????dd{illeg} vv2vbzz+cz+g+bzz+cz+g+eezzddaainbzxddzzeezz{illeg} {4vvbin} bz2+cz+g+z44aaz2+4a4inQ:bzz+cz+gz4{illeg} 4z4vbzz+cz+ginzz2aainbzz+cz+gz4{illeg} 4{illeg} +16oa4in{illeg}+gg{illeg} 16ovz2bzz+cz+ginzz2{illeg}inbz

<2v>

[22] [23] Figure Make ye line ac to revolve about ye point a : on ye end c let ye nut c bee fastened so {as} to t{illeg}|u|rne about its center. make ab=ac & fastend another nut at ye point b in ye same manner. {illeg} make ye line bc to slide through those two nuts soe yt ye △ abc will always be an isosceles. To ye line cb fasten ye line rstv at {illeg} right angles. {illeg} make ye line kg wth 2 nuts e & d at each end through wch ye lines rs & tu must slide to keepe ye line kg perpendicular to bc , in {illeg}|ye| midst of kg fasten ye nutt m so as it {illeg} may turne about its center & yt ye line ac may slit|d|e thro{illeg}|ugh| it then make yt side of ye line kg wch is next ab to be a file wch must be very smooth at the point m but must grow rougher towards ye ends d & e . Then by turneing ye line ac \to & from l & h / about its center & holding ye file kg close to ye plate hmflab , it shall fil{illeg}|e| it into ye shape of a Parabola.

Figure To describe ye Parabola by points. {illeg}|Ma|ke ca=r4; c ye {illeg}|v|ertex; {illeg}|a | ye focus; ab=r. yn wth some radius as ag=ae, describe ye circle ge : & take bd=2ga=2{illeg}ae=\2/de & ye point e shall bee in ye parabola, also if from e to g , a \streight/ line be drawne it shall touch ye Parab: in e.

Or thus, take ch=ca=r4, hd=2cg \or da=2hg:/; & ga=ae=de. &c:

Or thus, take cm=gc, dm=ma; & ga=ae=de; &c.

Or thus take cm=gc & raise me a perpendicular to ca, wch shall intersect ye parab, & circle ge in ye same point.

Figure Or thus. {illeg}|U|pon ye focus or center a describe ye center {ef} make ab=r4. bd=2bc= {illeg}|r|. kb=bg. wth ye Rad bc describe bed . ye circle.

[24] Or thus take \r2=/ac=cn=Rad. Circle aen: ab=r4. am=ap & produce mp indefinitely. Then take some point ad in ye line an , & draw dg perpendic: to an yt is soe yt dm=dg, yn take df=ae, & f shall be a point in ye parabola afr.

<3r>

Banderon's addition to Ferrarius's Lexion \Geographicu/, ye best for Geog. {T}{F}{illeg} \Ortelius/ Geogr. Lexicon. MrJohn Craige DrArchibald Pitcarne } Scotch Mathematicians

Experiments about \the resistance of/ things falling in water.

1. I filled to ye top a {illeg}|woo|den vessel {illeg} 9 inches squa{illeg}|r|e within & 9 foot 412 inche{illeg}|s| high \within/. And making balls of bees wax of several bignesses & wth pieces of Lead stuck in them to give them weight: three balls each of wch weighed in the air 7612 grains & in ye water 5116 grains, fell each of them in ye water from ye top to ye bottom of ye vessel in 15″ of time the motion of descent being (to {sence}) almost uniform almost from ye top to ye bottom. so then a globe equall to 71716 gr of water moving \uniformly/ 9 foot 412 inches ({illeg}) in 15″ of time feels a resistance equal to 5116 gr of weight.

2. Two balls, each weighing in air 15614 gr in water 77 gr fell each of them the same height \of 9 foot 412 {dig.}/ in 4″ of time. And these expts seemed sufficiently accurate.

Corol. Ergo ye resistance is as ye square of the velocity.

3. Two balls weighing \each of them/ in air 245 gr, in water \{almost}{illeg}/ 1gr12 fell \each/ ye same height in 4412″. But thi|e|se expts w{illeg}|er|e not so accurate as {sic} for{mers.}

The same two balls augmented wth lead so as each of them to weigh in air 25112 in water 7gr18

Three balls

<4r>

[25] as=y. sm=x. mb=z. mp=a. \qs=v/ mn=yzx+z. ab2=xx+yy+2zx+zz. zzyy+zzxx+2z3x+z4xx+2zx+zz=nb2. eezzyy+eezzxx+2eez3x+eez4 ddxx+2ddzx+ddzz =np2=aa+yyzzxx+2zx+zz. sb=z. mn=zyxyz. ab2=qb2=zz+y nb2= z.4+yyzz.2xz.32xz.yy+xxzz.+xxyy. zz= ddzzyy.2d2zxy.y+ddxx.y2+aaddzzeezz . e2=1. d2= z42xz3+xxzz+2xyyzxxyy=0 yy 2aa . Suppose. yy=fx2+2gx+h. |yn,| v=fx+g. z+fx+g=ω. ω44fxω3+6ffxxω24f3x30000z+f4x4=0 4g+12fgx12ffxxg+4f3x3g 2x+6gg12fxgg+6ffxxgg +5fxx4g3+4fxg3 +4gx4ffx3+g4 +xx+6fgx2+f3x4 2ggx+2ffx3g 2aa+fxgg h+2gxx +2fhxffx4 +2gh4fgx3 +4faax3ggx2 +4gaaffhx2 +2hx2fghx ggh 2aaffxx 4aafgx 2aagg 2fhxx 2ghx fx4 2gx3 hxx . & ω=bq. ab=ξ. sb2=ξ2y2. mb=ξξyyx. ξξyyyx ξξyy =nm. ξξξyyξx ξξyy =nb. |nb2= |aa.dd+ yyξξdd.y4dd.+yyxxdd.2d2yyxξ2y 2 eeξξyyee = eeξ4.eeξξyy.+eeξξxx.2eeξξxξξyy eeξξeeyy . dd=2. ee=1. 2aaξ22aayy+3yyξ22y4+2yyxxξ4ξξxx 4yyxξ2y2+2ξξxxxyy } =0 .

Problems. 1 To find ye axis, diameters, cente{illeg}|r|s, asymptotes \& vertices/ of lines

2 To compare their crookednesse wth ye crookednes of a gi{illeg}|v|en circle

3 To find ye longest & shortest lines wch can {illeg}|b|e drawn wth in & perpendicular to the line & to find a{illeg}|ll| such lines are {illeg}|per|pendicular at both ends to ye given crooked line

4 To find where th{illeg}|ei|r greatest or least crokednesse is.

5 To find ye areas, ye l{illeg}|e|ngths, & centers of gravity {illeg}|o|f crooked lines \when it may b{e}/

[26] 6 If y (one {illeg}|u|ndetermined quantity) moves perpendic{illeg}|u|larly to x (ye other undetermin{ed} quantity. if s=a secant=db. v=dc. y=bc. x=ca. Then having ye proportion of {illeg}|v| to {x}{s} to find y, or having ye proportion of v to y to find x: when it may bee.

7 To reduce all kinds of equations, when it may bee

8 To find tangents to any crooked lines. Whither Geometricall or Mechanicall

9 To compare ye superficies of one line wth ye area of another & to find ye centers of gravity twixt two lines or sollids. 15

10 Ha{illeg}|v|eing ye {illeg} respe position wch x must beare to y {illeg} (as if x is always in ye same line, but y cutteth x at given angeles {sic}. or if x & y wheeling about 2 poles describe ye lines by theire intersection &c) to find theire position in respect of ye line soe ye equation e{illeg}|x|pressing theire relation may bee as simple as may bee (as to find in w{illeg}|h|at line x is & wt angles it maketh with y; or to find ye distance of ye 2 poles & in what line they must be, soe yt ye relation twix{t} x & y may bee had in a{illeg}|s| simple termes as may bee).

11 Of ye description of lines.

12 Reasonings of gra{illeg}|v|ity & levity upon severall suppositions (as yt ye rays of gravity are parallel or verge towards a center; yt they are reflected, refracted, or neith{er} by ye weighty body &c.

13 Of ye u{illeg}|s|e of line{illeg}|s|

< insertion from lower down f 4r >

14. To f{illeg}|i|nd such lines whose areas length or centers of gravity {illeg}|m|ay bee found.

15. To compare ye areas, lenghs {sic}, gravity of lines \when it may bee./ & to find such lines whose lengths, {illeg}|ar|eas may be comp{illeg}

16. To doe ye same to sollids in respect of theire areas, content, gravity &c wch was done to lines in respect of their are{illeg} lengths, areas, & gravity.

17. Of lines wch l{illeg}|y|e not in ye same plane as tho{illeg}|se| made by ye intersection of a cone & {sphæreides}.

18. Two equations given to {illeg}|k|now whither they expresse ye same line or not.

19. Of ye proportion wch ye rootes of an equation beare to one another.

20 One line being to find other lines at {pleasure} of {illeg} {same length} {illeg}

21 How much doth any medium resist ye motion of any given body.

22 To Determin maxima & minima in equation wch hath more then {sic} {illeg} unknowne quantitys.

To Determin max & min by numbers.

< text from f 4r resumes >
<4v>

[27] cd=x. gd=y. rx+rqxx=rx. ac=a de=12r+rqx. ag=aa+2ax+xx+rx+rxxq. af=a+x+12x+rq aa+2ax+xx+ar+2aqrx+rxxq+rrxxqq+14r r = fa2 , in rx+rqxx aa+2ax+xx+rx+rxxq =fo2. fofl2.1. |aa+ar+14rr=bb| |xc=2ax+2arxq+rrxq| |fl2=| aarx+aarqxx+2arxx+2arxxx+rx3+rqx4+arrx+3arrqxx+14r3x+r3xx2q+2arrx3qq+2r3x3qq+r3x4q3 2aa+4ax+2xx+2rx+2rxxq aar+arr+14r3=bbr. a+12r=b. bbrx+crxx+grx3+rqq+r3x4q 2aa+4bx+2q+2rxxq =fl2. aaq+2a+3arq+rr2q=c . 2aq+1+2aaqq+2rrqq=g . {illeg} {illeg} r= {illeg} /r=2 q=6. x=3.\ gd=r2x+13xx=3. {illeg} /ac=1\ df=r2+rqx=2. ag=5. 53af=6185=of . fl=95. deoffl=18e5d. dk=9×29324ee25ddO 18×324ee25dd+81×324ee25dd9×Q:324ee25dd: 8118×324ee25dd+Q:324ee25dd: . dk=450dd225d2324eeO801900ddee944784e4 50625dddd145800ddee+104976e4 dk=50dd25dd36eeO9900ddee11664e4 625d41800ddee+1296e4 }=g. de=a3. g=p+ps . e=1 9aae254aee+81ee18agee+54gee+9ggee ddgg +aaee6aee+9ee 2age2+6ge2+ggee dd 9aa+54a81 +18ag54g9gg gg =e 2 =z2 +9aaee54aee+81ee18apee18aeeqs+54eep+54eeqs+9eepp+9eeqs2qsqs×eea=z2 +eep4+6eeppqs+eeqqrs+2aaeepqs2aaep3+18eepqs+aaeepp+aaeeqs+6eeqsqs 9aadd+54add81dd12aaeepqs+6eep3+18eeqs6aeepp6aeeqs +18apdd54pdd9ppdd6aaeepqs54d2qs+9eepp+9eeqs +18eeppqs18pddqs6aeepqs +4eep3qs+18eepqs +4eepqsqs9ddqs +18addqs ddpp+2ddpqs+ddqs

[28] ac=a=ce . cd=x. dg=y. bc=x. df=12r. rx=yy. aa+2ax+rx+xx rxaa+2ax+ar+rx+xx+14rrlf. rx+ar+14rrinrxaa+2ax+rx+xx=fo2. fl2=eerxdd+4eearrx+eer3x4ddaa+8ddax+4ddrx+4ddxx. fl2=pp. lk=r ac=a. ab=x. axxax . xx=aaax. xx=42x. x=1+5 2515135. 625=525+1. xx=ax+aa. 14418_324 18×25_=45009036 14410 324×18_=58322592324 / 02916011664}=145800\ 003242592}=2624458320032076 x=1a+5aa4 ei=a. hk=z.h{illeg}=ezd \gd=y/ hi=ezd. he=eezzaadddd. ek=ddzzeezz+aadddd. ce=a. fl=b fk=c. lk=ccbb. zeezzaaddddcb{illeg}. c=dbzeezzaadd. lk2=ddbbzzbbeezz+aabbddeezzaadd. df=v lk=bv+dbbzeezzaaddy {illeg} =dbby+bveezzaaddyeezzaadd=yddbbzzbbeezz+aabbddyeezzaadd ddbbyy+vveezzvvaaddddyyzz+eeyyzzaayydd+2b dvyeez2aadd=0. ab=q. bc=x. dc=y. r=latrxrxrxxq=yy. ef=b. fg=c. eb=12qb. cf=x12q. ce=x12q+b. bcx12q+by. cx12qc+bc b=y=rxrxxq ccxxqccx+2bccx+14qqccqccb+bbcc=0 +bbrqxxbbrx . q=3. fg=c=1 {illeg} b=1. xx+13xx=3x2x+x94+31=0. 4xx3=2x14=0 xx=64x316. x=34O9316. x=34O38 rx+rxxq=9. r2+rxq=2 /12r+rxxq=7 rx2 {illeg}=7.\ ac=a . kd=b. ad=c. dc=d. {illeg} cababc {illeg} dabec=cf. kl=e. x=1. r=14. ad=a. dl=b. lk=c. ac=g. dgbea=ce. ddgceea=ef. of2=d4ggcce4ccaae4aa. e=2. d=2. +bggc +bggcca acc=of2. g=c=1=a. 15=of2. ggcc16aacc. g={illeg}|{ 8 }| {illeg} =8a={illeg}2 c 3 =of2 . ab=a. bc=b. cd=c. be=x. ce=xb. de=xx2bx+bbcc=cxa . xx=2bxbb+ccinaaaacc x=aabaaccOa4bb+aabbcc+a4ccaac4a42aacc+c4 bm=f. be=g. me=fg. ab=a. {illeg} cd=c. agcgca=de. gafgafagg=mr. mn=z. aaff2aafg+aagggg+ff2fg+gg(=re2)ineedd=rn2=aaff2aafg+aagggg+zz.

<5r>

eh=8 {}{} ei=6 hi=10. ek=15. 0751546=289=17=hk. {gh= }{gk= } de={illeg}15. dg=16=y. cd=x. df=a. gk={14} 3416 gkgd 178 30a2408a17=fl . flfo 10 17 . 1204a5=244a5=fo . ad=b. ag=bb+{illeg} 256bb+256 576192a5+16aa25 576bb1925abb+16aabb25256+576192a5+16aa25 = af2 = aa+2ab+ {illeg} 5bb4+3abb20 +aabb4009aa252ab1925a+576=0. +500bb+60a+aa=200ab+144aa+15360a230400 {illeg} yy=rx+rqxx=256. rqx+r2=a. 256ax=12rx. 512xa2=r eh=52 . {illeg} ei=6. hi=132. hk=222120. ek=9514920gh={illeg} 22120502022120+cdg=5020+221 dg=52+50c221 . 9c5149221=de fk=00+9514920 {illeg} fk=9c5149221+ ek=3514920. kd=g. 5g×2065149=50g35149=dg. dg2=2500gg46341. gk2=48841gg. fk=ca. 50cg50ag35149in221=fl=f k×dggk 50cg50ag3905149=fo. ae=p. {illeg} d e=g3514920 ad=pg+3514920. ag2=pp2pg+48841gg46341+46341400+3p1051493g105149 ag2gd2af2fo2.

eh={illeg}. {illeg} eh=a. ei=b. hi=aa+bb hk=deaa+bb. ek=ddaa+ddbbeeaae eh=c. ek=ddcc+ddbb000ee 2abx=n. axx+abbbxx+baafg. abbgaabfaxxgbxxf=0 nn4aabb=xx. agnnbfnn+4a3b4g4a4b3f=0. f=10. g=17. b4 axxabb=6. xx=6+abba. 17abb10aab10b17a=xx 10a3b17aabb+10ab3+60b=017aabb102a {illeg} a33410aab+abb+6=0102a10b. qa2+qa+s×a+c. c{illeg}=6s. r+6s=34b10. 10r34+6034s=b. a3+raa+sa+cs +c+cr r=6s34b10. 36ss204b10s+s=bb10210b. cc=20 c45 qa3+raa+sa+sc +qc+rc . b=1 10ba3 10a334aa+112 a +60. 04483360_3808_ (2. 2. 2. 2. 2. 7. / 2. 2. 3. 5 190495247623811917 03868.(2.2.967 01934( 00967( 1.2.4.6.10.3.5.15.30. 20 10.0. 0 2.967.4.1934.3868. 10 0036=1020=_1056= pqrDiv nn+2pn . pn=c \{illeg} aa4a/ 4 10a334aa92a+60 34+2+4 2 . 4 12034_86 15034_126 036827 00_0120_3168 (2.2.1594.797. 372 3720_ 4094 120_ 3974 1987 014c 056 14 (296160_ 256 144180_ 324 11713 20a334aa{illeg}136aa {illeg}22a \{illeg}/ + {illeg} 120 49_96480_57649 6252 a2410a 6 {illeg} [29] 30a3306aa+168a180. 1008(2.2.3.3.4.6.9.12.24.18.54.36. 50400_ 0180_ 51228.25614.12807.4269.1423 1361531134217 102 40a3204340aa+640102a+240. 0 40a3544aa538a+240. eh=12.ei=9. hi=15.hk=20.ek=16. 17_ 119 170_ 0289_ 2083 2890 49131530_ 3 729 816480_6561×4= { 2 }620 {illeg}| 1 | {illeg}

[30] d {illeg}3= axxca=bb. axx+abbbxx+baaed. daxx+dabb=ebxx+ebaa. 25839(600239{illeg} xx=aabeabbdadeb=10aab17abb17a10b. xx=17abb10aab10b17a. 40b17abb+10aab. /a=917. b=1. {illeg}\ 109017{illeg} 3,4,9. 5,12,13. 7,24,25. 12,16,20. 12,9,15. xx=4abb3aab3b4a. {3 } x4axx4abb+3aab ax2xx+2bb3bO 4x4+8bbxx+4b49bbxx 9bb . 4x4bbxx+4b4. x=4 . b=1 . {illeg}+86O86=a=3{illeg} {illeg}=43 x={illeg} x={illeg} {illeg}+13=ab{illeg}4+19{illeg}15 7 4x4bbx2+4b4=4bx4 [31] {illeg}83 3. 8+23=103=cb. 4+49. 309 . {illeg} 83 {illeg} b={illeg} 4x4c4x5+=bb. {illeg}+{illeg}={illeg}2bc+cc. cc+xx2c=b. 4x4bbxx {illeg} b4=4b4bbxx+63 {illeg} {illeg} = {illeg}c44a2bb{illeg}3aab=4bb3ab=4bb4{illeg}cc. 4c{illeg} {illeg}aa={illeg}4aa{illeg} {illeg}9acc{illeg}36a{illeg} {illeg}

<5v>

[32] 4x4bbxx+4b4=4b4+4bbcc+c4 2 4x4c4 4cc+xx =bb= 4x6+16ccx44xx4c6 4c4+4ccxx+x4 . hx2+in+{illeg} ax3+bx2+cx+d. 4x4b2x2+4b4=bb+cx+dxx+ee. 4x4bbxx=4bbcx4bbdxx4bbee+ccxx+2cdx3+2ceex+ddx4+2deexx+e4: +4x4+ddx4+2cdx3+ccxx+2deexx+2ceex+e4 xx+4dxx+4cx+4ee =bb. |24503 /2236+4520\ 223 12+15203 | 2fxx+2gfx+ff. 2e=f. 2ce=2g. ccxxe=xx+4dxx cc=ee+4dee. d=cc+ee4ee 4x4 : +c4+2ccee+e416e4inx4 : +c3+cee2eeinx3 : + ccxx : +e4+ccee2eeinxx : +2ceex + e4 . xx : +cc+ee2eeinxx +4cx +4ee =bb hhx4+2hix3+2hkx2+2ikx+kk +ijxx . 63e4+2ccee+c416e4=hk. {illeg} {illeg}e {illeg}k {illeg}ee. 2fxx+2gfx+ff. 2e=f. 2ce=2g. ccxxe=xx+4dxx cc=ee+4dee. d=cc+ee4ee 4x4 : +c4+2ccee+e416e4inx4 : +c3+cee2eeinx3 : + 32ccxx + ee2xx + 32ccxx + 2ceex + e4 ccxxee + 4cx + 4ee =bb k=ee. 2i=2c. i=c. {illeg} h=cc+ee4ee. c4+2ccee63e416e4=hk {illeg} c4+2ccee63e4=c4+2ccee+e4. ee=k. i=c. d=h. c4+2ccee+e4eeinx4 : +c3+cee2eeinx3 : + 32ccxx + ee2xx + 32ccxx + 2ceex + e4 +ff 2f =xx .

[33] 43+32+12+2+92= {illeg} 6 /{illeg}\ x3+y3 +9zz43azx2y+y3z3azxyy 9x46ayx2+10aay2+aax26a3x 25+5+6+12+4+14112 834f 2ff / 5 \ 254+58+ 6424+6+2{illeg} {illeg}|5| dabbebxxebaa+d axx=0 dpqqeqyyeqpp+dpyy=0 . ssv2 + 2vyyy=a4yy2a42y3+2y 2ab=2exx. daxxeaaexx= b . ebxx +ebaa abb + axx =d= eq y y +eqpp pqq + pyy . pqqbxx+pqqbaa+pyybxx+pyybaa abbqyyabbqppaxxqyyaxxqpp =0 pqqa+pyya =bqyy+bqpp. axxqyy+axxqpp=pqqbxx+pyybxx. pqqab+pyyab =bbppq+xxppq. axxqyy+abbqyy=pqqbxx+pyybxx. bbpq+xxpq bqq+byy =a= pqqbxx+p yybxx qyyxx+qyybb . aabpyyabbqyy+bpyyxx=0 +aabpqqabbqpp+bpqqxx=0 axxqyy axxqpp . aa+xx= abbqyy+abbqpp+axxqyy+axxqpp bpyy+bpqq aabpyy+aabpqq = abbqyy+axxqyy a=x=bqq=yy=pp

< insertion from the bottom >

b3+z3=abz . bb2bx+xx+yy ss2vv+2vxxx=r4xx 0012-2 2r42xxx+2xx2x=v {illeg}

< text from f 5v resumes >

hgxxgix+ . hkx+ik. 2rxxx+rr=yy. v=rx. rx+rqxxyy=0 120 . r=2rxq 2rx+2yx+xx=yy r+y+x . xx {illeg} =q2 yy=rq2+rq4xx+yy axxx=yy. yyrq4. 2rxxx =yy. v=rx. x={illeg}rSymbol (taurus Operator with dot inside circle) in text2rr x Symbol (taurus Operator with dot outside circle) in textrzSymbol (inverted taurus Operator with dot outside circle) in textzx for x {illeg}|wri|te x+zzxr 00000+rr{illeg} for {illeg}| y | write 2rxxx4zx+2zxxr+2zzxrzzxxrr {illeg} 00000xx {illeg} r {illeg} x \/ z 2rxxxr for y rx {illeg} z Symbol (inverted taurus Operator with dot outside circle) in text 2zx {illeg} x 2x {illeg} Symbol (taurus Operator with dot inside circle) in text2 zx Symbol (inverted taurus Operator with dot inside circle) in text2 zx xr 2zzxr=+2rx xx+2rxxx+2x3r /4rxSymbol (inverted taurus Operator) in text2x3r4xx+2x3r\ {illeg}Symbol (inverted taurus Operator with dot outside circle) in text{illeg} xx+ xxz Symbol (taurus Operator with dot outside circle) in text4zxSymbol (inverted taurus Operator with dot inside circle) in text 2zxxr 2 z2 {illeg} z Symbol (inverted taurus Operator with dot outside circle) in text4zxr Symbol (taurus Operator with dot inside circle) in text2z{illeg}Symbol (inverted taurus Operator with dot inside circle) in text4zxr=0 {illeg}{illeg}xx zz+2zzxrzxxrr {illeg}{illeg}xx

<6r>

[34] ag=x. bg=y. ag=x. gd=d. dc=e. bo=s. de=w. gh=b. yvy+bvy+vby=. \go=v./ if=c. ewe+bew000e ew+bwe=if. yvy+byv+bvy=hf. dc×de{illeg}dc+bw de+hi+gh×dedc=go+gh×gobg. ag{illeg}
ag=x. bg=y. r x=yy. go=de=12r. gd=o. dc=rx+ro. {illeg} gh=z. o+rz zrx+ro =rzzrx 2orx{illeg} 4orrxx+rrox + 2rzrx = 2rzrx+ro. 4ozrx3+roxx=4zzro. x3=zzr. z=x3r. rxr2x3rxrx2rx=x2 {illeg} x+r2=hf. x3r+9xx4+3rx2+rr4=bf2. rx+xx=yy{illeg}
[35] xy=rr. v=yyx=y3rr=r4x3. gh=z. dg=o. de=+r4x3+3oxxdc=rrx+ofizxrr+000x+o rr +rrzxr4+rrzo x3+3xxo =fi. r4x3rrxfhzxrrx . r4+zxrrox3x3=fi rr {illeg}x4+r4+x3{illeg} rrzx4+r4x3rrzox3r4x3zrrx4+ox6+3r4xx03zx3rro+3x5oo +2rrzxx43r4=0. z=3rr2x+x32rr=gh. bh=rr2x+x32rr {illeg} +r4x3+x2=fh. r8x6+r4xx+xx4+r44xx+xx2+x64r4=bf2 6r8x63r42xx+3xx4+6x62r4. 6 x12+16x8r410r8x4 24r12. 6r12+

gogbfk+gohg . dedcfi+dedi . dc×fi+dc×de+dc dc×fi+dc×dede=di=gb×fi+gb×dg+gb×gogo. rrzx+o + r6 x4+4x3o r4 x3+3x2o = rrzx+r6x4+rrox r4 x3 . zx x+o+ r4x x4+4ox3 = zx+3zo x + r4x+3r4o x4 +xo . zx5+4zx4o+r4xx+r4ox x5+5ox4 = zx5+3zox4+r4xx+3r4ox x5 4zx9+r4x6=5zx9+5r4x6+3zx9+3r4x6 . 4zx4+7r4=0 rrz x+o + r6 x4+4ox3 inr4x3= rrzx+ rrox+r6x4inr4x3+3ox2 . zxx+ox+r4x5+4ox4=z+oxx+3ox+r4x5+3ox4 . zx3+3zoxx+r4 x5+4ox4 = zx4+ox4+3ozx3+xr4+3or4 x6+6ox5 zx5+ 3zox4 + r4xx 6zox4+ 6r4xo =zx5+ 2 ox5 + 3ozx4 + xxr4 + 4ozx4 + 3oxr4 + 4ozr4 9zx4+6xr4=x5+7zx4+7xr4 . 2zx4xr4x5=0. z=r42x3+x2. r4x3rrx r4+x4 2x3 hb . xxrrr4+x42x3r4+x42rrx=bh. r8+2r4x4+x8 4r4xx r8+2r4x4+x8 4x6 =3r8x4+3r4x8+x12+r12 4r4x6=bf. 6x12+6r4x86r8x46x12 =0 . x8r8=0 . x4r4=0 . xxrr=0 . x=r. therefore take ag=gb=r , & ye greatest crookedness of ye line cb will be found at b . bh=r=fh . bf=r2 . gh=w . hf=σ . {illeg} gb=y . go=v . wv+σ yv {illeg}. or, yv wyσ=vwvyy . go×ghgo×bgbg=fh . y3wrry4rr=σy . 2yyw rr 3yyyrr=0 . w=3y2 . 3r4+x4 2rrx =0 . x3=r6y3 . 3rr2x+r42y3=3y2+r42y3. bf=p . al=q . gb=y . go=v . ag=x. bf=p. {illeg} vyq+vxqy+yvyxv=p . gb×al+gb×gogb×gago= {illeg} yq+y4rrrr=py3rr . y4rr+3rr2yq=0. q=y32rr+3rr2y . as before. or q= yy 2x +3x2=yy+3xx2x gl=yy+xx2x . w=v+x= dyy+ey+2fxy+bx+dx2+2ayx d+dx+2ay +bx+dxw+2ayw+dyy+ey+2fxy+bx+dx2+2ayx=0 . fxx+ex+c=0 +dyx+by +dyx . w22wx+xx w2 2wc2wby2wayy2wdyx fx+e ex+dyx+c+by+ayy f . +fxx+ex+dyx+c+by a xy=aa . x=aay . y=aax . v=yyx . qaax+aayyxxa4xy=0 . qaayxx2a2y3x32a4xy . q= fxx+ex+c=0 +dyx+by +dyx . 2fxy+dyy+ey b+dx+2ay =v . qy+ 2fxyy+dy3+eyy2pfxypdyypey b+dx+2ay yx=0 [36] 2bqyf+4aqyyf+2dy3f+2eyyf2pdyyf2peyf2dyc2dbyy2day3 2pf y+by+2a yy+dey+ddyydfqy2ffyy =x x=edy2fO ee+2dey+ddyy 4cf4bfy4afy 4ff {illeg} eyf+2aeyyf+deey+ddyefdefqy {illeg} {illeg} bqyf+2aqyyf+ dy3f+ eyyf pdyyfpeyfdcydbyyday3 2pffy+bfy+2af yy+edy+ddyy dfqy2ffyy =x. 2bqyff+4aqyyff+ 2 dy3ff+ 2 ffey2 pdffyy2peffy2dcfydbfyy2dafy3 . 4befy+2aefyy+ edfy+ c ddfyy edfqy+eddyy+d2y3ddfqyy

<6v>

[37] yy{illeg} vv+yy=ss=yy+2oy vv.+xy.+ay.+ax.+yy.=ss= vv.2ov+xy.+xo+ax.+ay .+ao+yy.+2oy. . 2ov=ox+ao+2oy . =vv2ov+zy+zo+az+o = {illeg} vv+2ov+oo+rs+ra+as+ss. {illeg} v= xy+ax+ay+yyrsarasss zo . xyrs{illeg}. v=xy
yyss=2o {illeg} xy+ax+ay+2yy+vv2vy=ss=ξz+aξ+az+2zz+vv2vz xyξz+axaξ2y2z=b. xyξz2by+2bz=0 . xy2by=0 x=2b . xxyyξξzz a2xξa2 =b . 12y+12x 4x2axO22x4ax3 4z2+azO2zzzzaz 2z+2x =v 4x24zz 2x2z =b. 2x22x3bxbz 2010 /b=4x\ 2x4+2z4ax3az32zz4x2z2axz2+aazx2azxx=ccxx2c2zx+cczz \ O2x4ax3O2z4az3 =cxcz/. 2x+2z12aO2xxaxO12zzaxz4x \2xx+2zxax/ 2xO2xxax+axOa2xxax O2 xxax 4xy+2ax2xx+ay2xy2x2y= xxO6x2xxax+3axOx2xxax O22xxax 8xxO6x2xxax+3axOa2xxax O22xxax . 64x348axx+9aax 4x2a 2xxax+ 4zzx2zz 2x xx+dy+yy=0 . 2b ϩzccb cc +dϩbc +2abϩc+ 2b ϩzccb cc . d2=+a . b=0 . c= any finite line. as {illeg} x=ϩ. y=12d+z . ϩ2+14dddzzz y3=axx+aax . y+a=ϱ . ϩ ϱ33aϱ2+3aaϱaxx+aaxa3=0 0450.2250 48xx 54×16×27_324540_864 240480_720 ϩ3b3=0 . +6ϩabc+cϩccbb×a3abcϩcc=0 105300_2025 075150_225 11252250_3375 16_96160_256 db=a. ba=b . ac=c . ad=d . ddb=r , latrec:Parabdbe . ddc=s=lat:rec:Parab:dce . ccb=lat:rec:Parbgqc {illeg}. {illeg} lq=a . axx=y3. y=x+z . axx+x3+3x2z+3xz2+z3=0 . caxxx=z. +2axy3xxy6xyy3y3 3yy+6yx+3xx =v=2axy 3yy+6yx+3xx z3+3xz2+3xxz+x3d xx=0 a=8 . x=1 . {illeg} 7+3z+3zz+z3=0 y3+ ayy+2ab+abb +2b+bb zz+4z+7. z=2O47 +448+192z+24zz+z3=0. zz+20z+11 2 3x=a+2b.3xx=2ab+bbb3dbb=abb.bd=a 3x2b=a=3xxbb2b6bx+3bb+3xx=0. x=aa=b=x.ba=d. y+a×y+b×y+byyy+ayy+2abyabb+2byy+bby ax=yy. axyy+2ay+aa=0. ax=y+a. caϩrabzc+ddcc2dbcϩ +2dczr+cczz+bbϩz2aabϩ 2bϩzrbbzz+2azcd +2aazr . 2bccbb.b=c. 2dbc2aab. aac4aabbcc=4bbccdd+8 2dc+2ac=0.d=acc.d=a. af=a . ag=b . ab=ϱ . bc=z . abbh=aϱabbϱb=gb . ch=ϩbaϱ+ab . fg=c . ag=b . fg=c . fh=cϩb . af=ccbb . ϱbinccbbb=bh . bϩϱ+b×ccbbb=ch . bϩϱ+binccbbc=cd . abϩaaϱ+aab+ccϱbc=df . cc= {illeg} aa+bb . ϩbaϱ+ab aa+bb =cd=x. aϩaa+bϩ aa+bb =df=y. bϩ+abxaa+bb a =ϱ= yaa+bbaaaϩ b bbϩ+aaϩ=ayaa+bba3{illeg} abb+xaa+bb . a {illeg} ϩ=ayaaa+bb+bxaa+bb . Or ϩ= ayac+xccaac . /ϱ= yccaaax c \ ϱ=cybaaybcxac {illeg} c=5 . a=3 . ϩ=3y15+4x5 . ϱ=4y3x5 . {illeg}y4 ϩ4=ϱ3 . |5 | 27y3405yy+2025y3375=256y4768y3x+864yyxx432yx3+81x4 +108yyx1080yx+2700x 144yxx720xx +64x3 ϱϱϩ=a3 . {illeg} c=5r . a=4r . ϩ=4y20r+3x5 . ϱ=3y4x5 {illeg} =2rr . {illeg} =rr .
9yy24xy+16xx25 . 36y396xyy+64xxy+48x3=225a3 +2772xxy 180ryy+480rxy360rxx 12y3 {illeg}3 {illeg}yy 36y369xyy8xxy+48x3=0 180ryy+480rxy360rxx rrr .

<7r>

2bqff +4aqyff 2qeff 2dcf +d3yy dbyf +bef+2aefy +dee+2ddey defqddfqy = 2pff+bf+2afy +de+ddydfq2ffy inee+2edy+ddyy4af4bfy4a {illeg} 4bbqqf4 +16abqqf4y +6bqffd3yy +8aqffd3y3 8bqf3dc 4bbqf3d 4d4cf 2d4bf +4bbqf3e +8aef3bq +2befd3 +4aefd3 +6bqffdde +4d5e 4bqqf3de4bqqf3dd2d5fq +16aaqqf4 +4ddcffb8aqf3db +4ddccff16dcf3aq+16aaq3f3+d6y4 4dcffbe8dcffae 4ddcfee8d3fce8aqqf3dd +4ddcffeq+4d3cffq+ddbbff +bbeeff+8aqbef34aedbff +2be3fd2bbeffd4d3ebf +2beeffdq+4abeeff +dde4+4bddeef+4aaeeff 2de3fq+8aeeddf +ddeeffqq 2ddeebf +4ade3f+6d4ee +4d3e310d4efq +d4ffqq 8adef3qq+12aeddfq +2ddeffqb +4adeeffq 6d3eefq +2d3effqq 8ppf4edy =4ppf4+4pbf3 +4bbf3+8paf3q+4aaffyyinee+4bf4cf +4pdeff+4pddff+4afdd +4df3qq+4abff+d4 4pdqf3+2ddbf 8pqf4+4afde +bbff4adffq +2debf8aqf3 2dbffq+2ed3 4bqf32d3fq +ddee4ddffq 2ddefq 4deffq +ddffqq +f4qq
Figure
bc=x. cd=y. ef=a. ea=b. ad=c. xx+yycc=ab2+b=eb . axb+xx+yy cc=ch . aa+xx+yycc+bb+2bxx+yy cc=bf2 caa+xx+yycc+bb+2bxx+yy cc+ax b+xx+yy cc =y . ccaa+ccxx+2ccyyc4+bbcc+2bccxx+yy cc=bbyy+2by2(&c)2axx+xxyy+y4 . {illeg} yy+xx+bbcc+2bxx+yy cc ccaa2axyxx+yyaaxxax yycc
Figure ac=x. bc=y. af=z. bf=zza. \{illeg}/ df=a2 . de=aa+4zz2a . fe=2zzazxaa+zz2a 2aax=2aaz+4az3
bf=z af=az . 2z ad=aa4+az za4+zxxaa4+az+zz . 4z3+4azz+aaz=axx+4zxx .

To know whi|e|ther ye changing of ye sines {sic} of an Equation change ye nature of ye crooked line signified by yt Equation observe yt

If ye sines {sic} of every other terme (of yt Equa{illeg}|t|ion ordered{illeg} according t{illeg}|o| {either} of ye undetermined quanti{illeg}|t|ys) be changed ye nature of ye line is not changed. but if ye signes of some signes bee changed but not in {illeg}|e|ve{ry} other termes (of it ordered according to one of ye unknowne quantitys) ye nature of y{illeg}|e| line is changed.

If ye knowne qua\n/titys are every where divers, & one of ym be blotted {illeg} out yt produceth a line, when one terme is already wanting

Those lines may bee defined ye same whose natures {illeg} \may be/ expressed by ye same equation although angles made by x & y are not ye same.



In ye {illeg}|H|yperbola ye area of it beares ye same respect to its Asymptote wch a logarithme {di}{illeg} number.

To make ye equation x3ax2+abxabc=0 . be divisible by xc=0 . suppose c=x , yn tis c3acc+0=0 c=a . therefore write c in steade of a & it is x3cx2+cbxbcc=0 . wch is divisible by xc To make ye same Equation divisible by xx2ax+ac=0 Suppose it to bee divided by it & ye ration will bee xx2ax+ab)x3ax2+abxabc=0(x+a x3+2ax2abx 0+ax2+0abc axx+2aaxaab 0+2aaxaababc . The quote is 2aaxabcaab wch have vanished therefore to m{illeg}|a|ke soe suppose each terme =0 & the{illeg} will be 2aax=0 & abc+aba=0 both include a=0 . Which since it cannot happen ye equation cannot be divided ye one by ye othe{r}

The rootes of {illeg}|t|wo divers equations may easily be added to substracted from multiplyed {&c} by one another while they are unknowne.

[38] That ye penultimate terme of ye Equation x3a2x+b3=0 . bee wanting I multiply & then suppose x a knowne {illeg} quantity & y an unknowne {illeg} x3 {illeg} +b3y3 {illeg}{ d3ayy+y3=0 .} by this {having}{illeg} x {illeg} {illeg} {illeg}

<7v>

[39] ddϱ2+2dϱϩeedd+eeϩϩddϩϩ=eexx. d3ϱ3+3ddϱϱϩeedd+3dϱϩ2ee3dϱϩ2dd+eeddϩ3eedd={e3x3} [40] 6ddϱϱϩϩee6d4ϱϱϩϩ+4ee4dddϱϩ3eedd+e4ϩ42eeddϩ4+d4ϩ4=e4x4 [41] +10ee10ddd3ϱ3ϩϩ +10ee10ddddϱϱϩ3eedd +5e410eedd+5d4dϱϩ4 +e42eedd+d4ϩ5eedd =e5x5 [42] ccee2cedϩ+ddϩϩ +2ceϱ2dϩϱeedd +eeϱϱddϱϱ =eeyy. +c3e3+3cceeϱeedd+3ce3ϱϱ+eeϱ3eedd=e3y3 3cceedϩ6cedϩϱ3eedϩϱϱdd +3ceddϩϩ+3ddϩϩϱ3ceddϱϱ d3ϩ3+3d3ϩϱϱ . +c4e4+4c3e3ϱeedd+6cce4ϱϱ+4ce3ϱ3eedd+e4ϱ4=e4y4 4c3e3dϩ12cceedϩ12ce3dϩ4cedd2eedd +6cceeddϩϩ+12ceddϩϩ+6eeddϩϩ4eedϩ+d4 4ced3ϩ34d3ϩ36cceedd+4d3ϩ +d4ϩ4+12cced3ϩ 6d4ϩϩ . c5e5+5c4e4ϱeedd+10c3e5ϱϱ+10cce4ϱ3eedd+5ce5ϱ4+e4ϱ5eedd=e5y5 5c4e4dϩ 20c3e3dϩ30cce4dϩ20ce3dϩ5dϩe42eedd +10c3e3ddϩ2 +30cceeddϩ2+30ce3ddϩϩ+10eeddϩϩ10ce3dd+d4 10cceed3ϩ3 20ced3ϩ310eed3 ϩ310cceedd+10d3ϩee +5ced4ϩ4 +5d4ϩ410c3e3dd+20ced3ϩ+5ced4 d5ϩ5 +30cceed3ϩ10d4ϩϩ5ϩd5 30ced4ϩϩ +10d5ϩ3 . [43] cceeϩeedd+2ce3ϩϱ+eeϩϱϱeedd=e3xyy 3ddϩ +ddϩ 34 ceddϩϱ +cceedϱ . [44] e4xxyy= 2ce3dϩ3 +2ced3ϩ3 2deeϱϩ3eedd +4 d3ϱϩ3 +2ccdeeϱϩ +4cde3ϱϱϩ6cd3e +2deeϱ3ϩeedd4d3. 6ddceϱϱϩe2d25ddeeϱ3ϩ+c3e3ϩeedd=e4xy3 4d4ϱϩ3+3ce3ϱϱϩeedd+4d4ϱ4ϩ+ceddϩ3 +3cce4ϱϩ3ceddϱϱϩeedd +e4ϱ3ϩ +3ddeeϱϩ3 . 8ddc3e3ϱϩ 18ddcceeϱϱϩe2d22ddce3ϱ3ϩ6ddeeϱ4ϩeedd+c4e4ϩeedd=e5xy4 16d4ceϱϩ3 10d4ϱϱϩ3 +16d4ceϱ3ϩ +5d4ϱ4ϩ+6ccddeeϩ3 +4c3e5ϱϩ +6cce4ϱϱϩ +4ce5ϱ3ϩ +e4ϱ4ϩ+d4ϱ5 +12ce3ddϱϩ3 +6ddeeϱϱϩ3 . c5e5ϩeedd +5c4e6ϱϩ+10c3e5ϱϱϩeedd+10cce6ϱ3ϩ+5ce5ϱ4ϩeedd+e6ϱ5ϩ =e6xy5 +10c3e3ϩ3dd10c4e4ddϱϩ+30ce3ddϱϱϩ350cce4ddϱ3ϩ30ce3ddϱ4ϩ8e4dd +5ced4ϩ5+30cce4ddϱϩ330c3e3ddϱϱϩ+10dde4ϱ3ϩ3+25ced4ϱ4ϩ+13eed4 40cceed4ϱϩ350ced4ϱϱϩ330eed4ϱ3ϩ36d6 +5eed4ϱϩ5+40cceed4ϱ3ϩ3 6d6ϱϩ5+20d6ϱ3ϩ3 . 3c2eeeedϩ3 6ce3dϩ3ϱeedd 3e4dϱϱϩ3 +6cde3ϱ3ϩeedd +e4dϱ4ϩ =e5xxy3 d3eeϱ5+12ced3ϱϩ3 +12eed3ϱϱϩ312cd3e +3cceed3ϩ2+2c3e3dϱϩ10d5ϱϱϩ3 +d5ϩ5 +6ccde4ϱϱϩ5eed3 +3cceed3ϩ+4d5 . 4c3e5dϩ312cce4dϩ3ϱeedd12cde5ϩ3ϱ24de4ϩ3ϱ3eedd+8ce5dϩϱ4+2de4ϱϩeedd =e6xxy4 4ce3d3ϩ5+24cceed3ϩ38d3eeϱ5ϩ +4c3e3d3ϩ34d3eeϩ54ced5ϩ3+20d5ϩ3+20ced5ϩ+6d5ϱ5ϩ +4ced5ϩ5+6 d5ϩ5+8c3de5ϩϱϱ+12ccde4ϩ28ce3d3ϩ +2c4e4dϩ+20d3eeϩ3 +48ce3d3ϩ3ϱϱ24cceed3ϩ 12c3d3e3ϩ . ce3ϩ3eedd +4d4ϱϩ3+3ceddϩϱϱeedd 4d4ϱ3ϩ =e4x3y ceedd5ddeeϱϩ3+3ddee +e4ϱϩ3 . +cce4ϩ3eedd +8ced4ϱϩ3 +3ccddeeϱ2ϩeedd 8ced4ϱ3ϩ 5d4ϱ4ϩeedd =e5x3yy cceeddϩ310ce3ddϱϩ3+10d4ϱϱϩ3+6ce3ddϱ3ϩ+3ddeeϱ4ϩ +ddeeϱ5+2ce5ϱϩ38ddeeϱϱϩ3 d4ϩ5+e4ϱϱϩ3 . [45]

<8r>

[46] ϱϱϩϩϱ2g2= { b4 . } a=r. c=2r. {illeg} y2r+xx2=ϩ . ϱ=x+y32 xxyy2xy3 {illeg} ϩ=ayac+xccaac . ϱ=yccaaaxc aaccy42aac3y3+2accxy3ccaa4aaccxxyy a4y42a4cy3+2a3xy3ccaa+4a4xxyy 2a3xy3ccaa+a4xxyy +4a3cxyyccaa+aac4yy +c4xxyy 2ac3xy2ccaaaaccxxyy +a4ccyy ϩϩ=aayy2aacy+aacc+ccxxaaxx +2ayxccaa2acxccaa 0 ϱϱ=ccy2aayy2axyccaa+aaxx 0 2aaxy+aacx axxccaa +ccxy+ayyccaa acyccaa aaccx4+4a3x3yccaa+6a4xxyy a4x42a3cx3ccaa6 aaccxxyy+6a3cxyy000+aaccy4 2accx3yccaa+4 aac3xxy4a3xy3000a4y4 6a4cxxy 2a3 ccxy000+2a4cy3 2aac3y3 +a4ccxx+2 accxy3000+aac4yy +c4xxyy2 ac3xyy000a4ccyy 3x44x3y32xxyy 2cx33+10cxxy+2cxyy3+3y4=0 +ccxx2ccxy6cy3 +4xy3+2ccyy g3y3 0 3x44x3y3+6cxxy+4xy33 2cx336xxyy2ccxy3 +4xxyy +4cxyy+2cxyy3 +ccxx +yy3xx3+2xy. +cxcy3 0 xxyy2axxy+aaxxaaxxa4=0 0 xxyy+4bxyy+4bbyy2axxy8abxy a48abby

[47] bc=x. cd=y. bf=c. bp=ϱ. pd=ϩ. bc=d. bg={illeg} fefgde . feegdf. bf hp={illeg} z. fg=exd . eg=fxd . pddhrs. dh=sϩr . rtpdph=tϩr. dedhdg=esϩdr. gh=fsϩdr fg=ϱ+tϩdr+fsϩdr=exd . drϱ+dtϩ+fsϩer=x . rfx+cdresϩdr=y . fdrϱ+dtfϩ+ffsϩ+cdereesx der =y= frϱ+tfϩdsϩ+cer er ec=c. bc=x. dc=y. pd=ϩ. pf=ϱ. fg=exd . eg=fxd . pg=sϩ r . gd=tϩ r . fg=ϱr+sϩr=exd . {illeg} x=drϱ+dsϩre. eg+ecgd=y=frϱ+fsϩ+recteϩre.

[48] fe=bc=x. cd=y. fp=ϱ. pd=ϩ. fefgdedhdg. feegdfhdhg. pddhrs. pdphrht drϱdtϩ+fsϩer=x. frϱftϩdsϩ+cerer=y. d=r . f=eedd . s=rrtt . s=ddtt . ddϱdtϩ+ϩeeddeett+ddttd4ed=x. dϱeeddtϩeedddϩddtt+ceded=y. Lastly dp=dt+eeddeett+ddttd4 . n=eedd . dq=teedd+dddtt . & Therefore x=dϱ+pϩe. & y=nϱqϩ+cee.

[49] bf=c. fa=z. fk=v. bc=x. cd=y. ap=ϱ. dp=ϩ. vv+zzvvϩϩvvϩϩvv+zz=pg2. devϩvv+zzevϩdvv+zz=po. ac=xzao=exezdde. exezdevϩdvv+zz=ϱ . dϱvv+zz .

[50] bf=c. af=z. bc=x. fc=xc=an. fk=v. {illeg} deanno=execd. oc=exec+dzd . ak=vv+zzzed=ϩzϩvv+zz=gd. vϩvv+zz=eg . go=evϩdvv+zz. exec+dzddzϩevϩdvv+zz=y

[51]

<8v>

fd=x. db=y. dc=v. ed{illeg} ab=z. vv+yyvvzzvvzzvv+yy=ed2. fe= {illeg} x {illeg} / y \ fe=xOvzyy+vv. ae=yOyzyy+vv. in ye 1st case.[52] fe=xOvzyy+vv. ae=yOyzyy+vv. in ye 2d {illeg}|c|ase.[53] fe=Ox+vzyy+vv. ae=y.

[54] Have{illeg}|in|g ye nature of a crooked line expressed in Algebr: termes to find its {illeg}|a|xes, to det{illeg}|e|rmin it & describe it Geometrically &c

[55] If fd=x. db=y. & y being pe{illeg}|r|pendicular to x describes ye crooked line ye crook ye line wth its one of its extremes. Then reduce ye Equation (expressing ye nature of ye line in wch x & y onely are undetermin{illeg}|ed|) to one side soe yt it be =0. Then Then {sic} find ye perpendicular bc {illeg} wch is done by findind|g| dc=v. for vv+yy=bc2 (In finding dc=v {illeg}  {sic}\obse{illeg}|r|v{illeg}|s| this rule./ Multiply {illeg} ye each terme of ye Equat: by so many units as x hath dimensions in yt terme, divide it by x & multiply it by y {illeg} for a Numerator. Againe multiply each terme of ye Equation by soe many units as y hath dimensions in each terme and divide by y f{illeg}|o|r a denom: in ye val{illeg}|o|r of v. [56] Example, rx+rxxq+yy=0. 1rx+2rxxq+0yyiny x =ry+2rxyq. 0rx+0rxxq+2yy y =2y. t{illeg}|h|erefore ry+2rxyq2y =v=+12rrxq. Also if x3bxx+yyxy3=0 +yxx . +3x32bxx+yyxiny +2yxx x 3y3+2yxx+yxx y 000= 00= 0003xxy2bxy+2xyy+y3000 003yy2yx+xx00 =v [57] And if x4yyxx+aayxy4=0 . then 4yx32y3x+aayy 4y3aax+2yxx =v . &c) Then make ab=z. fe=x+vzyy+vv. ae=yvzyy+vv. & substitute this valor of (fe) into ye place of x {illeg} & this valor of (ae) into ye place of y in ye Equation \& th{illeg}|e|r{illeg}|e| {illeg}|take| {{illeg}|in|} a 2d equation/. {illeg}|t|hen by multiplication or by some other meanes take a{illeg}|w|ay ye irrational quantity yy+vv & lastly take awa{y} y or x {illeg}|b|y ye helpe of these 2 Equations, soe yt you have a {illeg} \3rd/ equation in wch there is either x onely, or y onely & supposeing it to have 2 equall roots multiply each terme by {illeg}|soe| many units as {illeg}|ye| unknowne quanti{illeg}|t|y hath dimensions in yt terme {illeg} wch {illeg}|p|roduct is a 3rd equation it according to Huddenius his Method for a 3rd /4th\ Equation & by ye helpe of ye 3rd & 4th equation take away {illeg} ye in wch & there will result a 5t Equation in wch there b{illeg} one unknowne quantity viz: either x or y. & there will result a 5t Equation in wch is neither x nor nor {sic} y. & by wch the valor of z may be found. one \The greatest/ of whose valors signifies ye longest, another \the least {illeg}/ of ym ye shortest of all ye perpendicular lines ab. & if it have other rootes they signifie other lines (ab) wch are perpendicular to ye crooked line at both ends, a & b; & some of these must signifie ye axes of ye line if it bee of an elliptical nature.

<9r>

[58] ac=x. ch=y. bf={illeg} \z {illeg}/. fh={illeg} \{illeg} ϩ/ cd=a. dbbefhehbc. cxb=be. cϩb=eh. {illeg} ϩccbbb=fe=cxbzb. ϩccbb+bzc=x. ed{illeg}=xccbbb= ϩccϩbb+bzccbbbc hc= ϩbb+bzccbb+abcbc= acϩb+zccbbc=y.
||00 = ||00 ||00 = ||00 ||00 for ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 { x ||00 xx ||00 x3 ||00 x4 ||00 y ||00 yy ||00 y3 ||00 y4 ||00 xy ||00 xyy ||00 xy3 ||00 xxyy ||00 xxy ||00 x3y ||00 } ||00 = ||00 ||00 = ||00 ||00 write ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 ||00 = ||00 { +ϩccbbc ||00 2bϩzccbbcc ||00 ϩ3ccccbb c3 ϩ3bbccbb c3 + 3bbzzϩccbb c3 ||00 4ϩ3ccccbb×bz 4y3b3zccbb + 4ϩb3z3ccbb c4 ||00 ϩbc ||00 2ϩabc2ϩbzccbb cc ||00 ϩ3b33ϩbaacc3ϩbcczz +3ϩb3zz6ϩabczccbb ||00 4ϩ3b3ac4ϩ3b3zccbb4ϩa3bc312ϩaabcczccbb12ϩabb3zz+12ϩab3cz2 +ϩz3b3ϩz3bccccbb c4 ||00 acϩccbb+ϩzcc2ϩzbb cc ||00 4ϩabbcz3ϩbbzccbb+aaccϩ+zzccccbb+2ac3zϩ+b2ϩ3ccbb c3 ||00 3bbccϩ3z 4b4zϩ3 + 3abbcϩ3ccbb+z3c4ϩ+4z3b4ϩ5z3bbccϩ9abcc+3ac3zzϩccbb aabbcc+3aac4zϩ+a3c3ccbb c4 ||00 2ab3cϩ3 2abc3ϩ3 +4b32bcczϩ3ccbb +2bcc4b3z3ϩccbb+2aabbcczϩccbb+4abc3zzϩ6ab3czzϩ c4 ||00 b3ϩ3 bccϩ3 + 2bcczzϩ 3b3zzϩ +2abczccbb c3 ||00 4b4zϩ3 5bbcczϩ3 + c4zϩ3 +ac3abbcϩ3ccbb +3b cczzϩ 4b3zzϩ +3abczϩccbb c4 ||00

Haveing therefore an equation expressing ye nature of a{illeg} crooked line To find its axis. \Supposeing c= some quantity most frequent in ye equation/ Subroga{illeg}|t|e bz+ϩccbb c into ye roome of x ; & acϩb+zccbb c into ye roome of y: Order ye Equation according to {illeg} ϩ, make every terme =0 , in wch ϩ is of {illeg} \one/ dimensio{sic} Order every terme in the|i|se 2dary Equations according to ye dimensions of z. & supposeing every terme of each of ym =0 , by ye helpe of the{illeg}|s|e {illeg}|E|quations (in wch is neither x , y , z or ϩ ) may be found ye valors of a & b . Then perpendicular to ac from ye point a draw ab=a. & from ye point d | b | draw bk=b, & parallel to ac. from ye point k draw mk=ccbb , & perpendicular to bk . & through ye points b , {illeg} m {illeg} draw bl ye axis of ye line hgn . & yt ye relation twixt bf={illeg}z. & fh=ϩ may bee had, write ye valors of a , b , c now found in their stead in ye 2dary equation.

Example dd+dy+xyyy=0. Then makeing d=c I write bz+ϩccbb c , or bz+ϩddbb d for x & its square for xx &c. & adbϩ+zddbb d for y , & its square for yy. & soe I have this equation, 0=dd+adbϩ+zddbb +adbz2bbϩz bϩϩ +bzz +adϩ +2azd +2bϩz ddbb +ϩzdd aadd +2adbϩ bbϩϩ ddzz +bbzz dd or by ordering it according to ϩ , bbϩϩ+bϩϩddbb+ddbϩdaϩddbbd4 +2bbzϩ2bzϩddbb+abdz aadd ddz+ddzz 2abdbbzz +2adz0 bzz ddz ddbb =0 Then by makeing those quantitys in ye last terme save one {illeg} {illeg} =0 . I have this Equation 2bbz ddz 2bzddbb + ddb 2abd daddbb =0 . {illeg}|W|hich I divide into 2 pts makeing those termes =0 in wch z is not, & those =0 in wch z is of one dimension. & then I have these 2 equation{s} 2bbdd2bddbb=0 . & db2abaddbb=0 . by ye f{illeg}|irs|t 4b4 4bbdd + d4 =4bbdd 4b4 . Or 8b4 8bbdd + d4 =0. That is bb=dd2Od48=dd2Odd22=dd2Odd22. by ye 2d Equation I find ddbb4adbb+4aabb=aaddaabb . or 5aabbaadd=0 4adbb +ddbb . & by writing ye valor of dd wch was found before I have 5aadd2O5aadd4ad32O4ad3+d32Od42aadd2 22 =0. Or 3aa24ad2+dd2=0 O5aaO4adOdd . Or aa= 4ad2O4addd2Odd 32O5 . & a=d8O2d18O5 O 8ddO4dd8+4dd5dd dd36O5dd2Odd18 18O518+25 a= d8O2d 18O5 O+ dd 18O518+25 or 2d22d 325 O+ dd 43152 =a . & dd2Odd 22 =bb. a= 2d2O2dOd 32O5

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[59] ddϱ2+2dsϱϩ+ssϩϩ ee =xx. d3ϱ3 + 3ddϱϱsϩ + 3dϱϱsϩϩ + s3ϩ3 =e3x3 . |{d }. a+y| d4ϱ4 + 4d3ϱ3sϩ + 6ddϱϱssϩϩ + 4dϱs3ϩ3 + s4ϩ4 =e4x4. d5ϱ5 + 5d4ϱ4sϩ + 10d3ϱ3ssϩϩ + 10dds3ϱϱϩ3 + 5dϱs4ϩ4 + s5ϩ4 =e4x5 ttϱϱ2tϱvϩ+vvϩϩ=yy +2tϱce2cevϩ +ccee . t3ϱ3 3ttϱϱvϩ + 3tϱvvϩϩ v3ϩ3 =e3y3 +3ttϱϱce6tϱce+3ce +3tϱccee3ccee +c3e3 . t4ϱ4 4t3ϱ3vϩ + 6ttϱϱvvϩϩ 4tϱv3ϩ3 + v4ϩ4 =e4y4 +4t3ϱ3ce 12ttϱϱce + 12tϱce 4ce + 6ttϱϱccee 12tϱccee + 6ccee +4tϱc3e3 4c3e3 +c4e4 . t5ϱ5 5t4ϱ4vϩ + 10t3ϱ3vvϩϩ 10ttϱϱv3ϩ3 + 5tϱv4ϩ4 v5ϩ5 =e5y5 +5t4ϱ4ce 20t3ϱ3ce + 30ttϱϱce 20tϱce + 5ce + 10t3ϱ3ccee 30ttϱϱccee + 30tϱccee +10ttϱϱc3e3 20tϱc3e3 +10c3e3 +5tϱc4e4 5c4e4 + c5e5

[60] bc=x . dc=y . df=z . bh=c . hkkede . ke=exd. dfdedf . fzd=de . cd+exfzd=y. fm=ϱ . mh=dϱe . mk=xedϱe . pe=xedϱd= p=n . fp=ϩ2nn. ep= eϩ2nn+dn d =exd eeϩϩ= eenn+ddnn2dnex+eexx . fdfp {illeg}fg. ϩgf=fp . fϱ+ϩg f =x . fppede. eϩgdf={illeg}. pd=ϩffggf fm=eϱd. hm=ϱ. eϱ+cddϩffggf=y. f=d. &c dϱ+gϩd=x. eϱ+cdϩffggd=y.

[61] If any crooked line be revolved about its \owne/ {illeg}|a|xis it generates a Sollid intersected by any plaine \not perpendicular to ye axis/ produceth another line { not more compoundyn of the same kind with ye forme{illeg}|r|. But if it bee revolved by any other line it generates a Sollid which intersected by any plaine \not perpendicular to ye axis/ produceth another whose composition is {n}ot { lesseynequall moreyndouble } to ye formere

Figure In the △ adb if ab=a, & db=b are definite, but ad=v, & bc=x indefined. Then ye Equation is bbvv+aa2ax=0. But in this case ye maximu or minimum of either v or x cannot bee found according {illeg}|t|o Cartes or Hudde{nius} method, by reason yt {vx} hath not 2 divers valors when {xv} is determined, wch become equall when {xv} is ye least or greatest yt may be. But if cd might heve {sic} bee used inste{ad} of cb &c. There be other instances of this Nature against Huddenius h{illeg}|i|s assertion.

Figure These points a/,\b/,\c/,\ being given {illeg}|a| circle may {illeg}|b|e described (wch shall pass through a point them all) by an instrument whose angle edf=abc. And soe ye sides ed & df being moved close by ye points a & c, ye point (d) shall describe ye a{illeg}|r|ch abc

To w{illeg}|o|rke mechanic{illeg}|a|lly & exactly b{illeg}|y| a {{illeg}|s|cal{illeg}|e|} it may be{illeg}|e| better divided according to ye fassion {illeg} {illeg}|r|epresented by ye figure A, yn by that at B.

To {illeg}|m|ake a {plated} superficies exactly: Take three plates A, B, D. Figure & {g{illeg}|r|ind} them together A & B, A & D, B & D; pressing ye uppermost pla{illeg}|t|e onely in the middle at {illeg}|c| that it may not weare {move} a{illeg}|w|ay in the edges yn in the midst & move it to & fro wth but sma{illeg}|ll| vibrations. Soe shall the 3 {illeg}|f|iduciall sides of ye 3 plates bee {ground} exactly plane.

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[62] Probleme. Of Usury. ab=a= the princi{illeg}|p|le. bc{illeg}={illeg}x= the time of the m{illeg}|o|ney lent ce=dxe= the use due for ye principle {illeg}|fo|r ye time bc. de= the use upon {illeg}|u|se. {illeg} cd ye cd=y= ye use{illeg} for ye principle & use during ye time bc. axdxea+yinfcy. ab ye sume of princi df a t{illeg}|a|ngent to ye line bd. dg a perpendicular. cg=v. Then as ye sume (ab) or principle drawne into ye time bc, is to (ce) ye use for it in yt time [63] So is ab+dc the sume ab+dc drawne into ye time fc, to ye use (dc) for it in ye time fc. {illeg} therefore axdxe a+yin{hfcy {illeg}. axy=ahdx+yhdxe. eayad+yd=hy{illeg}yv. eav=ady+dyy. v=ady+dyyea. d=e. ay+yya=v

Of Reflect{illeg}|i|ons.

Figure Suppoe {sic} yt {illeg}|t|he bodys a, b, have noe vis elastica to reflect ye one from ye other but at their occursion conjoine & keepe together as i{illeg}|f| they were one body. Then 1st if Theire bulke \& motion/ be equall yn at theire {illeg} meeteing they shall rest. 2 If (b) have more motion yn (a) all {illeg} ye motion of (a) shall be lost & soe much of (b)s as (a) had & they shall both move towards c shareing ye differencde of ye motion \proportionally/ twixt ym. Demon: {illeg}|S|uppose ye motion of ehf= motion of a
2 If a rest & b hit it they shall both move towards c wth {illeg} shareing ye motion \of (b)/ twixt them.

[64] Of Reflection.

Figure Suppose ye Bodys a, b doe not reflect one another b{illeg}ut conjoyne either moveing or resting together of at theire meeting & soe move or rest to{illeg}|g|ether. a= ye body a; b= ye body fec; c= body ced; d= body fedc. m= motion of a, n= motion of b, p= motion of c, q= motion of d=n+p, before reflection. e= motion of a, f= motion of b, g= moti {sic} of c, h= motion of d {illeg}|a|fter reflection. r= swiftnesse of a, s= motion of b, c, or d, before reflection t= swift{illeg}nesse of a, v= swiftnes b, c, or d ref occursion. ⊙ ye point of theire occursion.

Axiome 1st

[65] Two bodys \bc/ being alike swift {illeg} ye motion of bmot: cbc. for equall pts have equall motion. Therefore bcall ye parts of ball such pts of cmot: bthe motion of c.

Prop: 1st. If before ye occursion \of a & d/ a rest yn shall eqa{illeg} e+h=q. & since t=v, tis {alsoe} eqaa+d. Or e=aqa+d also h=qaqa+d=dqa+d.

Prop: 2d. If a meete d, & have lesse motion yn it, then, qm=e+h. for suppo{illeg}|s|e, m=n. yn should {illeg}|a| & b rest after occursion did not p=qm {illeg} force ym towards k.

Prop 3 suppose i ye center of gravity in d, y in a. z & f ye in wch ye bodys a & d touch in theire meeting. ⊙ ye point of theire meeting. a ye magnitude of \ye body/ a, d ye magnitude of d. m= motion of a before meeting, n= mot: {illeg}|d| before me{illeg}|et|ing. ye time in wch a or d Figure moves to = time in wch they both move to y. p= motion of a, {illeg} q= moti{illeg}|o|n of d after occursion{illeg} m+n=p+q. adpq. or a+ddm+n=p+qq=qm+qn dm+dna+d. am+ana+d=p. mpz⊙zy. am×z⊙+an×z⊙ am+dm=⊙y.

Figure a= magnitude of ye body a, d= mag: of ye body d. {illeg} o= {illeg} ye point of concourse: zf= ye points of contac{illeg}|t|, at o. zo={illeg}|b|. fo=c. op=e. t= time in wch ye bodys move from z & f to o. v= time in wch they move from o to p. m= motion of a before occursion n= motion of d after occursion dm{illeg}{illeg}=dn+ana or cdm+bam=bdn+ban. {illeg}|&| cdm+bambd+ba=n{illeg}mn. tmvn{illeg}betbd+tbavcd+vba. {illeg}cd{illeg} v=det+aetcd+ab. Figure. {illeg}{illeg}{&} d {illeg} meete {illeg} {illeg} yt c must be negative yt is abv0nt{illeg}e be negative ye point {illeg} must be t{illeg}on ye same side {illeg}

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Definitions.

[66] {illeg} \1st/ When a body \{illeg}|Q|uan{illeg}|ti|ty/ {is translatedpasseth} from one pte of Extension to another it is saide to mo{ve.}

2 One body \Quantity/ is soe much swifter yn another, as ye distance th{illeg}|r|ough w{illeg}|c|h it passeth is greater yn ye distance through wch ye other passeth in ye same time.

One body /quantity\ {illeg}|h|ath soe much more motion yn another, as ye summe of ye spaces th{illeg}|r|ough wch each of its pts moveth i{illeg}|s| to ye summe of ye spaces through which each of ye pts of ye other \quantity/ body moveth supp in ye same time, suppi|o|seing each of the{illeg} pts in both bodys /Quantitys\ to be equall & alike to one another \& moved in ye same position./ {illeg}.

3 One Quantity hath so much more motion yn another, as ye distance through wch it moveth drawne into {illeg}|it|s quantity, is to ye distance {illeg}|t|rough wch ye other moveth in ye same time d{illeg}|raw|ne into its quantity. As if ye line ab move ye length of bc Figure & ef ye length of eh in ye same time, ye motion of ab is to ye motion of cd, as ab×bc=abcd, to ef×eh=iehk. Figure Alsoe if \ye cube/ lmqyz=8 move ye length of op=5; & the piramis tvwx=7 move ye length of rs=3 in ye same tim{illeg}|e|; y{illeg}|n|, as, op×lmqyzrs×tvwx4021 ye motion {illeg}|of| lmqyz to ye motion tvwx. Or th{illeg}|e| motio{illeg}|n| of one quantity to another is a{illeg}|s| their powers to /persever in that state\

Those bodys \Qua{illeg}|n|titys/ are said to have ye same determination of their motion wch move ye same way, {illeg}|&| those have divers wch move divers ways.

[67] 5 A body /quantity\ is reflected when meeting wth another quantity it looseth ye determination of its motion by rebounding from i{illeg}|t|. As if ye bodys a, b meete one A quantity is said to bee refracted another in ye point c they are parted Figure either by some springing motion in y selves or of \in/ ye matter {crouded} bet{illeg}|w|ixt ym. & as {illeg} ye spring is more dull or {illeg}ety \{illeg}|vi|gor{illeg}|ous|/ /quick\ s{illeg}|o|e ye bodys {illeg}|w|ill bee reflected wth wth more \or lesse/ force; a{illeg}|s| if it endeavour to get liberty \to inlarge it selfe/ wth as greate strength & vigor as ye bodys ab , pressed it together, ye ye {sic} motion of ye body{illeg} a from b will bee as greate after as before y{illeg}|e| reflection. but if ye spring have but halfe yt vigor, yn ye distance twixt a & b,|at| {illeg}|t|he minute after ye reflection shall bee halfe as much as it was befor at ye minute beef{ore} ye reflecti{illeg}on.

Figure 7 Refraction is when {illeg} ye body \{illeg}/ c passing \obliquely/ through ye surface ed at ye point b meets wth more or lesse oppo{illeg}|s|i{illeg}|t|ion on one side of ye surface yn on ye other & soe looseth its determinacon; as if it turne towards a.

[68] 9 Force ii|s| ye pressure or erouding of one body {illeg} upon an{illeg}|o|ther,

10 The center of Gravity \{ Motion }/ \in ye same body/ is such a point wthin a quantity \{illeg}wch rests when a body is moved wth \any/lar but noe progres\sive motion//; yt if it \be considered to as at a/ rest & ye quantity & some quantity line as mn be drawne through it: about wch (as \about/ an axis) ye f{illeg} quantity dklp revolving. {illeg}|t|here shall bee ye same quantity of motion on both sides any {illeg}|p|laine {illeg}|w|th wch mn is coincident; also ye line in n \drawne throug{illeg}|h| it/ is called an axis of gravity \motion/.

The center of motion in \2/ divers bodys is {illeg}|a| point soe placed {illeg}|t|wixt those bodys yt (if it bee conceived to rest {&}) if {illeg} the bodys bee moved about it {illeg} wth circular motion they shall both have an equall quantity {o}f motion, the line about wch they move is ye axis of motion.

12 A Body is said to move toward another body either when all its pts move towar{d}s it or else {illeg}|w|hen some of its pts have more motion towards it y{illeg}|n| others have from it. Otherwise /not\

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13 Bodys are more or lesse distant as ye distances of {illeg} their pts \centres of motion/ are more or lesse. or as their distances might bee acquired wth more or less motion

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Axiomes. & Propositions.

1 If a quantity once move it will never res{illeg}|t| unlesse hindered by some externall caus{e.}

2 A quantity will always move on in ye same streight line (not changing ye determination \{nor} celerity/ of its motion) unlesse some externall cause divert it.

3 There is exactly required so much \& noe more/ force to reduce a body to rest {illeg} /as\ there {illeg} was {to} put it {illeg}n motion: et e contra.

4 S{illeg} much {illeg}{illeg}s is required to d{illeg}p{illeg}e {illeg}|d|estroy any quantity of motion in a body soe {illeg} to generate it; & soe much as is required to generate it soe mu{illeg}ived to destroy it.

[69]6 {illeg}ove 2 unequall bodys \(a & b)/ ye swiftness{illeg}|e| of {illeg} \on{illeg}e/ body a is to ye s{illeg} is to a . {(1)} & therefore ye motion of both bodys shall bee equall.

5 If {illeg}{b}ee moved by unequall forces, as ye force moveing b is to ye force {illeg} motion {illeg}|o|f b. to ye m{illeg} of c, so is ye swiftnes of b, to yt of c.

[70]7 If two body {illeg}{illeg} \{illeg}way to{illeg}s {illeg}{illeg}r{illeg}cking {illeg}/ {illeg}e of theire motion shall be lost. f{illeg} pres{illeg}{illeg}{illeg}{illeg} ye motion of b shall {illeg}{illeg}

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[71] 8 If two quantitys (a & b) move d{illeg} towards one another & meete in {illeg} o, Then ye difference of theire motion shall not bee lost nor {illeg}|l|oose its determinacon. For at their occursion they presse equally uppon one another, & (p)[72] therefore one must loose noe more motion yn ye other doth; soe yt ye difference of their motions cannot be destroyed.

9. If one body a overtake ano{illeg}|t|her body b they both moveing towards o then they shall always move together. v
If ye body c move against an imm{illeg}|o|veable quanty {sic} d it shall not bee rebounded for c having urged d wth

[73] 9 If the body t{illeg}|w|o \equall & equally swift/ bodys (d & {illeg}|c|) meete one another they shall bee reflected, s{illeg}|o|e as to move as swiftly frome {illeg}|o|ne another a{illeg}|f|ter yr reflection as they did to one another before i{illeg}|t|. For {illeg}ng For firs{illeg}|t| suppose ye {illeg}|sphæricall| bodys ef to have a springing or elastic{illeg}|k| for{illeg}|c|e soe yt {illeg}|m|eeting one another they will relent & be pressed into a sphæri|o|idicall figure, {illeg}|{&}| in yt moment in wch there is a period put to the{illeg}|ir|e motion towards one another theire figure will be most sphæroidicall & theire pression one upon the other |i|s at ye greatest, & if th{illeg}|{e}| bodys endeavour to restore theire \call/ figure w{illeg}h \bee/ as much vigor|ous| & force|i||ble| as it was destroyed by, & as theire pressure upon one another wa{illeg}|s| to destroy it they will gaine theire whole /as much\ motion from one another \thei{illeg}|r| {illeg}|p|arting/ as their|y| \had/ towards one another {illeg} theire reflection. Secondly suppose they be sphæricall & absolute\ly/ sollid then at the period of theire motion towards one another (yt is at ye moment of theire meeting) theire pression is at ye greatest or rather tis \done with/ the whole for{illeg}|c|e by wch theire motion is stopt, \for theire whole motion was stoped b{illeg}|y| ye force of theire pressure upon one another in ysone mome\nt// for /&\ there cannot beesucceede divers degrees of pressure twixt two bodys in one moment) Now i{illeg}|f| /so long as\ neither of these 2 bodys yeild to one another they will {illeg} always retaine ye same forcible pressure towards one another: that is soe much force as deprived ye bodys {illeg} of th{illeg}|ei|r motion (when it moved towards h \towards one another soe much/ doth now {illeg} it towards g, & therefore (r) y{illeg} urge them from one ano{illeg}|t|her, & therefore (r)[74] they shall move from one another as much as they did towards one another before theire reflection.

10. There is {illeg}|y|e same reason wh{illeg}|e|n unequall & unequally moved \bodys/ reflect, yt they should sepera{illeg}|t|e from{illeg} one another wth as much m{illeg}|{ot}|ion as they they came together.

[75] [76] 11. If a line \df/ bee moved not wth a Circular \Progressive/ but onely a Circular motion i{illeg}|t|s middle point \n/ shall rest. For if it move let it move towards r soe yt, when ye point d is moved in p & f in q, then n shall be moved to s :

Figure 11 If {illeg}|a| line ce be bisected in a about wch ye line ce doth circulate {illeg}|&| yt point bee fixed. yn ye whole line hath noe progressive motion. For makeing ab=ad, bf, ag, & dh bee parallel, & perpendic to fh, yn is vb=dp. & vf+ph=bf+dh=2ag. Wherefore ye point c moveing to{illeg}|w|ards n ye point {illeg}|d| shall move soe much towards ye line fh as ye point b doth from it, & all ye points in {illeg} ac or ye line ac move as mue|c|h from to ye line fh as \all/ ye points in ae or ye line ae moves from it soe yt ye whole line ce stays in equilibrio neither moveing to nor from fh, by ye 12th Defin{illeg}|.|

12 H{illeg}|e|nce when \ye center of a line/ a is not in ye center \midst/ of a line me ye whole line moves ye same way wch ye longest pte doth. for supposeing ca=ae y{illeg}|n| ye line ce in equilibrio ( ax:1{illeg}|1|) but if mc moves towards fh & be added to ce yn me moves towards ce (by def {12}

13. When ce moves circularly but maketh noe progression it{illeg}|s| midle {sic} point shall rest & is therefore ye center of its motion, for if ye middle point move ye whole line let it bee to r from a soe yt ye line ec bee moved into ye place {wt} yn let ye {wt} move about ye fixed center r into ye place xs, yn {xs} & {wt} are equally distant from fh (by def: 13 & ax: 11) & alsoe ln & ce are equally distant from ye {illeg}{am} f{illeg} but xs is further from fh yn ln there & ln are not equally distant from f{illeg}{illeg}ore neither are wt & ce {illeg}|e|qually distant f{illeg}|r|om fh. & therefore ye line {illeg} pro{gre}ssive motion when it {pressed} into {wt}

14 By ye same reason ye midle {sic} point {illeg}ogram, parallelipipedon, prisme cilinder, circle, sphære, {illeg}|e|lip{illeg}|s|is, sphæroides {illeg} of theire motion

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[77] 15 A Body moves yt way \hath ye same determinacon of its motion/ wch the center of its motion hath. As if ye line ac move into ye place gh, ye center of its motio{illeg}|n| b moveing into ye place d. th{illeg}|e|n let gh move about ye center d untitill {sic} it be parallel to ac, as into ef \soe yt ye point a fall into ye {illeg}|p|oint e/. Now since {illeg} gh by turning about ye center d hath noe progressive motion (by Def: 10) tis plaine yt gh & ef {illeg} have determinacon from ac but ef hath ye same determic|n|acon from ec wch d hath from {illeg}|b| (for if ac be understood to move parallell to its selfe into ye place ef, all its points describe parallel lines & therefore have ye s{illeg}|a|me deter{illeg}|m|inacon one wth another & each with ye whole body (by axiom 14.) therefore gh hath ye same determinacon from ac wch ye point d hath from ye point b

14 A Body being moved parallell to its selfe all it{illeg}|s| points describe ∥ lines, \& each{illeg} y have ye same determ \& velocity/ wth ye body./ for (by axiome 2d) they {illeg}|m|ust {illeg}|a|ll bee streight ones wch if they intersect ye body will not be \moved/to its selfe.      &c.

16 If a body move forward \& circularly/ its center of motion shall allways bee in ye same streight line. For ye body hath allways ye same determinacon (ax 2d) & ye cent' of its motion hath ye same determinacon wth ye body (ax 15) therefore it hath always ye same determinacon, & soe will move continually in ye same streight line.

[78] 17 If a body move \streight/ forward & circularly its cente{illeg}|r| of motion shall have ye same determinacon & velocity yt {illeg}have had did ye body move Pa∥ll to it selfe \the body hath/. For {suppose} ac wh to be moved into ye place gh & its center of motion b into ye place d, yn let it turne about ye center d into ye place ef ∥ to ac s{illeg}|o|e yt ye point wch was in a bee now in e. N{illeg}|o|w since {gf} by moveing into ye place fe makes noe progressiv motion (def: 10) it follows yt {illeg}parallell to it selfe into ye place ef it would {illeg} ye same determinon {sic} & quantity of motion ye same quantity \(Or since gh=ef=ac) ye same velocity/ & \(axiom 10)/ determinacon of motion \in ye same time/ would translate ac parallell to it selfe into ye place ef yt w{illeg}ld {sic} translate it into ye pla{illeg}|ce| gh , had it bo{illeg}|t|h progressive & circular motion. But ye point d {illeg} hath ye f|s|ame velocity & determinacon wch ye line ef hath when moved ∥ to its selfe (x)[79] therefore ye point d hath ye same determinacon & velocity wch ye line gh hath when moved wth both ◯lar & progressive motion \vide ax 37/.

18 If a body move progressively in some crooked line & alsoe circularly {illeg} its center of motion shall have ye same determinacon & velocity wch ye body {hath} for in {illeg} {illeg} any point of ye crooked line its determinaco {sic} is in ye tangent \(ax 17) th{illeg}|i|s is trew when its {illeg}|m|otion is in a strei{illeg}|gh|t lin{illeg}|e| but a crooked line may/ bee conceived to consist of an infinite number of streight lin{illeg}es. Or else in any p{illeg}|oi|nt of ye croked {sic} line ye motion may bee conceived to be on in ye tangent.

[80] 19 {sic} 2 bodys circu make ye same number of circulations wth ye same dista{nce} from ye center c : yn as ye Radij of ye circles wch they|ir| \centers of motion/ {illeg}|de|scribe are to one another soe are ye perimeters one to another soe are theire velocitys one to another (ax: 10, def: 2), & their motions are to {illeg}|o|ne another as theire bulkes drawne into ye Radij of those circle {sic} (wch theire centers of motion describe) are to one another (def 3). As: ec=eo velocity of eb velocity of ac. & eb×ecao×co mot eb mot of ao.

[81] 20 If a s{illeg}|ph|ære ⊙c move wth in \be compelled by/ /move wth in\ {illeg}|y|e concave sphæcall {sic} or cilindricall surface of ye body edf to move circularly abou{illeg}|t| ye center m it shall press upon ye body def for when it is in c (suposeing ye bhc to be described by it {sic} center of motion {illeg} & ye line cg a tangent to yt at ⊙) it moves it moves towards g or ye determination of its motion is towards c      therefore if at yt moment ye body edf should cease to check it it would continually move in ye {illeg}|l|ine cg (ax 1. 2.) obliq{illeg}|l|y from ye center m , but if ye body def oppose it selfe to this indeavour in ever keeping it equidistant from m , that is done by a continued \checki{illeg}|n|g or/ reflection of it from ye tangent line in every point of ye ◯ chb , but ye body edf cannot check & curbe ye determinacon of ye body c⊙ unless they continually presse upon one another. |The same may {illeg}|b|e understood if ye body adb bee restrained into ◯lar motion by ye thred om |

21. Hence it appear{illeg}|e|s yt all {illeg}|b|odys moved ◯larly have an endeavour from ye {illeg}|c|enter abot|u|t wch they move, otherwise ye b{illeg}|o|dy ⊙c would not continually presse upon edf .

2{illeg}|2| The whole force by wch a body c⊙ indevours from ye center {illeg}| m | in halfe a revolution {i}s \more yn/ double to the force wch is able to generate or destroy its motion for supposeing it have moved from c by h to b then i|y|e resistance of ye body ef {illeg} (wch |is| equall to its pressure upon def ) is able to destroy its force of moveing {illeg}{illeg} & to generate in it as much force of moveing from b to h the qu{illeg}g {illeg}|w|ay.

[82] 2{{illeg}|5|}{{illeg}|3|} {illeg}|H|aving {illeg}of motion of ye 2 bodys ob & dc to find ye common center of both {in}{illeg}draw a line ⊙e from the centers of theire motions ⊙ & e & divi{illeg}oe yt {illeg}|th|e body ob is to ye body de as the line ae t{illeg}|o| ye line oa : yt is soe{illeg} ae×de . For th{illeg}|e|n if they move about ye center {illeg}{illeg}{illeg} they have equall motion (ax 19th) & consequen{tly} {illeg} <12r> have an equall endeavour from ye center a (ax 24|3|) soe yt if they bee joyned tig{illeg}th by the line to center a by ye lines {illeg} ae & ao they shall not mo {illeg}|t|he one h{illeg}|i|ndereth ye other from forcing ye center a any way soe yt it shall stand in equilibrio betwixt them & (by def 10) is therefore their center of \motion/

[83] 24 If two bodys ( cb & de ) move about a center a yn as ye motion o makeing bc=a, de=b, ac=c, ae=d, ye time in wch bc makes halfe a revolution call e, yt in wch de doth ye sam{illeg}|e| call f , ye pressure of cb from ye center a in halfe a revolution call q , {illeg}|&| yt of de call h ; ye motion of cb in halfe a revoluco k & yt of de call l . yn kl

24 If two bodys ( cb & de move about a center a yn ∼ ∼ ∼ ∼ ∼ ∼ The \whole/ force by wch ye body cb tends from ye center a \in one revolutio {sic}/ being equall to {{illeg}|6|}{{illeg}|61|} times ye force by wch y{illeg}|t| body is moved \(ax 22)/ is to ye motion of yt body {illeg} one revolucon as ye \whole/ force by wch ye body de tends from ye center a in one revolution (wch is equall to {illeg}|6|{+} times ye force by wch ye de is moved, or wch is able to stop i{illeg}|t|s motion (ax 22) ) {illeg}|is| to ye motion of ye body de . Vide Axioma 23ũ.

[84] {illeg}|2|6 If y{illeg}|e| body a move through ye space ab \=b/ in ye time d \=be/, & ye body c {illeg}|thr|ough ye space cd |=e| in ye time f . then ye velocity of a is to ye velocity of {illeg} c as ab×dc to cd× {illeg} be . for supposeing cb=gp then ye velocity of a is to ye velocity of c as ab to cp (def 2d) or as ab×gpcp×ebab×cdad×eb . for since \Then is/ cp×fd=cd×gp=cd×eb . Or {illeg} cp×fd×ab×{ebgp=cd×eb×ab×gp yt is ab×gpcp×ebab×fdcd×ebabcp velocity of a velocity of c velocity of a to ye velocity of cabcp{illeg} For supposeing yt gp=eb. yn is cp=eb×cdfd And (by def: 2) ye velocity of a is to ye velocity of cabcpabeb×cdfdab×fdeb×cd

[85] Alsoe ye motion of a is to ye motion of c (by def 3d) a×abc×cpa×ab\c×c/ a×abc×cpa×abc×eb×cdfda×ab×fdc×eb×cda×its velocityc×its velocity.

Note yt when ye motion is uniforme yt is when a body moves over ye same sp{illeg}|a|ce in ye same time (wch will ever bee when ye motion of {illeg}|y|t body is neit{illeg}|h|er helped nor hindred) yn in a right angled triangle a b may designe ye space through a body moveth {illeg} in ye ti{illeg}|m|e eb. Otherwise when tis not uniforme ye proportion of ye time in wch a body moves to ye {illeg} distance through wch it moves may be designed by lines drawne to a crooked line, as ye time by gf ye dis & ih , ye distance by gh or fi , ye velocity by ye proportion of nh to hi , ni being tangent to ye crooked line at i . &c.

[86] 23 If 2 bodys be moved wth equall or uneq
If ye body bace is moved \acquire ye motion q / by ye force {illeg}| d | {illeg}|&| ye body f \ye motion p/ {illeg}|b|y ye force g . yn {illeg} dqgp. for suppose ye body rscb=f , yn ({illeg} {illeg}) to {illeg} acquire ye motion w by ye force d , yn (ax: 5)[87] dgwp . but q=w (by ax: 4) therefore dgqp.

Ax: {illeg}|{1}|00 Every thing doth naturall{illeg}|y| persevere in yt state in wch i{illeg}|t| is unlesse it bee interrupted by some externall cause, hence axiome 1st, & 2d, & {γ}, A body once moved will always keepe ye same cele{illeg}|r|ity, quantity & determinacon of its motion.

[88] If 2 equall bodys (bcqp & r) meete one another wth equall motion \celerity/ (unlesse they could pass through one ye other by penera|tr|acon of dimensions) they must mutually hinder their perseverance {illeg} in their{illeg} states, & (since ye one hath no{illeg}|e| advantage more yn /over\ ye other they must) equally hinder ye one ye o{illeg}|t|hers haveing both of them an equall power to persever in theire state |celerity power to persevering in its state| |perseverance in its state| likewise if ye body aocb be = & equivelox wth r they have a like power of persevering &{illeg} |{illeg}ing {illeg} equally {illeg}|hin|der or op{illeg}|p|ose ye one yt {offers} progression or perseverance in their states| therefore ye power of ye body aopq (wh{illeg}|e|n tis equivelox wth r) is double to ye power yt r hath to persever i{illeg}|n| its state. yt is ye e{illeg}|ff|ic{illeg}|a|cy force or power \of ye cause/ wch can reduce aopq to rest must bee double to ye power & efficacy of ye cause wch can reduce r to rest, or ye power wch ca{illeg}|n| move ye one must {illeg}|b|e double to ye power wch can move ye other soe yt they bee made equivelox.

Hence in equivelox bodys ye powers of persevering in their states are proportionall to their quantitys.

101 Hence may bee perceived what is meant. Supposeing ye bodys aobc & cbqp to be equall & equivelox: Then {illeg}|t|hat cause \hindrence, impedimnt resist{ance}/ or opposi{illeg}|ti|on wch can \onely/ deprive cbqp of its \whole velocity &/ motion by hindering its p{er}severance can {illeg}|a|l{illeg}|s|o \onely/ deprive aocb of its \whole {whole velocity &}/ moti{illeg}|o|n {illeg} yt cau{illeg}|s| hath ye same {illeg}{illeg} over both ye bodys. Now if {illeg} add ye opposition a wch can \{being} {illeg}ive of its {illeg}/ {illeg}|r|educe cbpq to {illeg}{illeg}ion b wch can reduce aob {illeg} \{illeg}/ ye whole opposition ( a+b=2a=2b ) {illeg} \{illeg}/ both {illeg} bodys aobc+bcpq=aopq ) {illeg} \{illeg}/ motion when they are joyned into one aopq for acbpqbaobca+bcbpq+aobc2aaopq Also neither {illeg} a or b {illeg} aopq of {illeg} motion for {illeg} <12v> pte ( a or b ) would be equall to ye whole (a+b=2a=2b ). By ye same r{illeg}|e|ason | aopq {illeg}|&| cbqp loosing equall velocity ye resistance /impediment\ of aopq must be double to ye opposition of cbpq .|

[89] 102 By they {sic} same reason yt \Since/ beacuse aopq {illeg} is double to cbpq & both of ym equivelo{x} therfore ye opposition wch can deprive aopq of its motion must be double to yt wch can deprive cbpq of its motion; by ye same reason it will follow yt in equivelox bodys as one body{illeg} \ a / {illeg}|i|s to another \ b / {illeg}|s|oe must ye resistance wch can deprive yt body a of its {velocitymotion bee to ye resistance wch can deprive b of its whole {velocitymotion so is ye resistance wch can deprive a of some pte of its velocity, to ye restance {sic} wch can deprive b of ye same quantity of velocity, soe yt a & b bee still equivelox.

Now {illeg}|i|t may be perceived how & why {illeg} amongst bodys moved some require a greater dome a lesse opposition to deprive ym of theire whole velocity or of some pt{e} of it wch {illeg}p

103 By ye same reason alsoe If two bodys rest or bee {illeg}|e|quivelox: yn as ye body a is to ye body b soe must ye power orf efficacy \vigor strength/ or virtue of ye cause wch begets new velocity in a {illeg}|b|ee to ye power virtue or efficacy of ye cause wch begets ye = same quantity of velocity in b , soe yt a & b {illeg} bee still equivelox.

104 Hence it appeares how & why amongst bodys moved som{illeg}|e| require a more potent or efficacious cause others {a lesse} to hinder or helpe their velocity. And ye power of this cause is usually called force. And as this cause \useth or/ apply|eth| its power or force to hinder {illeg} or helpe \or change/ ye {illeg}g perseverance of bodys in theire state, it is said to Indeavour {illeg}|t|o change their {illeg} perseverance.

[90] 105 If ye equall & equivelox bodys a & b meete (unlesse they could passe yt one through ye other by penetra{illeg}|t|ing its dimen{illeg}|tio|ns) they must necessarily hinder ye one ye others progression, & since these bodys have noe advantage ye one over ye other ye hindrance on both pts will be equall, likewise if ye bodys d+a & b+c bee equall & equivelox they must equally hinder one anothers progression in its s{illeg}|t|ate But ye body b (being lesse yn ye body b+c ) & equivelox wth d+a ) canot equally hinder ye progression of ye body d+a soe much as ye body b+c ca{illeg}|n|; for {yn} the power of b being part of ye power of ye body b+c would bee equall to ye {illeg} {illeg}|w|hole power of b+c therefore yt b+c & d+a being equivelox d{illeg}|o|e equally hinder ye one ye others progression tis required yt they be equall.

[91] 106 Now if ye {illeg} bodys a & b meete one another ye cause wch hindereth ye progression of a is ye power wch b hath to persever in its state velocity \or state/ & is usually called ye force of ye body b & {illeg}|i|s this power or force are said to |soe yt a body is {so} to be moved wth more or lesse force wch meeting wth another body can cause a greater or lesse mutation in its state, or wch requireth more or l{illeg}|e|ss for{illeg}|e| {sic} to destroy its motion.| & as {one} body b useth or applyeth this force to stop ye progression of a it is said to {illeg} Indeavour ty|o|e hinder ye {illeg} progression of a \wch indeavour in body is performed by pressure/ & by ye same reason ye body b may {illeg}|b|ee said to endeavor to helpe ye motion of a if it should apply its force to move it forward: soe yt it is e{illeg}|v|ident wt ye Force & indeavor of \i{illeg}|n|/ bodys are.

[92] 107 If ye bodys b & c be equiv{illeg}|e|lox yn as {illeg} bc ye force of \wth wch/ b \is moved/ (or ye power of b to persever in its velocity \or to \{keepe}{helpe} {illeg}/ hinder another body f{illeg}|r|o persevering in its velocity/ to ye force of c . For let there be 2 other bodys a & d equivelox to th{illeg}|e|m soe yt a meeting b , & d meeting c they would eqaully hinder one others progression yn is a=b , & c=d (ax 105) & a=bd=c yn force wch can stop a (= to ye force of b ) to ye force wch can stop d (= to ye force of c ). |(vide ax: 102.|

[93] 108 Tis knowne by ye light of nature yt equall forces shall effect an {illeg}|e|quall ch{illeg}|a|nge in equall bodys. Therefore if ye forces g, h, k, m, be equall, & ye bodys a, b, equall {illeg}|&| rest, then let a bee moved by ye force g ; & b by h , a & b shall be equiv{illeg}|e|lox: Also (since tis noe greater change for a to acquire another part of motion now it hath one yn for it to acquire y{illeg}|t| one when it {illeg} had none) if a bee againe moved forward by ye force k , its velocity shall be double to ye velocity of b , & if it bee againe moved forward by ye force m its velocity shall be triple to yt of b . &c. Whence as ye force moving a is to ye force moving b soe is |ye| velocity acquired in a to ye velocity acquired in b \{{illeg}|b|y that force}/

109 By ye same reason if \a=b &/ ye velocity of a be t{illeg}|r|i{illeg}|p|le to ye velocity of b , y{illeg}|t| force {illeg} wch can deprive a of its velocity. must be \wch is/ 3ple to ye force wch can deprive b of its velocity. Or in gener{illeg}|a|ll {\2/} {illeg} \so/ \is/ ye \lost/ velocity of a {illeg} to ye \lost/ velocity of b soe is \As/ ye force wch one deprives a of \some or all of/ its velocity, to ye force wch can deprives b of \some or all of/ its velocity & so is ye force \{That}/ wch can deprive a of

{illeg} ye force {illeg}|w|th{illeg} is {illeg}\or preserve it selfe in its {illeg}/ is to ye force wth w{illeg}|c|h b is moved {illeg} ye velocity of a {illeg} velocity of b otherwise it {illeg} not be {illeg} ye {illeg} Ax 5t

The force wch ye body a hath to preserve it selfe in its state shall bee equall to ye force wc{h}{illeg}{illeg} yt state; not greater for ye effect cannot exceede the {illeg} for {illeg}{illeg}{illeg} ye {illeg} wch was not in ye cause \nor lesse for/ ye cause only {illeg}to its effect{illeg}no reason why its {illeg}{illeg}

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[94] \112/ A body is saide to have more or lesse motion as {illeg} it is moved wth more or lesse force, yt is as ther{illeg}|e| is more or lesse force required to generate or destroy its \whole/ motion.

[95] 11{illeg}|3| If a body a move through ye space ab \=r / in ye time c . & {illeg}|t|he body {illeg}|f | through gf \=v / in the time h then, time c time h line ab \=r/h×abc= fk ak . & ye body a would move through ye space ak in ye same tim h in wch ye body f moves through ye space fg . Therefore ye velocity of a is to ye velocity of f as ye line ak=h×abc line fg {illeg} h×abc×fg {illeg} \(def 2)/ Then I ad {sic} ye body r to f soe yt r+f=a . since f & r are equivelox, \(ax: 107)/ as ff+r=am= force or motion of f , to {illeg} amf= force of f+r. againe sine {sic} a=f+r , & they move \(ax: 111)/ as ye velocity of a ; to ye velocity of f+rh×abc×fg n= ye force or motion of a , to {illeg} the n×c×fgh×ab=a×mf= to ye force of f+r . Soe yt, n×f×c×fg=m×a×h×ab . So{illeg}|e| yt haveing any 7 of t{illeg}|h|ese ye 8th m{illeg}|a|y bee found. {illeg} but suppose ye bodys moved in equall ti{illeg}|m|es yt is if c=h , yn ye rest of ye termes may bee found by, m×a×ab=n×f×fg . &c. yt i{illeg}|s| as f×fg is to a×ab soe is ye motion m of ye body f to ye motion n of ye body a . &c.

[96] 110. If ye body {sic} ( a & b ) bee equall & ye celerity of a ti|r|iple to yt of b , yn if ye force {illeg} {illeg}| d | can deprive {illeg}| b | of its motion, ye force 3d may can deprive a of its motion. But if there bee lesse force \ 3 d p / it cannot deprive a of its motion for soe ye pte 3 d p would be = to ye whole 3d ; if there be more force 3d +p it will doe more yn deprive the body a of its motion (i.e. move it ye contrary way) otherwise ye pte 3d would be equall to ye wh{illeg}|o|le 3d+p . |Therefore ye |If ye body a bee equall to ye body b .
force which can deprive a of its motion must bee 3ple to ye force wch can deprive b of its motion & consequently ({illeg}|d|ef 106) ye for{illeg}|c|e wherwth a is moved is 3ple to ye force wherewth b is moved

111 By ye same reason as ye celerity of ye body a=b is to ye celerity of b so is ye for{illeg}|c|e wherewth a moveth to ye force wherewth b moveth.

[97] 114 There is required soe much & noe more force to reduce a body to rest y{illeg}|n| there is to move it: et e contra. And

115 Soe much force a is required to generate any quantity of motion in a body so{illeg} much is required to destroy it, & e contra. For d \in/ loose|i|{illeg}|n| {sic} or to get|ting| ye same {illeg}|q|uanty {sic} of motion a body suffers ye same quantity of mutacon in its state, & in ye same body equall forces will effect a equall change

[98] 116 If ye bodys a=3b , & a & b {illeg} are moved wth ye same force d yn ye celerity of b {illeg} is tri{illeg}|p|le to ye celerity of {illeg} a . for if a be moved by suppose badadb & let a bee moved by adb & b by {illeg} for if a=3b be moved by 3d , & b be {illeg} moved by d , ( a & b ) shall {illeg} }{illeg} \moved by/{ for 3b moved by 3d is equivelox to b moved by d , but since 3b=a , therfore a moved {illeg}|b|y 3d is equivelox to b moved by d . And (ax 108) as ye ce{illeg}|l|erity of a moved by {illeg}| d | is to ye celerity of a moved by 3d , soe is 1 to 3 , soe is ye celerity of a moved by d to ye celerity of b moved by d .

By ye \same/ reason, Any bodys f & g being moved by ye same force as f is to g , soe is ye celerity of g to ye celerity of f acquired by yt force. tis axiome ye 4th And (by ax: 113) ye bodys will have equall motion.

[99] 118 If ye body p , be moved by ye forc{illeg}|e| q , & r by ye force s , \to find {illeg} v ye celerity of p & w yt of r ,/ I add t to p , soe yt p+t=r , & yt p , & p+t are moved wth equall force, yn p+t=rpvpvr ye celerity of p+t, (ax 117) alsoe, (ax 108) sqwqws=pvr. Or qrw=pvs . that is ye celerity of p is to ye celerity of r as qr is to ps. And by ax 113 ye motion of p is to ye motion of r as ye force of p to ye force of r . And by ye same reason if ye motion of p & r bee hindered by ye force q & s , {illeg}ye motion lost in p is to ye motion lost in r , as q is to s . or if ye motion of p be increased by ye force q , by|u|t ye motion of r hindered by ye force s ; the {illeg} as q , to s ∷ so is ye increase of motion in p , to ye decrease of it in r (ax 111

[100] 1{1}9 \121/ If 2 bodys p & r p {illeg}{nest} ye one ye other, ye resistance {illeg}|i|n both is ye same for soe much as p presseth upon r so much r presseth on p . And therefore they must both suffer an equall mutacon in the {illeg} motion.

11{illeg}|9| {illeg} If r presseth p towards w then p presseth r towards w . {illeg} wthout {illeg}

120 A body must move yt way wch it is pressed.

122 Therefore if ye body p comes from c & ye body r from d soe much as { p {illeg} } motion is changed towards w soe much ye motion of {illeg} changed {illeg}{illeg}

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[101] \27/ If two bodys {illeg}| b | & c move from o their center of gravity they shall have equal motion For suppose b moved into ye place d ; then putting, cbdob×doc=oe (ax 25) ye body c must be the{illeg}|n| moved into ye place {illeg} e . Alsoe cbbob×boc=oc . (ax 25) therefore ec=b×bob×doc=b×bdc . that is {illeg} c×ec=b×bd . But (ax 11326 or) c×ecbd×b ye motion of c , to ye motion of d , & therefore c , & d have equall motion towards o

If ye body b move through ye places d , f , r , & ye body c through ye places {illeg}| e | g h & their center of o , p , q , r ye line opqr shall be a {illeg}|s|treight line For nameing ye lines bc=g . cr=h . br= k . bd=x. dexce . Then Then ce=exd . kgxgxk= cv & supposeing bcdvps . Therefore {illeg} ve=exd=gxk & then kgkxgkgxk=dv . b+ccdepedvpsvees also khxhxk=cv, & exdhxk=ve therefore ps=cgkcgxbk+ck. & es=cekxcdhxbdk+cdk. crce=er=hexd . er+es=sr=cekxcdhxbdk+dck+dhexd . Or rs=bdhk+cdhkbkexcdhxbdk+dck. {illeg} b+ccbccogcgb+c=co . crcohcgb+cbh+chcgrsspbdhk+cdhkbkex dhcxcdgkcdgx . Whence cdgkbh.cdgxbh+cdgkch.cdgxch.=bdhkcg.+cdhkcg.+kexbcgdhcxcg.

[102] 28. To fin If two bodys b & c mo{illeg}|v| {illeg} through in ye lines br & cr . The body c moveing through ye space cg in ye ti{illeg}|m|e vs , & though g h in ye time nv , & through kr in ye time nr . & ye velocity of ye body b is to ye velocity of c as d , t{illeg}|o| e , & a{illeg}|s| ye line cg to ye line be , or as ck to br , then {illeg} when ye body c is in ye place g , b will bee in e , & when c is in k , b will be in r . to find ye line wch the center of their motion describes, viz dfo . {illeg}|T|hen nameing ye quantitys br=a, cr=f. bc=g. {illeg} edadae=ck . kr=efdae . If o be ye center of gravity motion of ye bodys at k {illeg}|&| r ; yn, b+cbefdaebefabdeb+ec=or . And ye line df must passe through o . againe making gk=v . yn devevd=er . & if bcfiem , yn agevd=ergevad=em . also since f is ye &, afevd=erfevad=mr gr=gk+kr=v+efade . gm=grmr=ev+efadefevad=adev+adefaaddfeevade. since f is ye center of motion in ye bodys at g & e tis, b+cc {illeg} gefg . {illeg} b+ccegfgem=gevadcgevabd+acd=figm=&cgi=cadev+cadefcaaddcfeevbade+cade. gr=gk+kr=ev+efade. go=gror=ev+efade+abdbefeb+ec=bev+cev+cefcadeb+ec. gogi=io=adbev+cfeevbade+cade=abdv+cefvabd+acd. co=cror=fec+abdeb+ec. b+ccgcgb+c=cd . [103] {illeg}|N|ow if the lines oiifoccd . Then ye line od must be a streight line. but oiifadb+cfecgeoccdfec+abdecgfec+abdecg . therefore ye line do is a streight line, wth wch may bee found by ye two points d & o . |The demonstracon is ye same if ye body b moved from a to b |

Figure 29 If two bodys q & c be moved in divers plines {sic}, then find ye shortest {illeg} line pr wch can bee drawne frome one line cr {illeg}|to| ye other line qp in wch those bodys are moved, & yt line pr shall bee perpendicular to both ye lines cr & qp , viz qpr= rps=prc=recto. then draw qb equall & pr & draw br=qp . Then shall ye plaine qbrp be perpendicular to ye plaine bcr . Suppose also ye body c moves over ye space cggkkrin the timevwwttr {illeg}|&| yt ye body q moves over ye space qa in ye time vw , & ap in ye time wt . Also suppose another body b=q & equivelox to { q } yt is to move over ye space be=qa in ye time vw {illeg}

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Soe yt when c is in g or k {illeg}|,| b will bee in e or r & q in a or p . {illeg} Then \Then drawing {the} streight lines qc , ag , bk / if b+ccbccdegfgrkok ;|,| the points d , f , & o , shall be ye centers of gravity motion of ye bodys b & c , when they are in ye places b & c , e & g , r & k . & (prop 28) therefore ye line ( dfo {illeg}|)| in a streight line. Likewise if it bee {illeg} q+ccqclcagmgpknk, then ye points l , m , n are centers of motion to ye bodys ( q & c ) being in ye places q & c , a & g , p & k . Then drawing ye lines ld , mf , no , f{illeg} ye (twixt ye neighbouring centers of motion) since b+cc {illeg} q+ccbccdq {bc }. therefore qbc=ldc & by ye same reason gfm=gea {illeg}|&| krp=kon. Wherefore |all the lines qb , ae , pr , ld , ml , no are parallell t{illeg}|o| one another. And| b+0cbcdcqbldegfgea=qbmfkrkopr=bqno , soe yt ld=mf=no . & since these line line {sic} ld , mf , no , are parallell, equall, in ye same plaine ldon , & stand upon ye same streigh{illeg}|t| line do , their other ends \(the ce{illeg}|n|ters of motion of c & q )/ l , m , n , must bee in ye same streight line lmn , wch line ye line \ lmn / in wch their other ends l , m , n , are are terminated (i.e. in wch /are\ all ye centers of gravity motion of ye bodys ( c & q )) {illeg} must bee a streight line.

The demonstracon is the same if q moved from p to q .

[104] 30. Suppose ye bodys b , & c moved towards, r ; so yn|t| when b is in bep then c is in cgk. & theire centers of motion describe ye line dq . Then ye motion of the|i|re centers of motion shall be uniforme. For prpwerey \if pwnteyfsbc / prerpweyntfsnqfq . yt is prep=erprnqfn=fqnq & therfor since ye motion of ye body in epr is uniforme, ye motion of theire centers of motion in ye line fnq , must b{illeg}|ee| uniforme, yt is have allway alike {illeg}|v|elocity |The demonstracon is ye same in all other cases.|

[105] 28 \& 30/ Supposeing ye thing{illeg}|s| suppose {sic} in ye 28th prot{illeg}|p| {sic} by {illeg}|sc|hem {sic} 38th it may be thus done. pr{illeg} er{illeg} erbreybcfsdc. Also epebcggk. cyyw {illeg} & cgckcycwgy=cycghw=cwckgsktsytwbebp csctdcfsdcnt &c. Makeing fsdcnt . & mfqnet , yn is mf=cs & qn=ct . & fs=mc , & nt=qc=is . Then bebpcycw \cg/ck (so is ye velocity of b to ye velocity of c ) gy =cycghw=cwcksytw (for c+bbegef gysykpnpkwtw .) {illeg} mf=cysy {illeg} \ qn / =cwtw {illeg}. Againe brerbcey {illeg} dcfs \=mc,/ (for b+ccbcdc fg egfgeyfs) {illeg} \{illeg}/ Also Whence be=brerbrdm=dcmcdc . Also brprbcpwdcnt=qc , whence Therefore bebp=brprdmdq=dcqc . That is bebpdmdqmfqn. & consequently ye points d f n are in one streight line. & since ye motion of b is uniforme &, bebpdmdqdffn, the motion of ye center d is uniforme.

[106]28 & 30th. The bd|od|ys \( b & c )/ being in b & c , e & g , r & k , {illeg}|i|n ye same times, & d n being described by their centers of motion. Also making defsey . {illeg}|&| mfcn. Then bebrcycrcgck (for ye motions of b & c are u{illeg}|n|ifor) gy =cycgkr=crckgskn (for b+ccgegfgygskrkn) {illeg} mf=cs =cg+gscn=ck+kn . Againe brerbceydcfs=mc (for b+ccgegfeyfsbcdc (prop 25)). Therefore bebrdmdcmfcn & consequently ye points d f n are in one streight line. als{illeg}|o| since bebrdfdn ye cente{illeg}|r| of motions motion {sic} {illeg}|m|ust bee uniforme.

[107] 31 If two bodys \( b & c )/ meete & reflect one another \at/ their center of motion shall bee in ye same line \ kp / after reflection in wch it was before it. For ye motion of {illeg}| b | towards d {illeg} \ye {center} of their motion