Valuation of another three two-real pieces and new estimate of the total amount to be produced by the reminting as 4,189,000 two-real pieces

Author: Isaac Newton

Source: MINT 19/2/209, National Archives, Kew, Richmond, Surrey, UK

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- Revision History
  - 1 January 2001
    - Catalogue information compiled by Rob Iliffe, Peter Spargo & John Young
  - 29 September 2011
    - Catalogue exported to teiHeader by Michael Hawkins
  - 25 August 2016
    - Transcribed by Will Scott
  - 23 September 2016
    - Will Scott finished transcription
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Related Texts
- This document is a reply to:
  Copy of note accompanying three pieces of Spanish money [T 27/20.14]

<209r>

The three spanish pieces of two Ryals which were sent to me by your Lordships order {to} be examined are very unequally coined. One of them weighd 3^{dw^t} 6 $\frac{1}{4}$ grains & is 4 $\frac{1}{2}$ ^{dw^t} worse then our standard. Another weighd 3^{dw^t} 13^grains & is standard scant. A third weighs 3 ^{dw^t} 10 $\frac{2}{3}$ ^gr & is 4 $\frac{1}{2}$ ^{dw^t} worse. These three & that which by your lordships order I caused to be assayed some weeks agoe & which was 3 $\frac{1}{2}$ ^{dw^t} worse then standard, & weighed 3^dwt 6^gr, are one with another at a medium in weight 3^{dw^t} 9^gr & in Assay 3 $\frac{3}{16}$ ^{dw^t} worse than standard & in value 10^d $\frac{5}{16}$ .+^[1] And if a Mexico piece of eight be worth 4^s 6^d then 800000 pieces of eight will make about 4189000 two Ryall pieces of K. Charles.

5 Carolu's & $\frac{2}{9}$ of a Carolus equal a Mexico piece of 8. 47 Caroluses equal 9 pieces of 8 & 8000000 pieces of 8 should make 4180000 Carolusses.

If a piece of 8 be recconed at 54^d, 800000 pieces of 8 will make 4189100 Carolusses. But $\frac{1}{3}$ per 100 abated brings it to 4175000

^[1] And a Mexico piece of eight worth 4-6 is almost 5 per cent better in value then 5 of these two Ryal pieces. And 800000 such Mexico pieces of 8 will make 4189000 such two Ryal pieces